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Teachers A 2011 Gallup Poll found that \(76 \%\) of Americans believe that high achieving high school students should be recruited to become teachers. This poll was based on a random sample of 1002 Americans. a. Find a \(90 \%\) confidence interval for the proportion of Americans who would agree with this. b. Interpret your interval in this context. c. Explain what "90\% confidence" means. d. Do these data refute a pundit's claim that \(2 / 3\) of Americans believe this statement? Explain.

Short Answer

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a. The 90% confidence interval for the proportion of Americans who would agree with the statement is calculated by following steps 1 to 4. b. This interval means that we are 90% confident that the true proportion of Americans who agree with the statement lies within this range. c. '90% confidence' means that if this procedure was repeated many times, about 90% of the calculated intervals would contain the true population proportion. d. Whether or not these data refute the pundit's claim is determined by comparing the calculated interval with the pundit's claim (Step 7).

Step by step solution

01

Calculating the proportion

Firstly, calculate the proportion of Americans who believe that high achieving high school students should be recruited to become teachers, which is given as \(76 \% \). Convert this to decimal form by dividing by 100, which gives \(0.76\).
02

Calculating the standard error

Next, calculate the standard error. The formula for the standard error of a proportion is given by \(\sqrt{p*(1-p) / n}\), where \(p\) is the proportion and \(n\) is the sample size. Substitute \(p = 0.76\) and \(n = 1002\) to get the standard error.
03

Calculating the z-score

A 90% confidence interval corresponds to a z-score of 1.645 (for a one tailed test). You can either remember this value or look it up in a z-table.
04

Calculating the confidence interval

Now, calculate the confidence interval using the formula \(p \pm z*SE\), where \(SE\) is the standard error. Substitute the previously computed values to get the confidence interval.
05

Interpreting the confidence interval

The obtained interval is the range of values that likely contain the true population proportion with a confidence of 90%.
06

Understanding 90% confidence

90% confidence means that if this procedure was repeated many times, about 90% of the calculated confidence intervals would contain the true population proportion.
07

Comparing the derived interval with a claimed proportion

Lastly, compare the confidence interval with the pundit's claim of \(2 / 3\) or \(0.667\). If this value lies within the calculated interval, then we cannot refute the pundit's claim. Otherwise, we can.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Proportion
In statistics, a **proportion** represents a part of the whole. It's a way to express how many instances of a particular outcome occur in relation to the total number of possible outcomes. For example, in the Gallup Poll described, the proportion is the percentage of Americans who believe that high-achieving students should be recruited to become teachers. The poll indicates that 76% believe this, which can be converted to the numerical form of 0.76. Converting percentages to decimal form makes calculations easier, especially when dealing with formulas. Proportions aren't just percentages, though; they are vital in calculating other statistical measures, like the standard error and confidence intervals.
Standard Error
The **standard error** measures the accuracy with which a sample proportion estimates the true population proportion. It helps us understand how much variability to expect between the sample and the population.To calculate the standard error of a proportion, we use the formula: \[ SE = \sqrt{\frac{p(1-p)}{n}} \]Here, \( p \) is the sample proportion, and \( n \) is the sample size. With the Gallup Poll, the sample proportion \( p \) is 0.76, and the sample size \( n \) is 1002. Calculating the standard error helps us in constructing more informed and precise statistical interpretations. It is smaller with larger sample sizes, indicating that a larger sample gives a more accurate estimate of the population proportion.
Z-score
A **Z-score** in statistics is a numerical measurement that describes a value's relationship to the mean of a group of values. It's expressed as how many standard deviations the value is from the mean. When it comes to confidence intervals, the Z-score helps us determine the margin of error. For the 90% confidence interval cited in the Gallup Poll, the Z-score is 1.645. This is because the interval corresponds to the middle 90% of a standard normal distribution. A Z-score is essential in creating confidence intervals, as it scales the standard error to define the interval's range. It tells us how far and in which direction, a sample proportion is from the population proportion. It's a critical value that ensures we capture the true proportion with a certain level of confidence.
Gallup Poll
A **Gallup Poll** is a type of public opinion polling done by the Gallup organization, a well-known analytics and advisory company. These polls are typically random samples of specific populations and are used to infer the opinions and beliefs of the broader population. In 2011, the Gallup Poll in question reported that 76% of Americans believed in recruiting high-achieving students to become teachers. The credibility of this poll, like many others conducted by Gallup, relies on the random sampling technique, which is crucial for ensuring unbiased and representative results. The information from such polls helps inform policymakers, educators, and the public on widespread opinions and attitudes, shedding light on prevailing views within the population.
Hypothesis Testing
**Hypothesis testing** is a statistical method that uses sample data to evaluate a hypothesis about a population parameter. In the example provided, hypothesis testing is used to determine whether the claim that "2/3 of Americans believe" in recruiting high-achievers as teachers is supported by the poll data. Here's a breakdown of how it works:
  • We start with a **null hypothesis**, often stating that there is no effect or no difference. Here, it would claim that the true proportion is 0.667 (or 2/3).
  • The **alternative hypothesis** suggests there is an effect or a difference, stating that the true proportion is not 0.667.
  • We compare our calculated confidence interval to the hypothesized value. If 0.667 lies within the confidence interval, we do not have enough evidence to refute the pundit's claim.
Hypothesis testing allows researchers to draw inferences about populations using data from samples, guiding decisions based on statistical evidence.

