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9.14 Discuss how each of the following factors affects the width of the confidence interval for \(\pi\) : a. The confidence level b. The sample size c. The value of \(p\)

Short Answer

Expert verified
The confidence level and the value of p both tend to increase the width of the confidence interval for π, though the width decreases when p approaches 0 or 1. On the other hand, an increase in the sample size tends to decrease the width of the confidence interval.

Step by step solution

01

Analysis of Confidence Level

The confidence level indicates the level of certainty about the range within which an actual population parameter lies. A higher confidence level results in a wider confidence interval because to be more confident that the actual parameter is within the interval, the interval would have to cover a broader range of potential values.
02

Analysis of Sample Size

The sample size plays an inverse role in the determination of the width of the confidence interval. This is because larger the sample size, more information it provides about the population, thereby decreasing the uncertainty. Hence, as the sample size increases, the width of the confidence interval decreases.
03

Analysis of the Value of p

The value of p, the sample proportion, also has an effect on the width of the confidence interval. As p approaches 0 or 1, the width of the confidence interval tends to decrease as the binomial distribution becomes skewed. On the other hand, when p is around 0.5, the distribution is symmetric, leading to the widest possible confidence interval.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Confidence Level
To understand the confidence level, think about how certain we want to be that a range includes the true population parameter. In statistics, the confidence level is usually expressed as a percentage, like 95% or 99%. This percentage points to the likelihood that the confidence interval contains the true parameter.

When we choose a higher confidence level, say 99% instead of 95%, we are saying we want to be more certain. This increased certainty results in a wider confidence interval. Why? Because to capture the true parameter more surely, we must allow for a broader range to account for variability.
  • Higher confidence level = Wider interval.
  • Lower confidence level = Narrower interval.
The trade-off here is between certainty and precision. A wider interval is less precise but more certain to contain the true value.
Sample Size Effect on Interval
Sample size is a crucial element when calculating confidence intervals. Simply put, the larger your sample size, the narrower your confidence interval becomes. This is because a bigger sample provides more information about the population, thus reducing uncertainty about the estimates.

Mathematically, the variability in the sample data decreases as the sample size increases, which results in a smaller error margin. Thus, the confidence interval becomes narrower.
  • Larger sample size = Narrower confidence interval.
  • Smaller sample size = Wider confidence interval.
The key takeaway is that collecting a larger sample helps you make more precise estimates of the population parameter.
Binomial Distribution
The binomial distribution plays a significant role when working with proportions, often marked as \( p \). This is especially true when you deal with binary outcomes—such as success/failure, yes/no decisions.

The value of \( p \) affects the dispersion of these outcomes and thus the width of the confidence interval. As \( p \) gets close to 0 or 1, the binomial distribution becomes more skewed, and the interval gets narrower. Conversely, when \( p \) is around 0.5, the distribution is symmetric, which generally means a wider confidence interval.
  • Around \( p = 0.5 \) = Wider interval (more symmetric).
  • Close to \( p = 0 \) or 1 = Narrower interval (more skewed).
Understanding how \( p \) affects the distribution is essential for predicting how your interval might change with different outcomes.

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Most popular questions from this chapter

The article "Most Canadians Plan to Buy Treats, Many Will Buy Pumpkins, Decorations and/or Costumes" (Ipsos-Reid, October 24, 2005) summarized results from a survey of 1000 randomly selected Canadian residents. Each individual in the sample was asked how much he or she anticipated spending on Halloween during 2005 . The resulting sample mean and standard deviation were \(\$ 46.65\) and \(\$ 83.70\) respectively. a. Explain how it could be possible for the standard deviation of the anticipated Halloween expense to be larger than the mean anticipated expense.

An Associated Press article on potential violent behavior reported the results of a survey of 750 workers who were employed full time (San Luis Obispo Tribune, September 7,1999 ). Of those surveyed, 125 indicated that they were so angered by a coworker during the past year that they felt like hitting the coworker (but didn't). Assuming that it is reasonable to regard this sample of 750 as a random sample from the population of full-time workers. use this information to construct and interpret a \(90 \%\) confidence interval estimate of \(\pi\), the true proportion of fulltime workers so angered in the last year that they wanted to hit a colleague.

Despite protests from civil libertarians and gay rights activists, many people favor mandatory AIDS testing of certain at-risk groups, and some people even believe that all citizens should be tested. What proportion of the adults in the United States favor mandatory testing for all citizens? To assess public opinion on this issue, researchers conducted a survey of 1014 randomly selected adult U.S. citizens ("Large Majorities Continue to Back AIDS Testing," Gallup Poll Monthly [1991]: 25-28). The article reported that 466 of the 1014 people surveyed believed that all citizens should be tested. Use this information to estimate \(\pi\), the true proportion of all U.S. adults who favor AIDS testing of all citizens.

In an AP-AOL sports poll (Associated Press, December 18,2005 ), 394 of 1000 randomly selected U.S. adults indicated that they considered themselves to be baseball fans. Of the 394 baseball fans, 272 stated that they thought the designated hitter rule should either be expanded to both baseball leagues or eliminated. a. Construct a \(95 \%\) confidence interval for the proportion of U.S. adults that consider themselves to be baseball fans. b. Construct a \(95 \%\) confidence interval for the proportion of those who consider themselves to be baseball fans that think the designated hitter rule should be expanded to both leagues or eliminated. c. Explain why the confidence intervals of Parts (a) and (b) are not the same width even though they both have a confidence level of \(95 \%\).

The Center for Urban Transportation Research released a report stating that the average commuting distance in the United States is \(10.9 \mathrm{mi}\) (USA Today, August \(13 .\) 1991). Suppose that this average is actually the mean of a random sample of 300 commuters and that the sample standard deviation is \(6.2 \mathrm{mi}\). Estimate the true mean commuting distance using a \(99 \%\) confidence interval.

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