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Filling cola bottles Bottles of a popular cola are supposed to contain 300 milliliters (ml) of cola. There is some variation from bottle to bottle because the filling machinery is not perfectly precise. From experience, the distribution of the contents is approximately Normal. An inspector measures the contents of six randomly selected bottles from a single day鈥檚 production. The results are 299.4\(\quad 297.7 \quad 301.0 \quad 298.9 \quad 300.2 \quad 297.0\) Do these data provide convincing evidence that the mean amount of cola in all the bottles filled that day differs from the target value of 300 \(\mathrm{ml}\) ? Carry out an appropriate test to support your answer.

Short Answer

Expert verified
The data does not provide convincing evidence that the mean amount of cola differs from 300 ml.

Step by step solution

01

Determine the Null and Alternative Hypotheses

The null hypothesis (\(H_0\)) is that the mean amount of cola in the bottles is 300 ml, \( \mu = 300 \). The alternative hypothesis (\(H_a\)) is that the mean differs from 300 ml, \( \mu eq 300 \).
02

Calculate Sample Statistics

Calculate the sample mean (\( \bar{x} \)) and the sample standard deviation (\( s \)) for the given data: 299.4, 297.7, 301.0, 298.9, 300.2, and 297.0. \( \bar{x} = \frac{299.4 + 297.7 + 301.0 + 298.9 + 300.2 + 297.0}{6} \approx 299.03 \) ml. Calculate \( s \) by finding the square root of the sample variance.
03

Perform the t-Test

Use the formula for the t-test statistic: \( t = \frac{\bar{x} - \mu}{(s / \sqrt{n})} \). Here, \( \bar{x} = 299.03 \) ml, \( \mu = 300 \) ml, \( n = 6 \), and \( s \) is the standard deviation calculated in Step 2. Compute the t-value to evaluate the significance.
04

Determine the Degrees of Freedom and Critical Value

The degrees of freedom (df) for this test is \( n - 1 = 5 \). Use a t-distribution table to find the critical t-value for a given significance level (e.g., \( \alpha = 0.05 \)) for a two-tailed test.
05

Make a Decision about the Hypotheses

Compare the calculated t-value from Step 3 with the critical t-value from Step 4. If the absolute value of the t-value is greater than the critical value, reject the null hypothesis; otherwise, do not reject the null hypothesis.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Null Hypothesis
In the world of statistical inference, the null hypothesis is a foundational concept. Think of the null hypothesis as a baseline or starting point for evaluation. It is a statement that suggests no effect or no difference exists. For the cola bottle problem, the null hypothesis ( H_0 ) claims that the mean amount of cola in the bottles is exactly 300 ml. This is the claim we are testing against. Our job is to see if there is enough evidence in the sample data to contradict this claim. By assuming initially that the null hypothesis is true, we establish a position to statistically test whether this assumption holds up against the collected data by performing hypothesis tests.
Alternative Hypothesis
While the null hypothesis assumes no change or difference, the alternative hypothesis represents what we might believe is true if the evidence turns out to be convincing. In our case, the alternative hypothesis ( H_a ) suggests that the mean amount of cola in the bottles is not 300 ml. It's important to note that the alternative hypothesis is essentially the opposite of the null hypothesis. If statistical tests provide enough evidence against the null hypothesis, we then accept the alternative hypothesis. This switch is based on the significance of the data, determined by comparing test statistics to critical values. Once tested, if the collected data shows a considerable deviation from 300 ml, the alternative hypothesis gains strength.
t-Test
The t-test is a statistical method used to determine if there is a significant difference between the means or to test hypotheses about means. In this exercise, the one-sample t-test is apt because we wish to check if the mean amount of cola differs from the claimed 300 ml. For our data, after computing the sample mean and standard deviation, we calculate the t-statistic using the formula: \[ t = \frac{\bar{x} - \mu}{(s / \sqrt{n})} \] where \(\bar{x}\) is the sample mean, \(\mu\) is the population mean under the null hypothesis, \(s\) is the sample standard deviation, and \(n\) is the sample size. The resulting t-value helps us compare our sample against the theoretical expectation. This comparison determines whether any observed variance is due to random chance or suggests a different underlying mean.
Normal Distribution
Normal distribution often forms the basis of many statistical tests, including the t-test, due to its properties. A normal distribution is a continuous probability distribution characterized by a symmetric bell-shaped curve. The mean, median, and mode of a normal distribution are all equal, and it is defined by the parameters of mean and standard deviation. In the context of the cola bottle exercise, assuming a normal distribution for the fill levels allows us to make inferences about the population based on sample data. This is because many natural phenomena have approximately normal distribution, making it a reasonable assumption for machinery filling bottles. The use of the t-test, which relies on the t-distribution鈥攁 close cousin of the normal distribution鈥攊s justified if the sample data is roughly normal. This helps us confidently draw conclusions about whether the mean cola amount deviates significantly from the desired 300 ml.

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Most popular questions from this chapter

Is this what P means? When asked to explain the meaning of the P-value in Exercise 13, a student says, 鈥淭his means there is only probability 0.01 that the null hypothesis is true.鈥 Explain clearly why the student鈥檚 explanation is wrong.

Reporting cheating What proportion of students are willing to report cheating by other students? A student project put this question to an SRS of 172 undergraduates at a large university: 鈥淵ou witness two students cheating on a quiz. Do you go to the professor?鈥 The Minitab output below shows the results of a significance test and a 95% confidence interval based on the survey data. (a) Define the parameter of interest. (b) Check that the conditions for performing the significance test are met in this case. (c) Interpret the P-value in context. (d) Do these data give convincing evidence that the actual population proportion differs from 0.15? Justify your answer with appropriate evidence.

Study more! The significance test in Exercise 76 yields a P-value of 0.0622. (a) Describe a Type I and a Type II error in this setting. Which type of error could you have made in Exercise 76? Why? (b) Which of the following changes would give the test a higher power to detect \(\mu=120\) minutes: using \(\alpha=0.01\) or \(\alpha=0.10 ?\) Explain.

Women in math (5.3) Of the 16,701 degrees in mathematics given by U.S. colleges and universities in a recent year, 73% were bachelor鈥檚 degrees, 21% were master鈥檚 degrees, and the rest were doctorates. Moreover, women earned 48% of the bachelor鈥檚 degrees, 42% of the master鈥檚 degrees, and 29% of the doctorates. (a) How many of the mathematics degrees given in this year were earned by women? Justify your answer. (b) Are the events 鈥渄egree earned by a woman鈥 and 鈥渄egree was a master鈥檚 degree鈥 independent? Justify your answer using appropriate probabilities. (c) If you choose 2 of the 16,701 mathematics degrees at random, what is the probability that at least 1 of the 2 degrees was earned by a woman? Show your work.

An understanding of cockroach biology may lead to an effective control strategy for these annoying insects. Researchers studying the absorption of sugar by insects feed a random sample of cockroaches a diet containing measured amounts of sugar. After 10 hours, the cockroaches are killed and the concentration of the sugar in various body parts is determined by a chemical analysis. The paper that reports the research states that a 95\(\%\) confidence interval for the mean amount (in milligrams) of sugar in the hindguts of cockroaches is \(4.2 \pm 2.3 .29\) Cockroaches Does this paper give convincing evidence that the mean amount of sugar in the hind- guts under these conditions is not equal to 7 mg? Justify your answer.

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