/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q 57. In government data, a household ... [FREE SOLUTION] | 91影视

91影视

In government data, a household consists of all occupants of a dwelling unit. Choose an American household at random and count the number of

people it contains. Here is the assignment of probabilities for your outcome:

The probability of finding 3people in a household is the same as the probability of finding 4people. These probabilities are marked ??? in the table of the distribution. The probability that a household contains 3 people must be

(a) 0.68(b) 0.32(c) 0.16(d) 0.08(e) between 0 and1, and we can say no more.

Short Answer

Expert verified

The correct option is (c) 0.16

Step by step solution

01

Step 1. Given Information

The probability distribution for determining the number of people in a household is given. The chances of discovering 3 persons in a household are the same as finding 4people.

02

Step 2. Concept Used

An event is a subset of an experiment's total number of outcomes. The ratio of the number of elements in an event to the number of total outcomes is the probability of that occurrence and the use of the complimentary rule.

03

Step 3. Calculation 

The probabilities of 3 and 4 are the same.

The following are the probability distribution conditions:

1)The probabilities should be 0p1

2)The sum of all probability should equal one.

With the second condition,0.25+0.32+x+x+0.07+0.03+0.01=12x+0.68=12x=0.32x=0.16

As a result, the likelihood of a 3-person household is 0.16

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Playing cards Shuffle a standard deck of playing cards and deal one card. Define events J: getting a jack, and R: getting a red card.

(a) Construct a two-way table that describes the sample space in terms of events J and R.

(b) Find P(J) and P(R).

(c) Describe the event 鈥J and R鈥 in words. Then find P(JandR)

(d) Explain why P(JorR)P(J)+P(R) Then use the general addition rule to compute P(JorR).

Stoplight On her drive to work every day, Ilana passes through an intersection with a traffic light. The light has a probability of 1/3 of being green when she gets to the intersection. Explain how you would use each chance device to simulate whether the light is red or green on a given day.

(a) A six-sided die

(b) Table D of random digits

(c) A standard deck of playing cards

Random assignment Researchers recruited 20惫辞濒耻苍迟别别谤蝉鈥8men and 12women鈥攖o take part in an experiment. They randomly assigned the subjects

into two groups of 10people each. To their surprise, 6of the 8men were randomly assigned to the same treatment. Should they be surprised? Design and carry out a simulation to estimate the probability that the random assignment puts 6or more men in the same group. Follow the four-step

process.

You read in a book about bridge that the probability that each of the four players is dealt exactly one ace is about 0.11 This means that (a) in every100 bridge deals, each player has one ace exactly 11 times.

(b) in one million bridge deals, the number of deals on which each player has one ace will be exactly 110,000

(c) in a very large number of bridge deals, the percent of deals on which each player has one ace will be very close to 11%

(d) in a very large number of bridge deals, the average number of aces in a hand will be very close to 0.11

(e) None of these

At the gym Suppose that 10%of adults belong to health clubs, and 40% of these health club members go to the club at least twice a week. What percent of all adults go to a health club at least twice a week? Write the information given in terms of probabilities, and use the general multiplication rule.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.