/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 14 Suppose \(x=\) the number of cou... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Suppose \(x=\) the number of courses a randomly selected student at a certain university is taking. The probability distribution of \(x\) appears in the following table: $$\begin{array}{llllllll}x & 1 & 2 & 3 & 4 & 5 & 6 & 7\end{array}\( \)\begin{array}{llllllll}p(x) & 0.02 & 0.03 & 0.09 & 0.25 & 0.40 & 0.16 & 0.05\end{array}$$ a. What is \(P(x=4)\) ? b. What is \(P(x \leq 4) ?\) c. What is the probability that the selected student is taking at most five courses? d. What is the probability that the selected student is taking at least five courses? More than five courses? e. Calculate \(P(3 \leq x \leq 6)\) and \(P(3

Short Answer

Expert verified
a. \(P(x=4) = 0.25\) b. \(P(x \leq 4) = 0.39\) c. \(P(x \leq 5) = 0.79\) d. \(P(x \geq 5) = 0.61\), \(P(x > 5) = 0.21\) e. \(P(3 \leq x \leq 6) = 0.90\), \(P(3 < x < 6) = 0.65\). These probabilities are different because they represent different intervals of the probability distribution, with the first interval including the probabilities for \(x=3\) and \(x=6\) and the second interval excluding them.

Step by step solution

01

Identify the probability corresponding to \(x=4\) in the table

To find the probability \(P(x=4)\), we look at the given table of probabilities for each possible value of \(x\). The value of \(x=4\) corresponds to a probability of \(0.25\). So, \(P(x=4) = 0.25\). #b. What is \(P(x \leq 4)?\)#
02

Calculate the cumulative probability for \(x \leq 4\)

To find the probability \(P(x \leq 4)\), we sum the probabilities of all values of \(x\) less than or equal to 4. From the table, this includes the probabilities for \(x=1, 2, 3\), and \(4\): $$P(x \leq 4) = P(x=1) + P(x=2) + P(x=3) + P(x=4) = 0.02 + 0.03 + 0.09 + 0.25 = 0.39$$ #c. What is the probability that the selected student is taking at most five courses?#
03

Calculate the cumulative probability for \(x \leq 5\)

To find the probability that the selected student is taking at most five courses, we need to calculate \(P(x \leq 5)\). We will sum the probabilities of all values of \(x\) less than or equal to 5: $$P(x \leq 5) = P(x=1) + P(x=2) + P(x=3) + P(x=4) + P(x=5) = 0.02 + 0.03 + 0.09 + 0.25 + 0.40 = 0.79$$ #d. What is the probability that the selected student is taking at least five courses? More than five courses?#
04

Calculate the probability of \(x \geq 5\) and \(x > 5\)

To find the probability that the selected student is taking at least five courses, we need to calculate \(P(x \geq 5) = P(x=5) + P(x=6) + P(x=7)\), which can be found by summing the probabilities of all values of \(x\) greater than or equal to 5: $$P(x \geq 5) = 0.40 + 0.16 + 0.05 = 0.61$$ To find the probability that the selected student is taking more than five courses, we need to calculate \(P(x > 5) = P(x=6) + P(x=7)\), summing the probabilities of all values of \(x\) greater than 5: $$P(x > 5) = 0.16 + 0.05 = 0.21$$ #e. Calculate \(P(3 \leq x \leq 6)\) and \(P(3<x<6)\). Explain in words why these two probabilities are different.#
05

Calculate the probabilities for \(3 \leq x \leq 6\) and \(3 < x < 6\)

We need to calculate the probabilities for the intervals \(3 \leq x \leq 6\) and \(3 < x < 6\). For \(3 \leq x \leq 6\), we calculate the sum of probabilities for the values of \(x\) between 3 and 6, inclusive: $$P(3 \leq x \leq 6) = P(x=3) + P(x=4) + P(x=5) + P(x=6) = 0.09 + 0.25 + 0.40 + 0.16 = 0.90$$ For \(3 < x < 6\), we calculate the sum of probabilities for the values of \(x\) between 3 and 6, exclusive: $$P(3 < x < 6) = P(x=4) + P(x=5) = 0.25 + 0.40 = 0.65$$
06

Explain why the probabilities are different

The probabilities for \(P(3 \leq x \leq 6)\) and \(P(3<x<6)\) are different because they represent two different intervals of the probability distribution. The interval \(3 \leq x \leq 6\) includes the probabilities for \(x=3\), \(x=4\), \(x=5\), and \(x=6\), while the interval \(3 < x < 6\) only includes the probabilities for \(x=4\) and \(x=5\). Since the first interval includes the probabilities for \(x=3\) and \(x=6\), its overall probability is higher than the probability of the second interval.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Cumulative Probability
Cumulative probability represents the likelihood that a random variable falls within a certain range up to a specified value. It's akin to adding up all the probabilities for a random variable up to that point. This concept is essential when trying to understand events that have multiple possible outcomes.

