/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 52 The accompanying table gives the... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The accompanying table gives the mean and standard deviation of reaction times (in seconds) for each of two different stimuli: $$ \begin{array}{lcc} & \text { Stimulus } & \text { Stimulus } \\ & 1 & 2 \\ \hline \text { Mean } & 6.0 & 3.6 \\ \text { Standard deviation } & 1.2 & 0.8 \\ \hline \end{array} $$ If your reaction time is 4.2 seconds for the first stimulus and 1.8 seconds for the second stimulus, to which stimulus are you reacting (compared to other individuals) relatively more quickly?

Short Answer

Expert verified
The reaction to Stimulus 1 is relatively quicker compared to Stimulus 2.

Step by step solution

01

Calculate the z-score for Stimulus 1

The z-score is calculated with the formula \(Z = (X - μ) / σ\), where \(X\) is the value to be standardized (in this case, the reaction time), \(μ\) is the mean of the distribution, and \(σ\) is the standard deviation of the distribution. For Stimulus 1, \(X = 4.2 seconds\), \(μ = 6.0 seconds\), and \(σ = 1.2 seconds\). This gives us a z-score \(Z1 = (4.2 - 6.0) / 1.2 = -1.5\).
02

Calculate the z-score for Stimulus 2

We repeat the z-score calculation for Stimulus 2. For Stimulus 2, \(X = 1.8 seconds\), \(μ = 3.6 seconds\), and \(σ = 0.8 seconds\). This gives us a z-score \(Z2 = (1.8 - 3.6) / 0.8 = -2.25\).
03

Compare the z-scores

The lower the z-score, the closer the reaction time is to the average for that stimulus, and hence the quicker the relative reaction time. In this case, \(Z1 = -1.5\) is greater than \(Z2 = -2.25\), thus the reaction to Stimulus 1 is relatively quicker compared to Stimulus 2.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mean and Standard Deviation
The concepts of mean and standard deviation are crucial in statistics, especially when analyzing sets of data. The mean, often called the average, is found by adding all the values together and then dividing by the number of values. It's a measure of central tendency that helps give a single value representation of a dataset.
For example, if the mean reaction time for a stimulus is 6.0 seconds, this indicates that, on average, individuals respond in six seconds. However, it doesn't tell us how those reaction times spread around this average.
The standard deviation helps with this. It measures the amount of variation or dispersion in a set of values. A smaller standard deviation means the values are grouped closely around the mean, while a larger one indicates they are spread out over a wider range. In reaction times, a standard deviation of 1.2 seconds indicates more variability in individual responses compared to a standard deviation of 0.8 seconds.
  • Mean is a measure of central tendency.
  • Standard deviation is a measure of variability.
  • Together, they provide a fuller picture of a data set.
Reaction Time
Reaction time is the duration it takes an individual to respond to a stimulus. Understanding one's reaction time can give insights into neurological and psychological functions.
In an experimental setting, reaction time is measured from the onset of a stimulus to the moment a relevant response is made. Consistent variations might indicate differing conditions or states of attention, thus important for comparing individuals' responses across different stimuli.
For instance, if someone's reaction time is shorter than the average in a normal distribution, it may suggest a quicker-than-average response. In our example, the reaction times of 4.2 and 1.8 seconds are measured against set stimulus means, showing how an individual compares to the norm.
Statistical Comparison
Statistical comparison allows us to assess how individual cases stack up against the average population. An effective tool for this is the Z-score calculation.
A Z-score shows how many standard deviations a data point is from the mean. A negative Z-score indicates the data point is below the mean, while a positive one indicates it is above.
In the context of reaction times, calculating Z-scores for different stimuli gives a relative measure of response speed. Lower Z-scores indicate faster reaction speeds compared to the average, as seen with Stimulus 1 and 2. Stimulus 2 has a lower Z-score, indicating a relatively quicker reaction compared to the first stimulus despite both being below their respective means.
Understanding these comparisons helps in analyzing the behavior across differing conditions, giving researchers and individuals a tool to measure performance variability:
  • Z-score is a statistical measure of a score's relationship to the mean.
  • It helps in comparing individual vs. population performance.
  • Negative means below average, positive means above.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

An instructor has graded 19 exam papers submitted by students in a class of 20 students, and the average so far is 70 . (The maximum possible score is \(100 .\) ) How high would the score on the last paper have to be to raise the class average by 1 point? By 2 points?

Give two sets of five numbers that have the same mean but different standard deviations, and give two sets of five numbers that have the same standard deviation but different means.

An experiment to study the lifetime (in hours) for a certain brand of light bulb involved putting 10 light bulbs into operation and observing them for 1000 hours. Eight of the light bulbs failed during that period, and those lifetimes were recorded. The lifetimes of the two light bulbs still functioning after 1000 hours are recorded as \(1000+.\) The resulting sample observations were \(\begin{array}{llllllll}480 & 790 & 1000+ & 350 & 920 & 860 & 570 & 1000+\end{array}\) \(\begin{array}{ll}170 & 290\end{array}\) Which of the measures of center discussed in this section can be calculated, and what are the values of those measures?

The paper "Portable Social Groups: Willingness to Communicate, Interpersonal Communication Gratifications, and Cell Phone Use among Young Adults" (International journal of Mobile Communications [2007]: \(139-156\) ) describes a study of young adult cell phone use patterns. a. Comment on the following quote from the paper. Do you agree with the authors? Seven sections of an Introduction to Mass Communication course at a large southern university were surveyed in the spring and fall of 2003 . The sample was chosen because it offered an excellent representation of the population under study young adults. b. Below is another quote from the paper. In this quote, the author reports the mean number of minutes of cell phone use per week for those who participated in the survey. What additional information would have been provided about cell phone use behavior if the author had also reported the standard deviation? Based on respondent estimates, users spent an average of 629 minutes (about 10.5 hours) per week using their cell phone on or off line for any reason.

The accompanying data on number of minutes used for cell phone calls in 1 month was generated to be consistent with summary statistics published in a report of a marketing study of San Diego residents (TeleTruth, March 2009 ): \(\begin{array}{rrrrrrrrrr}189 & 0 & 189 & 177 & 106 & 201 & 0 & 212 & 0 & 306 \\\ 0 & 0 & 59 & 224 & 0 & 189 & 142 & 83 & 71 & 165\end{array}\) \(\begin{array}{lllll}236 & 0 & 142 & 236 & 130\end{array}\) a. Compute the values of the quartiles and the interquartile range for this data set. b. Explain why the lower quartile is equal to the minimum value for this data set. Will this be the case for every data set? Explain.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.