Chapter 9: Problem 13
Attitudes In the study of older students’ attitudes from Exercise 3, the sample mean SSHA score was 125.7 and the sample standard deviation was 29.8. A significance test yields a P-value of 0.0101. (a) Interpret the P-value in context. (b) What conclusion would you make if \(\alpha=0.05\) ? If \(\alpha=0.01\) Justify your answer.
Short Answer
Step by step solution
Understand the P-value
Setting Alpha Levels for Decision-Making
Compare P-value with Alpha = 0.05
Compare P-value with Alpha = 0.01
Conclusion Based on Each Alpha Level
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Statistical Significance
For example, in our exercise, the P-value was 0.0101, which we compared against certain alpha levels like 0.05 and 0.01. The P-value indicated whether the sample mean of 125.7 was significant enough to reject the null hypothesis.
- When a result is statistically significant, it does not mean it's important or practical, just that it is unlikely to have occurred under the null hypothesis.
- How "unlikely" is determined by our chosen threshold, the alpha level.
Null Hypothesis
- It's important because it sets a baseline for comparison.
- The test aims to reject \( H_0 \), which implies evidence for an alternative hypothesis, \( H_a \).
- A non-rejection of \( H_0 \) doesn't prove it true; it simply means we lack strong evidence against it.
Alpha Level
In our exercise, two alpha levels were used to compare against the P-value of 0.0101:
- \(\alpha = 0.05\): The result was statistically significant, prompting a rejection of the null hypothesis.
- \(\alpha = 0.01\): The result was not statistically significant, indicating insufficient evidence to reject the null hypothesis.
- A smaller alpha level (e.g., 0.01) means less risk of a Type I error but requires stronger evidence to reject \( H_0 \).
- A larger alpha level (e.g., 0.05) allows more room for Type I error but can be too lenient for certain studies.
Sample Mean
- Calculated by summing all data points and dividing by the number of points: \( \bar{x} = \frac{\sum_{i=1}^{n}x_i}{n} \).
- It reflects the central tendency of the sample data.
- If different from the hypothesized population mean, it suggests a possible effect.