/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q 48. Preparing for the GMAT A company... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 5: Q 48. (page 310)

Preparing for the GMAT A company that offers courses to prepare students for the Graduate Management The admission Test (GMAT) has the following information about its customers: 20% are currently undergraduate students in business; 15% are undergraduate students in other fields of study; 60% are

college graduates who are currently employed, and 5% are college graduates who are not employed. Choose a customer at random.

(a) What鈥檚 the probability that the customer is currently an undergraduate? Which rule of probability did you use to find the answer?

(b) What鈥檚 the probability that the customer is not an undergraduate business student? Which rule of probability did you use to find the answer?

Short Answer

Expert verified

Part (a) The likelihood is 0.15

Part (b) The likelihood is 0.80

Step by step solution

01

Part (a)  Step 1. Given Information

The company's tabular data shows that 20% of its employees are currently undergraduate students studying business; 15% are undergraduate students studying other fields of study; 60%are college graduates who are currently employed; and 5% are college graduates who are unemployed.

02

Part (a) Step 2. Concept Used

An event is a subset of an experiment's total number of outcomes. The ratio of the number of elements in an event to the number of total outcomes is the probability of that occurrence and the use of the complimentary rule.

03

Part (a)  Step 3. Calculation

P(undergraduateinbusiness) = 0.20

P(undergraduateinothersubjects) =0.15

P(employedgraduates) = 0.60

P(unemployedgraduates) = 0.05

Formula

P(AorB)=P(A)+P(B)

P(Undergraduateinbusinessorotherfields)=P(Undergraduateinbusiness)+P(Undergraduateinotherfields)=0.20+0.15=0.35(usingformula)

04

Part (b) Step 1. Calculation

P(undergraduateinbusiness) = 0.20

P(undergraduateinothersubjects) = 0.15

P(employedgraduates) = 0.60

P(unemployedgraduates) = 0.05

Formula

PAc=1-PA

Using complimentary formulas.

P(Notundergraduatebusiness)=1-P(Undergraduatebusiness)=1-0.20=0.80

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Get rich Refer to Exercise 63.

(a) Find P(鈥渁 good chance鈥� | female).

(b) Find P(鈥渁 good chance鈥�).

(c) Use your answers to (a) and (b) to determine whether the events 鈥渁 good chance鈥� and 鈥渇emale鈥� are

independent. Explain your reasoning.

Myspace versus Facebook A recent survey suggests that 85% of college students have posted a profile on Facebook, 54%use Myspace regularly, and 42% do both. Suppose we select a college student at random.

(a) Assuming that there are 20 million college students, make a two-way table for this chance process.

(b) Construct a Venn diagram to represent this setting.

(c) Consider the event that the randomly selected college student has posted a profile on at least one of these two sites. Write this event in symbolic form

using the two events of interest that you chose in (b).

(d) Find the probability of the event described in (c).

Explain your method.

Education among young adults Chooses a young adult (aged 25 to 29) at random. The probability is 0.13 that the person chosen did not complete high school, 0.29 that the person has a high school diploma but no further education, and 0.30 that the person has at least a bachelor鈥檚 degree.

(a) What must be the probability that a randomly chosen young adult has some education beyond high school but does not have a bachelor鈥檚 degree? Why?

(b) What is the probability that a randomly chosen young adult has at least a high school education? Which rule of probability did you use to find the

answer?

Lactose intolerance Lactose intolerance causes difficulty

in digesting dairy products that contain lactose (milk sugar). It is particularly common among people of African and Asian ancestry. In the United States

(ignoring other groups and people who consider themselves to belong to more than one race), 82%of the population is white, 14% is black, and 4% is

Asian. Moreover,15% of whites, 70% of blacks, and 90% of Asians are lactose intolerant.20

(a) What percent of the entire population is lactose intolerant?

(b) What percent of people who are lactose intolerant are Asian?

Twenty of a sample of 275 students say they are vegetarians. Of the vegetarians, 9eat both fish and eggs, 3 eat eggs but not fish, and 8 eat neither. Choose one of the vegetarians at random. What is the probability

that the chosen student eats neither fish nor eggs?

(a) 8/275=0.03 (c) 8/20=0.4 (e) 1

(b) 20/275=0.07 (d)

See all solutions

Recommended explanations on Math Textbooks

Applied Mathematics

Read Explanation

Probability and Statistics

Read Explanation

Geometry

Read Explanation

Theoretical and Mathematical Physics

Read Explanation

Logic and Functions

Read Explanation

Statistics

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.