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Cranky mower To start her old mower, Rita has to pull a cord and hope for some luck. On any particular pull, the mower has a 20\(\%\) chance of starting. (a) Find the probability that it takes her exactly 3 pulls to start the mower. Show your work. (b) Find the probability that it takes her more than 10 pulls to start the mower. Show your work.

Short Answer

Expert verified
(a) 12.8% chance of starting on 3rd pull. (b) 10.74% chance of more than 10 pulls.

Step by step solution

01

Understanding the Problem for Part (a)

The problem asks for the probability that the mower starts on the third pull, with previous two pulls not being successful. This scenario follows a geometric distribution because we are counting the number of trials until the first success.
02

Define the Variables for Part (a)

Let the probability of success (the mower starting) on each pull be \( p = 0.2 \). Then, the probability of failure (the mower not starting) is \( q = 1 - p = 0.8 \).
03

Use the Geometric Probability Formula for Part (a)

The probability that it takes exactly 3 pulls to start the mower is given by the formula for the geometric distribution: \[ P(X = k) = q^{k-1} \times p \] where \( k \) is the number of trials (pulls) needed. Here, \( k = 3 \).
04

Calculate the Probability for Part (a)

Substitute the values into the formula: \[ P(X = 3) = 0.8^{3-1} \times 0.2 = 0.8^2 \times 0.2 = 0.64 \times 0.2 = 0.128 \]. So, there is a 12.8\(\%\) chance that it takes Rita exactly 3 pulls to start the mower.
05

Understanding the Problem for Part (b)

For part (b), we are asked to find the probability that it takes more than 10 pulls to start the mower. This means all of the first 10 pulls have to be failures.
06

Calculate the Probability for Part (b)

The probability that all 10 pulls are failures (the mower does not start) and the first success is on a subsequent pull is given by: \[ P(X > 10) = q^{10} \] where \( q = 0.8 \).
07

Compute the Probability for Part (b)

Calculate \( P(X > 10) \): \[ P(X > 10) = 0.8^{10} \approx 0.1074 \]. Therefore, there is approximately a 10.74\(\%\) chance that it takes more than 10 pulls to start the mower.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability
Probability is a fundamental concept in statistics that measures the likelihood of an event occurring. In everyday language, it helps us understand how likely it is that something will happen. In the case of Rita's cranky mower, probability is used to calculate how likely it is for her mower to start after a certain number of pulls.

To calculate probability, we often use a ratio. It compares the number of successful outcomes to the total number of possible outcomes. In mathematics, probability values range from 0 to 1, where 0 means the event will not happen and 1 means the event is certain to occur.
  • For example, a probability of 0.2 (or 20%) indicates a 20% chance of the event occurring, like Rita's mower starting.
Understanding probability allows us to predict and assess outcomes effectively.
Geometric Probability Formula
The geometric probability formula is particularly useful when dealing with scenarios where you are looking for the first success in a series of trials. This formula is used in a geometric distribution, which models the probability of achieving the first success after a specific number of independent trials.

For Rita's problem, the geometric probability formula is as follows: \[ P(X = k) = q^{k-1} \times p \]
  • In this formula, \( p \) represents the probability of success on any given trial, which is 0.2 for Rita's mower.
  • \( q \) represents the probability of failure, calculated as \( q = 1 - p = 0.8 \).
  • \( k \) is the trial at which the first success occurs.
Using this formula helps to determine the specific pull on which the mower will start. It's an essential tool for calculating the likelihood of events over repeated independent trials.
Trial Success and Failure
In probability, each attempt to achieve a successful outcome can be considered a trial. A single trial results in either a success or a failure.

In the case of Rita's cranky mower, each time she pulls the cord constitutes a trial. Success is defined as the mower starting, while failure is when it does not start.
  • The probability of success on each pull is denoted as \( p = 0.2 \).
  • The probability of failure, therefore, is \( q = 1 - p = 0.8 \).
Over multiple trials, the concepts of success and failure become increasingly important as they help us understand and predict patterns. When discussing occurrences over several attempts, we refer to the geometric distribution to model when the first success might happen.
Statistical Calculation Steps
Calculating probabilities using geometric distribution involves several clear steps. These are necessary to ensure accurate results. Here’s how to handle such calculations systematically.

First, identify the probability of success \( p \) and of failure \( q \). For Rita, this means setting \( p = 0.2 \) and \( q = 0.8 \).

Next, apply the geometric probability formula to compute the probability for a specific event. For instance, to find the probability of the mower starting on the third pull, use:\[ P(X = k) = q^{k-1} \times p \]
  • For exactly three pulls, plug in the values: \( k = 3 \), leading to \( P(X = 3) = 0.8^2 \times 0.2 = 0.128 \).
For events taking more trials, consider scenarios such as "more than 10 pulls". This probability is calculated by: \[ P(X > 10) = q^{10} \].
  • Here, \( P(X > 10) = 0.8^{10} \approx 0.1074 \), representing the chance of exceeding 10 pulls.
These steps demonstrate how to systematically decide and utilize mathematical principles in probability assessment.

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