/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 51 The following data values are 20... [FREE SOLUTION] | 91Ó°ÊÓ

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The following data values are 2009 per capita expenditures on public libraries for each of the \(50 \mathrm{U} . \mathrm{S}\). states (from www.statemaster.com): \(\begin{array}{rrrrrrr}16.84 & 16.17 & 11.74 & 11.11 & 8.65 & 7.69 & 7.48 \\\ 7.03 & 6.20 & 6.20 & 5.95 & 5.72 & 5.61 & 5.47 \\ 5.43 & 5.33 & 4.84 & 4.63 & 4.59 & 4.58 & 3.92 \\ 3.81 & 3.75 & 3.74 & 3.67 & 3.40 & 3.35 & 3.29 \\ 3.18 & 3.16 & 2.91 & 2.78 & 2.61 & 2.58 & 2.45 \\ 2.30 & 2.19 & 2.06 & 1.78 & 1.54 & 1.31 & 1.26 \\ 1.20 & 1.19 & 1.09 & 0.70 & 0.66 & 0.54 & 0.49 \\ 0.30 & 0.01 & & & & & \end{array}\) a. Summarize this data set with a frequency distribution. Construct the corresponding histogram. b. Use the histogram in Part (a) to find approximate values of the following percentiles: i. 50 th iv. \(90 \mathrm{th}\) ii. 70 th v. \(40 \mathrm{th}\) iii. 10 th

Short Answer

Expert verified
While an exact solution can't be provided without creating a real histogram, the logic to find the solution is as follows: sort the data, find the frequency distribution, build a histogram, and then use the histogram to find the approximate values for the 50th, 70th, 10th, 90th, and 40th percentiles.

Step by step solution

01

Sort Data and Calculate Frequency

Firstly, make sure to sort the data from smallest to largest. Then count up frequencies of values. The frequency indicates how often a particular value appears. As there are many unique values, it may be useful to choose some interval class (say, having an interval class of 1.0, for example).
02

Construct Histogram

Now, with the sorted values and corresponding frequencies, a histogram can be constructed. The horizontal axis will present the intervals of the data and vertical axis will represent the frequency. The bar height corresponds to the frequency of the values within the particular interval.
03

Calculate Percentiles

The next step is to calculate percentiles. Percentiles are measures that divide the data into 100 equal parts. The nth percentile corresponds to the value below which n percent of the data falls. To calculate the 50th, 70th, 10th, 90th, and 40th percentiles, locate the equivalent area on the histogram first. For example, to find the 50th percentile, find the value which splits off the lowest 50% of data from the highest 50%. In other words, it's the median of the data.
04

Recap and check for understanding

Summarize all the steps and double check that all parts of the exercise have been fulfilled: the frequency distribution has been calculated and presented, the histogram has been created, and the percentiles have been approximately valued.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Frequency Distribution
Understanding frequency distribution is essential when analyzing sets of data such as expenditures on public libraries. A frequency distribution is simply an organized tally of how often each value in a set of data occurs. In the given problem, we might decide to group the expenditures into ranges (also known as bins) to make it easier to see patterns. For instance, one possible grouping could be in increments of \(1.00—how many states spend between \)0.00–\(1.00, \)1.00–$2.00, and so forth. By counting the number of observations within each of these ranges, you produce a frequency table that can then be visualized as a histogram. This process transforms raw data into a form where trends might be more easily spotted.
Histogram
A histogram provides a visual representation of frequency distribution. It consists of bars where each bar's height is proportional to the frequency of values within the interval it represents. When constructing a histogram from our expenditure data, the horizontal axis (the x-axis) would depict the range of expenditures, divided into bins, while the vertical axis (the y-axis) would represent the frequency of states within each bin. For the provided data, this bar chart will help students see which expenditure ranges are most common among the states and identify any outliers at a glance. It's a powerful tool for summarizing large data sets and can help in understanding the overall distribution pattern, like whether it's skewed toward higher or lower expenditure values.
Percentiles
Percentiles are a way to comprehend the relative standing of a value within a data set. The nth percentile tells you what percentage of the data falls below that value. For instance, the 50th percentile, also known as the median, is the middle value where half the data is lower and the other half is higher. On the histogram, you would find the 50th percentile by looking for the value that divides the area under the histogram into two equal parts. Similarly, the 10th percentile separates the lowest 10% of the data from the rest, and so forth. This method of dividing the data into one hundred equal parts can provide insight into the distribution's spread and center, and is especially useful when comparing different data sets or examining the distribution's shape.
Data Analysis
Analyzing data involves collecting, cleaning, interpreting, and presenting it. After creating a frequency distribution and a histogram, we proceed to examine the data for patterns, relationships, and insights. In the context of public library expenditures, we would analyze the histogram and calculate various percentiles to understand not just the average or mid-range spending, but also how spending is distributed across states. By doing this, we can identify which states are spending significantly more or less than others, which spending ranges are most common, or which percent of states fall below a certain expenditure threshold. This statistical analysis helps to make informed decisions and strategies in policy-making, budget allocation, and understanding public investment trends.

