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The formula used to calculate a large-sample confidence interval for \(p\) is $$ \hat{p} \pm(z \text { critical value }) \sqrt{\frac{\hat{p}(1-\hat{p})}{n}} $$ What is the appropriate \(z\) critical value for each of the following confidence levels? a. \(90 \%\) b. \(99 \%\) c. \(80 \%\)

Short Answer

Expert verified
The appropriate \(z\) critical values for each confidence level are: a. \(90\% \rightarrow 1.645\) b. \(99\% \rightarrow 2.576\) c. \(80\% \rightarrow 1.28\)

Step by step solution

01

Recall the standard normal distribution and the concept of the critical value

A standard normal distribution is a normal distribution with a mean of 0 and a standard deviation of 1. A \(z\) critical value corresponds to the number of standard deviations away from the mean that defines a particular confidence level or probability.
02

Use a Z-table or calculator to find the z critical value

A Z-table or a calculator with the standard normal distribution function can be used to find the \(z\) critical value for a particular confidence level. In this exercise, we need to find the \(z\) critical value for the following confidence levels: a. \(90\%\) b. \(99\%\) c. \(80\%\) To find the \(z\) critical value for each confidence level, first find the area (probability) that corresponds to each confidence level, and then use the Z-table or calculator to find the corresponding \(z\) value.
03

Find the z critical value for a 90% confidence level

For a \(90\%\) confidence level, there will be a \(10\%\) difference in the probability between the confidence interval and \(100\%\). This \(10\%\) needs to be split equally on both tails, so we have \(5\%\) on each tail. This means we need to find the \(z\) value associated with a \(95\%\) probability (since \(90\% + 5\% = 95\%\)). Using a Z-table or calculator, we can find the \(z\) critical value for a \(95\%\) probability to be approximately \(1.645\). So, the \(z\) critical value for a \(90\%\) confidence level is \(1.645\).
04

Find the z critical value for a 99% confidence level

For a \(99\%\) confidence level, there will be a \(1\%\) difference in the probability between the confidence interval and \(100\%\). This \(1\%\) needs to be split equally on both tails, so we have \(0.5\%\) on each tail. This means we need to find the \(z\) value associated with a \(99.5\%\) probability (since \(99\% + 0.5\% = 99.5\%\)). Using a Z-table or calculator, we can find the \(z\) critical value for a \(99.5\%\) probability to be approximately \(2.576\). So, the \(z\) critical value for a \(99\%\) confidence level is \(2.576\).
05

Find the z critical value for an 80% confidence level

For an \(80\%\) confidence level, there will be a \(20\%\) difference in the probability between the confidence interval and \(100\%\). This \(20\%\) needs to be split equally on both tails, so we have \(10\%\) on each tail. This means we need to find the \(z\) value associated with a \(90\%\) probability (since \(80\% + 10\% = 90\%\)). Using a Z-table or calculator, we can find the \(z\) critical value for a \(90\%\) probability to be approximately \(1.28\). So, the \(z\) critical value for an \(80\%\) confidence level is \(1.28\). Now, we have found the \(z\) critical values for each of the given confidence levels: a. \(90\% \rightarrow 1.645\) b. \(99\% \rightarrow 2.576\) c. \(80\% \rightarrow 1.28\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Z Critical Value
Understanding the concept of the z critical value is essential for conducting statistical tests and creating confidence intervals. This value represents the point on a standard normal distribution curve beyond which a specified percentage of the data falls.

For example, when we talk about a 90% confidence level, we are focused on the central 90% of the curve, leaving 5% in each tail. The z critical value for this area would be the number revealing how many standard deviations you'd need to be from the mean to encompass that 90% in the middle of the distribution. Concretely, we consider the value of 1.645 for a 90% confidence interval which means that 1.645 standard deviations from the mean will give us our desired level of confidence.

