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Refer to Exercise 28. Do the data provide convincing evidence of a difference in the distributions of opinions about how high schools are doing among black, Hispanic, and white parents?

(a) State appropriate null and alternative hypotheses for a significance test to help answer this question.

(b) Calculate the expected counts. Show your work.

(c) Calculate the chi-square statistic. Show your work.

Short Answer

Expert verified

(a) H0: There is no association between the variables

Ha: There is an association between the variables

(b) The expected counts is

(c) The value of2=22.4261.

Step by step solution

01

Part (a) Step 1: Given information

The given data is

02

Part (a) Step 2: Explanation

The null hypothesis states that there is no association between the variables: H0: There is no association between the variables

The alternative hypothesis states that there is an association between the variables:

Ha: There is an association between the variables

03

Part (b) Step 1: Given information

The given data is

04

Part (b) Step 2: Explanation

The given data is

n1=202

n2=202

localid="1650643605859" n=202+202+201=605

The expected count is the row total multiplied by the sample sizenidivided by the total sample size n :

05

Part (c) Step 1: Given information

The given data is

06

Part (c) : Step 2: Explanation

Observed counts

Expected counts

The chi-square statistic is the sum of squared deviations (between observed and expected counts) divided by the expected count:

2=(12-22.7041)222.7041+(69-68.4463)268.4463+(75-65.4413)265.4413+(24-24.0397)224.0397+(22-21.3686)221.3686+(34-22.7041)222.7041+(55-68.4463)268.4463+(61-65.4413)265.4413+(24-24.0397)224.0397+(28-21.3686)221.3686+(22-22.5917)222.5917+(81-68.1074)268.1074+(60-65.1174)265.1174+(24-23.9207)223.9207+(14-21.2628)221.2628=22.4261

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