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Most popular questions from this chapter

The paper "Modeling and Measurements of Bus Service Reliability" (Transportation Research [1978]: \(253-256\) ) studied various aspects of bus service and presented data on travel times (in minutes) from several different routes. The accompanying frequency distribution is for bus travel times from origin to destination on one particular route in Chicago during peak morning traffic periods: $$ \begin{array}{crc} \begin{array}{c} \text { Travel } \\ \text { Time } \end{array} & \text { Frequency } & \begin{array}{c} \text { Relative } \\ \text { Frequency } \end{array} \\ \hline 15 \text { to }<16 & 4 & .02 \\ 16 \text { to }<17 & 0 & .00 \\ 17 \text { to }<18 & 26 & .13 \\ 18 \text { to }<19 & 99 & .49 \\ 19 \text { to }<20 & 36 & .18 \\ 20 \text { to }<21 & 8 & .04 \\ 21 \text { to }<22 & 12 & .06 \\ 22 \text { to }<23 & 0 & .00 \\ 23 \text { to }<24 & 0 & .00 \\ 24 \text { to }<25 & 0 & .00 \\ 25 \text { to }<26 & 16 & .08 \\ \hline \end{array} $$ a. Construct the corresponding histogram. b. Compute (approximately) the following percentiles: i. 8 6th iv. 95 th ii. \(15 \mathrm{th}\) v. 10 th iii. 90 th

The article "Rethink Diversification to Raise Returns, Cut Risk" (San Luis Obispo Tribune, January 21,2006 ) included the following paragraph: In their research, Mulvey and Reilly compared the results of two hypothetical portfolios and used actual data from 1994 to 2004 to see what returns they would achieve. The first portfolio invested in Treasury bonds, domestic stocks, international stocks, and cash. Its 10 -year average annual return was \(9.85 \%\) and its volatilitymeasured as the standard deviation of annual returns-was \(9.26 \%\). When Mulvey and Reilly shifted some assets in the portfolio to include funds that invest in real estate, commodities, and options, the 10 -year return rose to \(10.55 \%\) while the standard deviation fell to \(7.97 \% .\) In short, the more diversified portfolio had a slightly better return and much less risk. Explain why the standard deviation is a reasonable measure of volatility and why it is reasonable to interpret a smaller standard deviation as meaning less risk.

The U.S. Census Bureau ( 2000 census) reported the following relative frequency distribution for travel time to work for a large sample of adults who did not work at home: $$ \begin{array}{cc} \begin{array}{c} \text { Travel Time } \\ \text { (minutes) } \end{array} & \text { Relative Frequency } \\ \hline 0 \text { to }<5 & .04 \\ 5 \text { to }<10 & .13 \\ 10 \text { to }<15 & .16 \\ 15 \text { to }<20 & .17 \\ 20 \text { to }<25 & .14 \\ 25 \text { to }<30 & .05 \\ 30 \text { to }<35 & .12 \\ 35 \text { to }<40 & .03 \\ 40 \text { to }<45 & .03 \\ 45 \text { to }<60 & .06 \\ 60 \text { to }<90 & .05 \\ 90 \text { or more } & .02 \\ \hline \end{array} $$ a. Draw the histogram for the travel time distribution. In constructing the histogram, assume that the last interval in the relative frequency distribution ( 90 or more) ends at 200 ; so the last interval is 90 to \(<200\). Be sure to use the density scale to determine the heights of the bars in the histogram because not all the intervals have the same width. b. Describe the interesting features of the histogram from Part (a), including center, shape, and spread. c. Based on the histogram from Part (a), would it be appropriate to use the Empirical Rule to make statements about the travel time distribution? Explain why or why not. d. The approximate mean and standard deviation for the travel time distribution are 27 minutes and 24 minutes, respectively. Based on this mean and standard deviation and the fact that travel time cannot be negative, explain why the travel time distribution could not be well approximated by a normal curve. e. Use the mean and standard deviation given in Part (d) and Chebyshev's Rule to make a statement about i. the percentage of travel times that were between 0 and 75 minutes ii. the percentage of travel times that were between 0 and 47 minutes f. How well do the statements in Part (e) based on Chebyshev's Rule agree with the actual percentages for the travel time distribution? (Hint: You can estimate the actual percentages from the given relative frequency distribution.)

Going back to school can be an expensive time for parents - second only to the Christmas holiday season in terms of spending (San Luis Obispo Tribune, August 18,2005\() .\) Parents spend an average of \(\$ 444\) on their children at the beginning of the school year stocking up on clothes, notebooks, and even iPods. Of course, not every parent spends the same amount of money and there is some variation. Do you think a data set consisting of the amount spent at the beginning of the school year for each student at a particular elementary school would have a large or a small standard deviation? Explain.

The chapter introduction gave the accompanying data on the percentage of those eligible for a lowincome subsidy who had signed up for a Medicare drug plan in each of 49 states (information was not available for Vermont) and the District of Columbia (USA Today, May 9,2006 ). $$ \begin{array}{llllllll} 24 & 27 & 12 & 38 & 21 & 26 & 23 & 33 \\ 19 & 19 & 26 & 28 & 16 & 21 & 28 & 20 \\ 21 & 41 & 22 & 16 & 29 & 26 & 22 & 16 \\ 27 & 22 & 19 & 22 & 22 & 22 & 30 & 20 \\ 21 & 34 & 26 & 20 & 25 & 19 & 17 & 21 \\ 27 & 19 & 27 & 34 & 20 & 30 & 20 & 21 \\ 14 & 18 & & & & & & \end{array} $$ a. Compute the mean for this data set. b. The article stated that nationwide, \(24 \%\) of those eligible had signed up. Explain why the mean of this data set from Part (a) is not equal to 24 . (No information was available for Vermont, but that is not the reason that the mean differs- the \(24 \%\) was calculated excluding Vermont.)

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