To find the z critical value, a Z-table or statistical software can be used. The table correlates the area under the curve with the number of standard deviations from the mean, hence giving us the z score. It is critical to understand that this z score can then be used to determine the margin of error when estimating population parameters.
Standard Normal Distribution
The standard normal distribution is a fundamental concept in statistics that applies to various statistical analyses, including the calculation of confidence intervals. It represents a normal distribution with a mean of 0 and a standard deviation of 1. This standardized form allows us to compare different data sets and use statistical tables such as the Z-table.

The standard normal distribution is often illustrated as a bell curve where most of the data points cluster around the mean, less so further away. Every point on the curve can be translated into a z score, indicating how many standard deviations away from the mean a data point is. The Z-table mentioned previously is derived from this distribution and enables us to find probabilities and z critical values for specific confidence levels.
Confidence Level
The confidence level is another key concept in statistics that complements the understanding of z critical values and standard normal distribution. It represents how certain we are that the true parameter (like a population mean or proportion) falls within the calculated confidence interval. It is expressed as a percentage, such as 90%, 95%, or 99%.

When we calculate the confidence interval for a sample statistic, the confidence level tells us how reliable our estimate is. For instance, a 95% confidence level implies that if we were to take 100 random samples and compute confidence intervals for each, we would expect about 95 of those intervals to contain the true population parameter.

Choosing a confidence level impacts the width of the confidence interval. Higher confidence levels produce wider intervals and vice versa. Ultimately, the choice of confidence level hinges on how precise we need our estimate to be and how much uncertainty we can tolerate.

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Most popular questions from this chapter

Use the formula for the standard error of \(\hat{p}\) to explain why a. the standard error is greater when the value of the population proportion \(p\) is near 0.5 than when it is near 1 . b. the standard error of \(\hat{p}\) is the same when the value of the population proportion is \(p=0.2\) as it is when \(p=0.8\).

Suppose that a city planning commission wants to know the proportion of city residents who support installing streetlights in the downtown area. Two different people independently selected random samples of city residents and used their sample data to construct the following confidence intervals for the population proportion: Interval 1:(0.28,0.34) Interval 2:(0.31,0.33) (Hint: Consider the formula for the confidence interval given on page 444.) a. Explain how it is possible that the two confidence intervals are not centered in the same place. b. Which of the two intervals conveys more precise information about the value of the population proportion? c. If both confidence intervals have a \(95 \%\) confidence level, which confidence interval was based on the smaller sample size? How can you tell? d. If both confidence intervals were based on the same sample size, which interval has the higher confidence level? How can you tell?

The report referenced in the previous exercise also indicated that \(33 \%\) of those in a representative sample of 533 homeowners in southern states said that they had considered installing solar panels. a. Use the given information to construct and interpret a \(90 \%\) confidence interval for the proportion of all homeowners in the southern states who have considered installing solar panels. b. Give two reasons why the confidence interval in Part (a) is narrower than the confidence interval calculated in the previous exercise.

The article "Career Expert Provides DOs and DON'Ts for Job Seekers on Social Networking" (CareerBuilder.com, August 19,2009 ) included data from a survey of 2667 hiring managers and human resource professionals. The article noted that more employers are now using social networks to screen job applicants. Of the 2667 people who participated in the survey, 1200 indicated that they use social networking sites such as Facebook, MySpace, and LinkedIn to research job applicants. Assume that the sample is representative of hiring managers and human resource professionals. Answer the four key questions (QSTN) to confirm that the suggested method in this situation is a confidence interval for a population proportion.

Consider taking a random sample from a population with \(p=0.70\) a. What is the standard error of \(\hat{p}\) for random samples of size \(100 ?\) b. Would the standard error of \(\hat{p}\) be smaller for samples of size 100 or samples of size \(400 ?\) c. Does decreasing the sample size by a factor of \(4,\) from 400 to \(100,\) result in a standard error of \(\hat{p}\) that is four times as large?

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