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Meal plan After surveying students at Dartmouth College, a campus organization calculated that a \(95 \%\) confidence interval for the mean cost of food for one term (of three in the Dartmouth trimester calendar) is (\$1372, \$1562). Now the organization is trying to write its report and is considering the following interpretations. Comment on each. a. \(95 \%\) of all students pay between \(\$ 1372\) and \(\$ 1562\) for food. b. \(95 \%\) of the sampled students paid between \(\$ 1372\) and \(\$ 1562\) c. We're \(95 \%\) sure that students in this sample averaged between \(\$ 1372\) and \(\$ 1562\) for food. d. \(95 \%\) of all samples of students will have average food costs between \(\$ 1372\) and \(\$ 1562\). e. We're \(95 \%\) sure that the average amount all students pay is between \(\$ 1372\) and \(\$ 1562\).

Short Answer

Expert verified
Only statement e correctly describes what it means for the mean cost of food to have a 95% confidence interval of $1372 to $1562. The other statements are common misconceptions about confidence intervals and do not accurately reflect what these range estimates mean in terms of the population parameter they are estimating.

Step by step solution

01

Interpretation of statement a

Statement a suggests that 95% of all students pay between $1372 and $1562 for food. This interpretation is incorrect. A confidence interval does not tell us about individuals within the overall population. It indicates where we expect the true population parameter (in this case the mean cost of food per term) falls, not the costs for individual students.
02

Interpretation of statement b

Statement b proposes that 95% of the sampled students paid between $1372 and $1562. This is also incorrect. The confidence interval tells us about where we expect the true population mean falls, not about individual observations in the sample.
03

Interpretation of statement c

Statement c says we're 95% sure that students in this sample averaged between $1372 and $1562 for food. This statement is wrong. The confidence interval is not concerned with averages within a specific sample, but rather is an estimate of where the true population parameter may lie.
04

Interpretation of statement d

Statement d claims that 95% of all samples of students will have average food costs between $1372 and $1562. It's a common misconception but still incorrect. Although different samples will have different averages, it's not true that 95% of them will fall within the given interval. The confidence interval should be used as an estimate for the parameter of the whole population, not for samples.
05

Interpretation of statement e

Statement e states that we're 95% sure that the average amount all students pay is between $1372 and $1562. This is the most accurate interpretation of a 95% confidence interval. It means that we can be 95% confident that the true average cost for all students falls between these two amounts.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Statistics
Statistics is a branch of mathematics that deals with the collection, analysis, interpretation, and presentation of masses of numerical data. It enables us to make sense of all the information around us, from election polls to medical research findings. In the context of the court case, statistics would refer to analyzing the numerical data related to the case, such as the incidence of a particular type of crime in the area, or the likelihood of certain alibis being legitimate based on historical data.

The key to understanding statistics lies in understanding its terms and concepts. For example, a confidence interval is a range of values, derived from sample data, that is likely to contain the value of an unknown population parameter. It is used to indicate the reliability of an estimate. In our exercise, the confidence interval gives us a range where we can expect the true average cost of food for all students at Dartmouth College to lie.
Deciphering Population Mean
The population mean is a measure that tells us the average value of a particular characteristic in a population. For a statistician, understanding the population mean is crucial since it represents a central value for a data set. In our Dartmouth College example, the true population mean refers to the average cost of food for all students at the college over a term.

However, obtaining data from every single student is often impractical or impossible, which is why we use sample data to estimate this population mean. It's important to note, as our exercise demonstrates, that the confidence interval does not predict individual costs but rather where we expect the average cost for the entire student population to fall.
Sample Data and Its Significance
Sample data are a subset of data collected from a population, used to make inferences or estimations about the population. In statistical studies, gathering data from every individual in a population is rarely feasible; thus, we collect sample data that's representative of the population.

The exercise at Dartmouth College did just this by surveying a group of students to estimate the average food cost for the entire student body. The confidence interval calculated from this sample provides an estimate for the population mean — not the mean of the sample itself. This distinction is often misunderstood, leading to incorrect interpretations like those we clarified in the solution.
Statistical Inference: Making Sense of Data
Statistical inference involves making educated guesses about a population based on sample data. It comprises various techniques like estimation (including the use of confidence intervals) and hypothesis testing, which help us make predictions or decisions about population parameters.

In the context of our Dartmouth College exercise, statistical inference allows us to derive a confidence interval that we use to estimate where the true population mean likely falls. The correct interpretation, as stated in the solution (statement e), reflects understanding that while we can never be certain about the population mean, we can use the confidence interval to say we're 95% confident the true mean lies within a specific range. It is this interval that forms the basis for sound conclusions and decisions in research, industry, policy making, and various other fields that rely on data analysis.

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Most popular questions from this chapter

GPAs A college's data about the incoming freshmen indicate that the mean of their high school GPAs was \(3.4,\) with a standard deviation of 0.35 ; the distribution was roughly mound-shaped and only slightly skewed. The students are randomly assigned to freshman writing seminars in groups of 25\. What might the mean GPA of one of these seminar groups be? Describe the appropriate sampling distribution model-shape, center, and spread-with attention to assumptions and conditions. Make a sketch using the \(68-95\) \(99.7 \mathrm{P}\)

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Hot dogs A nutrition lab tested 40 hot dogs to see if their mean sodium content was less than the \(325-\mathrm{mg}\) upper limit set by regulations for "reduced sodium" franks. A \(90 \%\) confidence interval estimated the mean sodium content for this kind of hot dog at 317.2 to \(326.8 \mathrm{mg}\). Given this, what would you tell the lab about whether the hot dogs satisfy the regulation.

Ski wax Bjork Larsen was trying to decide whether to use a new racing wax for cross-country skis. He decided that the wax would be worth the price if he could average less than 55 seconds on a course he knew well, so he planned to study the wax by racing on the course 8 times. His 8 race times were \(56.3,65.9,50.5,52.4,46.5,57.8,52.2,\) and 43.2 seconds. Should he buy the wax? Explain by using a confidence interval

Teachers Software analysis of the salaries of a random sample of 288 Nevada teachers produced the confidence interval shown below. Which conclusion is correct? What's wrong with the others? with \(90.00 \%\) Confidence, \(t\) -interval for \(\mu: 43454<\mu(\) TchPay \()<45398\) a. If we took many random samples of 288 Nevada teachers, about 9 out of 10 of them would produce this confidence interval. b. If we took many random samples of Nevada teachers, about 9 out of 10 of them would produce a confidence interval that contained the mean salary of all Nevada teachers. c. About 9 out of 10 Nevada teachers earn between \(\$ 43,454\) and \(\$ 45,398 .\) d. About 9 out of 10 of the teachers surveyed earn between \(\$ 43,454\) and \(\$ 45,398\). e. We are \(90 \%\) confident that the average teacher salary in the United States is between \(\$ 43,454\) and \(\$ 45,398\).

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