For example, if we have a random variable that describes the number of courses a student takes, and we want to know the probability of a student taking up to four courses, we would sum the probabilities of taking 1, 2, 3, and 4 courses. In mathematical terms, if we denote our random variable as 'X', the cumulative probability for 4 courses is denoted as P(X ≤ 4).

The calculation of cumulative probability can help in making informed decisions based on the overall likelihood of an event occurring within a range, rather than individual probabilities. Moreover, it serves as the foundation for cumulative distribution functions (CDFs), which play a crucial role in statistics for summarizing data and making predictions.
Random Variable
A random variable is a numerical description of the outcome of a statistical experiment. It assigns numerical values to the possible outcomes of a random phenomenon, such as the roll of a die or the number of courses a student might take. Random variables can be discrete or continuous, depending on whether they can take on a finite (or countably infinite) number of values or an uncountable range of values.

In the context of our example, the random variable 'X' represents the number of courses a student is taking. Each possible number of courses correlates with a probability P(X = x) where 'x' can be any of the possible quantity of courses. Understanding random variables is key to grasping more complex statistical concepts because they form the core of probability theory, allowing for the quantification of random events.
Probability Interval
A probability interval is a range of values within which a random variable is likely to fall. It can either include or exclude the endpoint values, i.e., it can be closed or open. Closed intervals include the endpoints, specified using the ≤ or ≥ symbols, whereas open intervals exclude the endpoints and are denoted with < or > symbols.

When asked for the probability within a certain interval, say P(3 ≤ X ≤ 6), you include the probabilities of X being 3, 4, 5, and 6. On the contrary, for P(3 < X < 6), the probabilities for X being 3 and 6 are not included, which can lead to a different cumulative probability compared to the closed interval.

Understanding probability intervals is fundamental when dealing with real-life scenarios where exact values are often not as crucial as the range within which the values fall. In risk assessment, for example, knowing that an adverse event has a high probability of occurring within a certain range is often more practical than knowing the precise probability of any given outcome.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Classify each of the following random variables as either discrete or continuous: a. The fuel efficiency (miles per gallon) of an automobile b. The amount of rainfall at a particular location during the next year c. The distance that a person throws a baseball d. The number of questions asked during a 1-hour lecture e. The tension (in pounds per square inch) at which a tennis racket is strung f. The amount of water used by a household during a given month g. The number of traffic citations issued by the highway patrol in a particular county on a given day

A pizza company advertises that it puts 0.5 pound of real mozzarella cheese on its medium-sized pizzas. In fact, the amount of cheese on a randomly selected medium pizza is normally distributed with a mean value of 0.5 pound and a standard deviation of 0.025 pound. a. What is the probability that the amount of cheese on a medium pizza is between 0.525 and 0.550 pounds? b. What is the probability that the amount of cheese on a medium pizza exceeds the mean value by more than 2 standard deviations? c. What is the probability that three randomly selected medium pizzas each have at least 0.475 pounds of cheese?

The paper "Examining Communication- and Media Based Recreational Sedentary Behaviors Among Canadian Youth: Results from the COMPASS Study" (Preventive Medicine \([2015]: 74-80)\) estimated that the time spent playing video or computer games by high school boys had a mean of 123.4 minutes per day and a standard deviation of 117.1 minutes per day. Based on this mean and standard deviation, explain why it is not reasonable to think that the distribution of the random variable \(x=\) time spent playing video or computer games is approximately normal.

You are to take a multiple-choice exam consisting of 100 questions with five possible responses to each question. Suppose that you have not studied and so must guess (randomly select one of the five answers) on each question. Let \(x\) represent the number of correct responses on the test. a. What kind of probability distribution does \(x\) have? b. What is your expected score on the exam? (Hint: Your expected score is the mean value of the \(x\) distribution.) c. Calculate the variance and standard deviation of \(x\). d. Based on your answers to Parts \((\mathrm{b})\) and \((\mathrm{c}),\) is it likely that you would score over 50 on this exam? Explain the reasoning behind your answer.

6.80 Information Security Buzz provides news for the information security community. In an article published on September \(24,2016,\) it reported that based on a large international survey of Internet users, \(60 \%\) of Internet users have installed security solutions on all of the devices they use to access the Internet. a. Suppose that the true proportion of Internet users who have security solutions on all of the devices they use to access the Internet is 0.60 . If 20 Internet users are selected at random, what is the probability that more than 10 have security solutions installed on all devices used to access the Internet? b. Suppose that a random sample of Internet users is selected. Which is more likely-that more than 15 have security solutions on all devices used to access the Internet or that fewer than 5 have security solutions on all devices used to access the Internet? Justify your answer based on probability calculations.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.