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The article "Scrambled Statistics: What Are the Chances of Finding Multi-Yolk Eggs?" (Significance [August 2016]: 11) gives the probability of a double-yolk egg as 0.001 . a. Give a relative frequency interpretation of this probability. b. If 5000 eggs were randomly selected, about how many double-yolk eggs would you expect to find?

Short Answer

Expert verified
a. The relative frequency interpretation of the probability 0.001 is that in a large number of eggs, around 0.1% of them would be double-yolk eggs. b. In a sample of 5000 eggs, we would expect to find approximately 5 double-yolk eggs.

Step by step solution

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1. Relative frequency interpretation

The probability of a double-yolk egg is 0.001. In terms of relative frequency, this means that if we were to observe a large number of eggs, around 0.1% of them would be double-yolk eggs.
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2. Expected number of double-yolk eggs in a sample of 5000 eggs

To find the expected number of double-yolk eggs in a sample of 5000 eggs, we can simply multiply the probability of a double-yolk egg (0.001) by the total number of eggs in the sample (5000). Using the formula: Expected Number of Double-Yolk Eggs = Total Number of Eggs * Probability of Double-Yolk Egg \(ExpectedNumber = 5000 * 0.001\) Computing the expected number of double-yolk eggs will give us the result.
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3. Calculate the expected number of double-yolk eggs

Following the formula from the previous step, we can now calculate the expected number of double-yolk eggs in the sample: \(ExpectedNumber = 5000 * 0.001 = 5\) Therefore, in a sample of 5000 eggs, we would expect to find approximately 5 double-yolk eggs.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Relative Frequency
When we talk about probability, the concept of relative frequency offers a practical way of understanding it. It refers to the ratio of times an event occurs to the total number of trials or observations. This concept is particularly useful when probabilities are empirical, which means they are based on actual experiments or trials, rather than theoretical calculations.

For instance, if a box contains a thousand eggs, and the probability of any egg being double-yolked is 0.001, what the relative frequency interpretation tells us is that if we keep taking eggs from this metaphorical box, about 1 in 1000 should be double-yolked. As we increase the number of trials (observing more and more eggs), the relative frequency of finding double-yolk eggs should stabilize and approach the probability of 0.001. This is an inherent part of the Law of Large Numbers, a fundamental principle in probability that asserts that as the sample size grows, the relative frequency gets closer to the theoretical probability.
Expected Value
Expected value is a fundamental concept in probability that represents the average outcome if an experiment or process were repeated many times. It’s a form of long-term average. When we calculate expected value, we're essentially predicting what will happen over many iterations of a certain event, based on the probabilities of the possible outcomes.

In our exercise, the expected value can be interpreted as the average number of double-yolk eggs we'd encounter if we were to pick 5000 eggs. Given that the probability of finding a double-yolk egg is 0.001, the expected value is calculated by multiplying the probability by the total number of eggs, which results in an expectation of finding 5 double-yolk eggs in 5000.

It's crucial to understand that the expected value doesn't indicate that we will find exactly 5 double-yolk eggs every time we select 5000 eggs, but rather that 5 is the average number we would expect to find across many such groups of 5000 eggs.
Sample Size
Sample size is a statistical concept that plays a crucial role in experiments and surveys. It refers to the number of observations or replicates included in a statistical sample. The larger the sample size, the more accurate and reliable the results tend to be. This accuracy comes from the Law of Large Numbers, which, as mentioned earlier, suggests that with a larger number of trials, the actual results are more likely to reflect the true probability.

When taking a practical example from the exercise, we are dealing with a sample size of 5000 eggs. This is a fairly large sample, and it allows us to use the probability of 0.001 to calculate an expected value with a reasonable degree of accuracy. However, if the sample size were, say, 10 eggs, our expected value calculation would hardly be reliable. With such a small number, the variability in outcomes is far greater, and even with a theoretically accurate probability, the expected number of double-yolk eggs would not be a trustworthy predictor of the actual number of double-yolk eggs that you might find.

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Most popular questions from this chapter

Are people more confident in their answers when the answer is actually correct than when it is not? The article "Female Students Less Confident, More Accurate Than Male Counterparts" described a study that measured medical students" confidence and the accuracy of their responses. Participants categorized their confidence levels using either "sure," "feeling lucky," or "no clue" Define the following events: \(C=\) event that a response is conect \(S=\) event that confidence level is "sure" \(L=\) event that confidence level is "feeling lucky" \(N=\) event that confidence level is "no clue" a. Data from the article were used to estimate the following probabilities for males: $$ \begin{array}{rrr} P(S)=0.442 & P(L)=0.422 & P(N)=0.136 \\ P(C \mid S)=0.783 & P(C \mid L)=0.498 & P(C \mid N)=0.320 \end{array} $$ Use the given probabilities to construct a hypothetical 1000 table with rows corresponding to confidence level and columns comesponding to whether the response was correct or not. b. Calculate the probability that a male student's confidence level is "sure" given that the response is correct. c. Calculate the probability that a male student's confidence level is "no clue" given that the response is incorrect. d. Calculate the probability that a male student's response is correct. e. Data from the article were also used to estimate the following probabilities for females: $$ \begin{array}{rrr} P(S)=0.395 & P(L)=0.444 & P(N)=0.161 \\ P(C 1 S)=0.805 & P(C \mid L)=0.535 & P(C \mid N)=0.320 \end{array} $$ Use the given probabilities to construct a hypothetical 1000 table with rows corresponding to confidence level and columns corresponding to whether the response was comect or not. f. Calculate the probability that a female student's confidence level is "sure" given that the response is correct. g. Calculate the probability that a female student's confidence level is "no clue" given that the response is incorrect. h. Calculate the probability that a female student's response is correct. i. Do the given probabilities and the probabilities that you calculated support the statement in the title of the article? Explain.

The National Center for Health Statistics (www.cdc .gov/nchs/data/nvsr/nvsr64/nvsr64_12.pdf, retrieved April 25,2017 ) gave the following information on births in the United States in 2014 : $$ \begin{array}{|lr|} \hline \text { Type of Birth } & \text { Number of Births } \\ \hline \text { Single birth } & 3,848,214 \\ \text { Twins } & 135,336 \\ \text { Triplets } & 4,233 \\ \text { Quadruplets } & 246 \\ \text { Quintuplets or higher } & 47 \\ \hline \end{array} $$ Use this information to estimate the probability that a randomly selected pregnant woman who gave birth in 2014 a. delivered twins b. delivered quadruplets c. gave birth to more than a single child

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