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In an AP-AOL sports poll (Associated Press, December 18,2005 ), 394 of 1000 randomly selected U.S. adults indicated that they considered themselves to be baseball fans. Of the 394 baseball fans, 272 stated that they thought the designated hitter rule should either be expanded to both baseball leagues or eliminated. a. Construct a \(95 \%\) confidence interval for the proportion of U.S. adults that consider themselves to be baseball fans. b. Construct a \(95 \%\) confidence interval for the proportion of those who consider themselves to be baseball fans that think the designated hitter rule should be expanded to both leagues or eliminated. c. Explain why the confidence intervals of Parts (a) and (b) are not the same width even though they both have a confidence level of \(95 \%\).

Short Answer

Expert verified
The constructed \(95 %\) confidence interval for the proportion of U.S. adults that consider themselves to be baseball fans, and for the proportion of these fans who believe the designated hitter rule should be expanded to both leagues or eliminated are not the same because the sample sizes used to calculate these proportions are different, leading to different standard errors. The specific intervals would be calculated in Step 3.

Step by step solution

01

Calculate sample proportions

Find the sample proportions (\(p\)) which are the ratios of the specific opinions to the total number of surveyed individuals. For the first case, \(p_1 = \frac{394}{1000}\), and for the second case, \(p_2= \frac{272}{394}\).
02

Calculate standard errors

Compute the standard errors (SE) for the proportions. The formula for standard error is \(SE = \sqrt{\frac{{p (1 - p)}}{n}}\) where \(n\) is the number of samples. Hence, calculate \(SE_1\) and \(SE_2\) for the first and second cases, respectively.
03

Construct confidence intervals

The \(95\%\) confidence interval (CI) is calculated as \(CI = p \pm 1.96 \times SE\). Here, 1.96 is the z-value for a \(95\%\) confidence level. Thus, create two confidence intervals, one for \(p_1\) and one for \(p_2\), using their respective SEs.
04

Explanation for different CI widths

The widths of the confidence intervals are affected by the variability in the data (reflected by the standard error) and the sample sizes. In this case, even though the confidence level is the same (\(95\% \)), the estimates are derived from different sample sizes (1000 and 394), resulting in different standard errors.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Proportions
Understanding sample proportions is crucial for statistical analysis and forms the basis of many inferences we make about a population. Essentially, a sample proportion is the fraction of the sample that displays the characteristic we're interested in. For instance, in a survey where 394 out of 1000 adults identify as baseball fans, the sample proportion (\( p \)) is the number of individuals with the characteristic (baseball fans) divided by the total number of people surveyed. Thus, we calculate it as \( p = \frac{\text{number of 'successes'}}{\text{total sample size}} = \frac{394}{1000} \).

Similarly, from those 394 baseball fans, if 272 believe the designated hitter rule should be altered, we find another sample proportion for this subgroup: \( p = \frac{272}{394} \). These proportions are estimates of the true population proportion and serve as the starting point for constructing confidence intervals to infer population statistics.
Standard Error Calculation
The standard error (SE) is a measure of the amount of variability or dispersion of sample statistics, like the sample mean or sample proportion, from the population parameter. It's pivotal because it enables us to gauge how concentrated the sample estimates are around the actual population parameter. To compute the standard error of the sample proportion, we use the formula \( SE = \sqrt{\frac{{p(1 - p)}}{n}} \) where \( p \) is the sample proportion, and \( n \) is the total number of observations in the sample.

For the case of U.S. adults who are baseball fans, we have \( p_1 = \frac{394}{1000} \) and thus \( SE_1 = \sqrt{\frac{{p_1(1 - p_1)}}{1000}} \). Subsequent calculations will result in the standard error for \( p_1 \) which indicates the variability around the sample proportion of baseball fans in the general population.
Confidence Interval Formula
A confidence interval gives a range within which we can be reasonably sure the true population parameter lies. It's constructed around a sample statistic to reflect the precision of the estimate. The basic form of the confidence interval for a sample proportion is given by \( CI = p \pm z \times SE \) where \( p \) is the sample proportion, \( z \) is the z-score corresponding to the chosen confidence level (e.g., 1.96 for a 95% confidence level), and \( SE \) is the standard error of the sample proportion.

Thus, if we want to calculate a 95% confidence interval for the proportion of U.S. adults who are baseball fans, we would take our sample proportion \( p_1 \) and plug it into our formula along with the standard error we calculated earlier and the z-score for 95% confidence to get \( CI_1 = p_1 \pm 1.96 \times SE_1 \). The result is the range that, statistically speaking, has a 95% chance of containing the true proportion of U.S. adults who are baseball fans.
Statistical Variability
Statistical variability, also referred to as dispersion or variability, is the degree to which data points in a set differ from the average of the set or from each other. It impacts every measure in statistics, including the width of a confidence interval. High variability means that the data points are spread out over a larger range of values, which tends to yield a wider confidence interval indicating less precision in our estimates. Conversely, lower variability results in a narrower confidence interval, suggesting a more precise estimate.

Variability is influenced by several factors, including the sample size and the standard deviation or standard error. Larger sample sizes typically offer lower variability, as they tend to provide more accurate representations of the population. In the AP-AOL poll example, despite both confidence intervals being set at the 95% confidence level, their differing widths are attributed to the different sample sizes and proportions, hence different standard errors, demonstrating the impact of statistical variability.

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Most popular questions from this chapter

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