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Most popular questions from this chapter

Rickets Vitamin D, whether ingested as a dietary supplement or produced naturally when sunlight falls on the skin, is essential for strong, healthy bones. The bone disease rickets was largely eliminated in England during the 1950 s, but now there is concern that a generation of children more likely to watch TV or play computer games than spend time outdoors is at increased risk. A recent study of 2700 children randomly selected from all parts of England found \(20 \%\) of them deficient in vitamin D. a. Find a \(98 \%\) confidence interval. b. Explain carefully what your interval means. c. Explain what "98\% confidence" means.

Junk mail Direct mail advertisers send solicitations (a.k.a. "junk mail") to thousands of potential customers in the hope that some will buy the company's product. The acceptance rate is usually quite low. Suppose a company wants to test the response to a new flyer, and sends it to 1000 people randomly selected from their mailing list of over 200,000 people. They get orders from 123 of the recipients. a. Create a \(90 \%\) confidence interval for the percentage of people the company contacts who may buy something. b. Explain what this interval means. c. Explain what "90\% confidence" means. d. The company must decide whether to now do a mass mailing. The mailing won't be cost-effective unless it produces at least a \(5 \%\) return. What does your confidence interval suggest? Explain.

Pilot study A state's environmental agency worries that many cars may be violating clean air emissions standards. The agency hopes to check a sample of vehicles in order to estimate that percentage with a margin of error of \(3 \%\) and \(90 \%\) confidence. To gauge the size of the problem, the agency first picks 60 cars and finds 9 with faulty emissions systems. How many should be sampled for a full investigation?

Confidence intervals Several factors are involved in the creation of a confidence interval. Among them are the sample size, the level of confidence, and the margin of error. Which statements are true? a. For a given sample size, higher confidence means a smaller margin of error. b. For a specified confidence level, larger samples provide smaller margins of error. c. For a fixed margin of error, larger samples provide greater confidence. d. For a given confidence level, halving the margin of error requires a sample twice as large.

Conclusions A catalog sales company promises to deliver orders placed on the Internet within 3 days. Follow-up calls to a few randomly selected customers show that a \(95 \%\) confidence interval for the proportion of all orders that arrive on time is \(88 \% \pm 6 \%\). What does this mean? Are these conclusions correct? Explain. a. Between \(82 \%\) and \(94 \%\) of all orders arrive on time. b. Ninety-five percent of all random samples of customers will show that \(88 \%\) of orders arrive on time. c. Ninety-five percent of all random samples of customers will show that \(82 \%\) to \(94 \%\) of orders arrive on time. d. We are \(95 \%\) sure that between \(82 \%\) and \(94 \%\) of the orders placed by the sampled customers arrived on time. e. On \(95 \%\) of the days, between \(82 \%\) and \(94 \%\) of the orders will arrive on time.

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