/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 2 An airline reports that for a pa... [FREE SOLUTION] | 91Ó°ÊÓ

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An airline reports that for a particular flight operating daily between Phoenix and Atlanta, the probability of an on-time arrival is 0.86. Give a relative frequency interpretation of this probability.

Short Answer

Expert verified
The relative frequency interpretation of the given probability 0.86 is that, on average, for every 50 flights operating daily between Phoenix and Atlanta, there will likely be 43 on-time arrivals.

Step by step solution

01

Define the probability

The probability of an on-time arrival for the flight is given as 0.86. This means that there is an 86% chance that the flight will arrive on time.
02

Convert the probability to a fraction

To convert the probability into a fraction, we can write 0.86 as a fraction over 100. This will give us the fraction \(\frac{86}{100}\).
03

Simplify the fraction (if possible)

We can simplify the fraction \(\frac{86}{100}\) by dividing both the numerator and the denominator by the greatest common divisor (which is 2 in this case): \(\frac{86}{100} = \frac{86\div2}{100\div2} = \frac{43}{50}\)
04

Interpret the relative frequency

The simplified fraction \(\frac{43}{50}\) represents the relative frequency of on-time arrivals for the flight. This interpretation means that, on average, for every 50 flights operating daily between Phoenix and Atlanta, there will likely be 43 on-time arrivals.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Relative Frequency Interpretation
Understanding the concept of relative frequency is essential when interpreting probabilities. When we say the probability of an event, such as a flight arriving on time, is 0.86, we are using the relative frequency interpretation of probability.

The relative frequency interpretation relates to the number of times an event occurs compared to the total number of trials. If we consider a large number of flights, the probability of 0.86 suggests that for every 100 flights we observe, approximately 86 of them are expected to arrive on time. It is important to note that this is an 'average' or an 'expectation' based on the probability value provided, and actual outcomes might vary.

This concept helps in making informed predictions about future events based on past occurrences. Students often find it easier to grasp probabilities when they can visualize them as the count of successes in a series of trials.
Probability as a Fraction
When dealing with probabilities, expressing them as fractions can be incredibly insightful. For example, the probability of the flight arriving on time is initially given as 0.86, a decimal. However, when we express this as a fraction, it becomes clearer how many out of a set number of trials result in the desired outcome.

In this instance, we convert the decimal to a fraction by considering the decimal as a part of 100. Thus, 0.86 becomes \(\frac{86}{100}\). This fraction represents the same idea as the decimal: out of 100 flights, we expect 86 to be on time. Using fractions can make it more tangible, especially when simplifying to the lowest terms to show the smallest possible 'group' that this probability might apply to.
Simplifying Fractions
Simplifying fractions is a valuable skill in mathematics, particularly in probability. It involves reducing a fraction to its simplest form, where the numerator and denominator have no common factors other than 1. To simplify the fraction \(\frac{86}{100}\), we find the greatest common divisor of both numbers, which is 2, and divide the numerator and denominator by this number.

After simplification, we get \(\frac{43}{50}\). This tells us that for every 50 occurrences (flights, in this context), we expect 43 successful outcomes (on-time arrivals). Students should note that simplifying fractions does not change the value of the probability; it only makes it easier to understand and often easier to work with in various probability problems.

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Most popular questions from this chapter

Six people hope to be selected as a contestant on a TV game show. Two of these people are younger than 25 years old. Two of these six will be chosen at random to be on the show. a. What is the sample space for the chance experiment of selecting two of these people at random? (Hint: You can think of the people as being labeled \(\mathrm{A}, \mathrm{B}, \mathrm{C}, \mathrm{D}, \mathrm{E},\) and \(\mathrm{F}\). One possible selection of two people is \(\mathrm{A}\) and \(\mathrm{B}\). There are 14 other possible selections to consider.) b. Are the outcomes in the sample space equally likely? c. What is the probability that both the chosen contestants are younger than \(25 ?\) d. What is the probability that both the chosen contestants are not younger than \(25 ?\) e. What is the probability that one is younger than 25 and the other is not?

The same issue of The Chronicle for Higher Education Almanac referenced in the previous exercise also reported the following information for Ph.D. degrees awarded by U.S. colleges in the 2013-2014 academic year: \- A total of 54,070 Ph.D. degrees were awarded. \- 12,504 of these degrees were in the life sciences. \- 9859 of these degrees were in the physical sciences. \- The remaining degrees were in majors other than life or physical sciences. What is the probability that a randomly selected Ph.D. student who received a degree in \(2013-2014\) a. received an degree in the life sciences? b. received a degree that was not in a life or a physical science? c. did not receive a degree in the physical sciences?

Suppose that \(20 \%\) of all teenage drivers in a certain county received a citation for a moving violation within the past year. Assume in addition that \(80 \%\) of those receiving such a citation attended traffic school so that the citation would not appear on their permanent driving record. Consider the chance experiment that consists of randomly selecting a teenage driver from this county. a. One of the percentages given in the problem specifies an unconditional probability, and the other percentage specifies a conditional probability. Which one is the conditional probability, and how can you tell? b. Suppose that two events \(E\) and \(F\) are defined as follows: \(E=\) selected driver attended traffic school \(F=\) selected driver received such a citation Use probability notation to translate the given information into two probability statements of the form \(P(\underline{C})=\) probability value.

The probability of getting a king when a card is selected at random from a standard deck of 52 playing cards is \(\frac{1}{13}\). a. Give a relative frequency interpretation of this probability. b. Express the probability as a decimal rounded to three decimal places. Then complete the following statement: If a card is selected at random, I would expect to see a king about times in 1000 .

a. Suppose events \(E\) and \(F\) are mutually exclusive with \(P(E)=0.64\) and \(P(F)=0.17\) i. What is the value of \(P(E \cap F)\) ? ii. What is the value of \(P(E \cup F)\) ? b. Suppose that \(A\) and \(B\) are events with \(P(A)=0.3, P(B)=0.5\), and \(P(A \cap B)=0.15 .\) Are \(A\) and \(B\) mutually exclusive? How can you tell? c. Suppose that \(A\) and \(B\) are events with \(P(A)=0.65\) and \(P(B)=0.57 .\) Are \(A\) and \(B\) mutually exclusive? How can you tell?

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