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A school newspaper article claims that $60\%$ of the students at a large high school did all their assigned homework last week. Some skeptical AP Statistics students want to investigate whether this claim is true, so they choose an SRS of $100$ students from the school to interview.

No, because the dot plot contains the results of $250$ simple random samples of size $100$, while the sampling distribution should contain the results of all possible samples of size $100$.

A school newspaper article claims that $60\%$ of the students at a large high school did all their assigned homework last week. Some skeptical AP Statistics students want to investigate whether this claim is true, so they choose an SRS of $100$ students from the school to interview

Shape: Roughly unimodal and symmetric, because the highest peak is roughly in the middle of the histogram.

Center: The highest peak in the histogram is at about $0.60$, thus the distribution is centered at $0.60$.

Spread: The data values appear to vary from $0.47$ to $0.74$.

Outliers are dots that are separated from the other dots in the dotplot by a gap.

Then we note that there are $4$ outliers (two on each side of the dotplot): $0.47,0.48,0.73,0.74$.

A school newspaper article claims that $60\%$of the students at a large high school did all their assigned homework last week. Some skeptical AP Statistics students want to investigate whether this claim is true, so they choose an SRS of $100$ students from the school to interview.

Claim: $p=0.60$or $60\%$of students did their homework last week.

The sample proportion is the number of successes divided by the sample size:

localid="1650027069959" $$\begin{gathered} \hat{p}=\frac{x}{n} \\ =\frac{45}{100} \\ =0.45 \end{gathered}$$

In the dot plot we note that there are no dots above $0.45$nor to its left, this means that it is very unusual to obtain a sample proportion of $0.45$if the population proportion is $0.60$.

Then it appears that the claim is false.