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Happiness in relationship Are people happy in their romantic relationships? The table shows results from the 2012 General Social Survey for adults classified by gender and happiness. \begin{tabular}{lrrrr} \hline & \multicolumn{3}{c} { Level of Happiness } & \\ \cline { 2 - 4 } Gender & Very Happy & Pretty Happy & Not Too Happy & Total \\\ \hline Male & 69 & 73 & 4 & \(\mathbf{1 4 6}\) \\ Female & 78 & 80 & 13 & \(\mathbf{1 7 1}\) \\ Total & \(\mathbf{1 4 7}\) & \(\mathbf{1 5 3}\) & \(\mathbf{1 7}\) & \(\mathbf{3 1 7}\) \\ \hline \end{tabular} a. Estimate the probability that an adult is very happy in his or her romantic relationship. b. Estimate the probability that an adult is very happy (i) given that he is male and (ii) given that she is female. c. For these subjects, are the events being very happy and being a male independent? (Your answer will apply merely to this sample. Chapter 11 will show how to answer this for the population of all adults.)

Short Answer

Expert verified
a: 147/317. b(i): 69/146, b(ii): 78/171. c: No, they are not independent.

Step by step solution

01

Total Probability of Being Very Happy

To find the probability that an adult is very happy in their relationship, divide the total number of very happy adults by the total number of adults surveyed. Using the table, the number of very happy adults is 147 and the total is 317:\[P(\text{Very Happy}) = \frac{147}{317}\]
02

Probability of Being Very Happy Given Male

To find the probability that an adult is very happy given that they are male, divide the number of very happy males by the total number of males. According to the table, there are 69 very happy males out of 146 males:\[P(\text{Very Happy | Male}) = \frac{69}{146}\]
03

Probability of Being Very Happy Given Female

To find the probability that an adult is very happy given that they are female, divide the number of very happy females by the total number of females. The table shows 78 very happy females out of 171 females:\[P(\text{Very Happy | Female}) = \frac{78}{171}\]
04

Test for Independence Between Very Happy and Male

Two events are independent if the probability of both events happening is the product of their individual probabilities. In this case:1. Find \(P(\text{Male})\) which is \(\frac{146}{317}\).2. Check if \(P(\text{Very Happy | Male})\) equals \(P(\text{Very Happy})\) since a mismatch would show dependence:\[P(\text{Very Happy}) = \frac{147}{317} eq \frac{69}{146} = P(\text{Very Happy | Male})\]Since these are not equal, being very happy and being male are not independent in this sample.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Independence in Statistics
Statistical independence is a fundamental concept that helps us understand the relationship between two events. When two events are independent, it means that the occurrence of one event has no influence on the occurrence of the other event. In practical terms, if you roll a die and flip a coin, the outcome of your die roll does not affect the outcome of your coin flip—that's independence.
To test for independence between two events, we often use probabilities. If the probability of two events occurring together is the product of their individual probabilities, the events are independent. For example, if you want to check whether being very happy and being male are independent, you'd compare the probability of a male being very happy with the general probability of someone being very happy. If these probabilities are equal, independence is indicated.
In the General Social Survey exercise, we compared these probabilities and found they were not equal, suggesting that the happiness of males in relationships is not independent of being male in this specific sample.
Conditional Probability
Conditional probability gives us a way to calculate the probability of an event occurring, given that another event has already occurred. It's like saying, "Given what's already happened, how likely is it that this outcome happens next?"
For example, in the happiness survey from the General Social Survey, we calculated conditional probabilities to determine how likely it is for someone to be very happy, once we already know they are either male or female. This helps us understand how specific conditions might affect the outcome.
Mathematically, conditional probability is represented as \( P(A|B) = \frac{P(A \cap B)}{P(B)} \), where \( P(A|B) \) is the probability of A happening given that B has happened. The exercise asked us to find probabilities like \( P(\text{Very Happy | Male}) \) and \( P(\text{Very Happy | Female}) \) by focusing on specific subsets of the population. This method offers deeper insights than just looking at overall probabilities.
General Social Survey Statistics
The General Social Survey (GSS) is a pivotal tool for gathering data on the complex dynamics of social relationships and attitudes in society. Conducted with adults across the United States, it provides valuable information on various domains, including personal happiness in relationships, as was the focus in the exercise.
The data from GSS is typically large-scale and representative, aiming to reflect the viewpoints of a diverse population. When analyzing such datasets, it becomes crucial to utilize statistical tools like probabilities and conditional probabilities to derive meaningful insights from the numbers.
Using the GSS data from 2012, as in our example, we learned about happiness patterns by gender in romantic relationships. Through these statistics, researchers can uncover trends and relationships between different social factors, allowing them to make informed social policy recommendations or conduct further research.

