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A restaurant has four bottles of a certain wine in stock. The wine steward does not know that two of these bottles (Bottles 1 and 2 ) are bad. Suppose that two bottles are ordered, and the wine steward selects two of the four bottles at random. Consider the random variable \(x=\) the number of good bottles among these two. a. When two bottles are selected at random, one possible outcome is (1,2) (Bottles 1 and 2 are selected) and another is (2,4). List all possible outcomes. b. What is the probability of each outcome in Part (a)? c. The value of \(x\) for the (1,2) outcome is 0 (neither selected bottle is good), and \(x=1\) for the outcome (2,4) . Determine the \(x\) value for each possible outcome. Then use the probabilities in Part (b) to determine the probability distribution of \(x\). (Hint: See Example \(6.5 .)\)

Short Answer

Expert verified
The sample space for selecting two bottles out of four is S = {(1,2), (1,3), (1,4), (2,3), (2,4), (3,4)}. The probabilities for each outcome are P(1,2) = P(1,3) = P(1,4) = P(2,3) = P(2,4) = P(3,4) = 1/6. The x values for these outcomes are x=0 for (1,2), x=1 for (1,3), (1,4), (2,3), and (2,4), and x=2 for (3,4). The probability distribution of x is P(x=0) = 1/6, P(x=1) = 2/3, and P(x=2) = 1/6.

Step by step solution

01

Identify all possible outcomes when selecting two out of four bottles

The sample space for selecting two bottles out of four can be defined as follows: S = {(1,2), (1,3), (1,4), (2,3), (2,4), (3,4)}
02

Calculate the probability of each outcome

Since there are a total of six possible outcomes when selecting two out of the four bottles, and we assume each outcome has an equal chance of occurring, the probability of each outcome is: P(1,2) = P(1,3) = P(1,4) = P(2,3) = P(2,4) = P(3,4) = 1/6
03

Determine the x value for each possible outcome using the information given

The possible x values can be calculated as follows: Outcome (1,2): x=0, since both bottles are bad. Outcome (1,3): x=1, because Bottle 1 is bad and Bottle 3 is good. Outcome (1,4): x=1, because Bottle 1 is bad and Bottle 4 is good. Outcome (2,3): x=1, because Bottle 2 is bad and Bottle 3 is good. Outcome (2,4): x=1, as given in the exercise. Outcome (3,4): x=2, because both bottles are good.
04

Determine the probability distribution of x

Now we will combine the probabilities calculated in Step 2 with the x values determined in Step 3: - x = 0: P(x=0) = P(1,2) = 1/6 - x = 1: P(x=1) = P(1,3) + P(1,4) + P(2,3) + P(2,4) = 4/6 = 2/3 - x = 2: P(x=2) = P(3,4) = 1/6 The probability distribution of the random variable x is as follows: - P(x=0) = 1/6 - P(x=1) = 2/3 - P(x=2) = 1/6

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Random Variables
Random variables are foundational elements in statistics and probability theory. They are not variables in the algebraic sense but rather functions that assign a numerical value to each outcome in a sample space. For example, consider the scenario where a wine steward selects two out of four bottles, unaware that two are bad. Here, we define a random variable, denoted as \(x\), representing the number of good bottles selected.

Crucially, random variables can be discrete or continuous. In our case, \(x\) is a discrete random variable since it can only take a finite number of values (0, 1, or 2). To ensure understanding: if there were a continuum of possible outcomes, for instance, the exact volume of wine in a bottle, we would be dealing with a continuous random variable.

In general, a random variable allows us to quantify outcomes and subsequently assess probabilities for these numeric values, which is precisely what we aim for when creating a probability distribution.
Sample Space
The sample space is a term in probability theory that refers to the set of all possible outcomes of a random experiment. Now, imagine the restaurant's wine selection process. The sample space for our wine problem is denoted as \(S\) and consists of the pairs of bottles that can be selected: \(S = \{(1,2), (1,3), (1,4), (2,3), (2,4), (3,4)\}\).

In this scenario, the 'experiment' is the selection of two bottles, and the sample space represents all possible combinations of the four bottles. Understanding the sample space is crucial, as it sets the stage for calculating probabilities. Remember that each outcome within this space should be unique, and the collective set should cover every single conceivable outcome, ensuring that the probabilities sum up to 1.
Probability Theory
Probability theory is the mathematical framework for quantifying uncertainty. The theory allows us to assign a probability—a value between 0 and 1—to each outcome in a sample space. In our exercise, we ascribe equal probability to the selection of each bottle pair since each is equally likely to be chosen by the steward.

For our discrete random variable \(x\), a probability distribution depicts the probability of each possible value of \(x\). By calculating the probabilities of the respective outcomes and applying them to the values of \(x\), we formed this distribution: \(P(x=0) = 1/6\), \(P(x=1) = 2/3\), and \(P(x=2) = 1/6\).

A key takeaway from probability theory is that the sum of the probabilities in our distribution must equal 1, symbolizing the certainty that one of the possible outcomes will occur. This foundational concept supports decision making in the face of uncertainty, as seen in our restaurant scenario and beyond, in a myriad of real-world applications.

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