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The two-sample t statistic for the road rage study (male mean minus female mean) is t=3.18. The P-value for testing the hypotheses from the previous exercise satisfies

(a) 0.001<P<0.005.

(b) 0.0005<P<0.001.

(c) 0.001<P<0.002.

(d) 0.002<P<0.01.

(e) P>0.01.

Short Answer

Expert verified

The correct option is (b).

Step by step solution

01

Given Information

Number of men and women are 596and 523respectively.

Test statistic (t)=3.18.

02

Explanation

The degree of freedom can be computed as:

df=minn1,n2

=min(596,523)

=523

Now, the P-value is:

0.0005<P<0.001

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