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Most popular questions from this chapter

Religious affiliation The 2012 Statistical Abstract of the United States \(^{3}\) provides information on individuals' self-described religious affiliations. The information for 2008 is summarized in the following table (all numbers are in thousands). \begin{tabular}{lr} \hline Christian & \\ Catholic & 57,199 \\ Baptist & 36,148 \\ Christian (no denomination specified) & 16,834 \\ Methodist/Wesleyan & 11,366 \\ Other Christian & 51,855 \\ Jewish & 2,680 \\ Muslim & 1,349 \\ Buddhist & 1,189 \\ Other non-Christian & 3,578 \\ No Religion & 34,169 \\ Refused to Answer & 11,815 \\ Total Adult Population in 2008 & 228,182 \\ \hline \end{tabular} a. Find the probability that a randomly selected individual is identified as Christian. b. Given that an individual identifies as Christian, find the probability that the person is Catholic. c. Given that an individual answered, find the probability the individual is identified as following no religion.

DNA evidence can be extracted from biological traces such as blood, hair, and saliva. "DNA fingerprinting" is increasingly used in the courtroom as well as in paternity testing. Given that a person is innocent, suppose that the probability of his or her DNA matching that found at the crime scene is only \(0.000001,\) one in a million. Further, given that a person is guilty, suppose that the probability of his or her DNA matching that found at the crime scene is \(0.99 .\) Jane Doe's DNA matches that found at the crime scene. a. Find the probability that Jane Doe is actually innocent, if absolutely her probability of innocence is 0.50. Interpret this probability. Show your solution by introducing notation for events, specifying probabilities that are given, and using a tree diagram to find your answer. b. Repeat part a if the unconditional probability of innocence is \(0.99 .\) Compare results. c. Explain why it is very important for a defense lawyer to explain the difference between \(\mathrm{P}\) (DNA match person innocent) and \(\mathrm{P}\) (person innocent \(\mid\) DNA match).

The all-time, on-time arrival rate of a certain airline to a specific destination is \(82 \%\). This week, you have booked two flights to this destination with this airline. a. Construct a sample space for the on-time or late arrival of the two flights. b. Find the probability that both the flights arrive on time. c. Find the probability that both the flights are late.

Every year the insurance industry spends considerable resources assessing risk probabilities. To accumulate a risk of about one in a million of death, you can drive 100 miles, take a cross country plane flight, work as a police officer for 10 hours, work in a coal mine for 12 hours, smoke two cigarettes, be a nonsmoker but live with a smoker for two weeks, or drink 70 pints of beer in a year (Wilson and Crouch, \(2001,\) pp. \(208-209)\). Show that a risk of about one in a million of death is also approximately the probability of flipping 20 heads in a row with a balanced coin.

In the opening scene of Tom Stoppard's play Rosencrantz and Guildenstern Are Dead, about two Elizabethan contemporaries of Hamlet, Guildenstern flips a coin 91 times and gets a head each time. Suppose the coin was balanced. a. Specify the sample space for 91 coin flips, such that each outcome in the sample space is equally likely. How many outcomes are in the sample space? b. Show Guildenstern's outcome for this sample space. Show the outcome in which only the second flip is a tail. c. What's the probability of the event of getting a head 91 times in a row? d. What's the probability of at least one tail in the 91 flips? e. State the probability model on which your solutions in parts \(\mathrm{c}\) and \(\mathrm{d}\) are based.

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