/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 100 Herc's one to sink your teeth in... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Herc's one to sink your teeth into: The authors of the article "Analysis of Food Crushing Sounds During Mastication: Total Sound Level Studies" (Journal of Texture Studies [1990]: \(165-178\) ) studicd the nature of sounds generated during eating. Peak loudness was measured (in decibels at \(20 \mathrm{~cm}\) away \()\) for both open-mouth and closedmouth chewing of potato chips and of tortilla chips. A sample of size 10 was used for each of the four possible combinations (such as closed-mouth potato chip, and so on). We are not making this up! Summary values taken from plots given in the article appear in the accompanying table. For purposes of this exercise, suppose that it is reasonable to regard the peak loudness distributions as approximately normal. a. Construct a 95\% confidence interval for the difference in mean peak loudness between open-mouth and closedmouth chewing of potato chips. Be sure to interpret the resulting interval. b. For closed-mouth chewing (the recommended method!), construct a \(95 \%\) confidence interval for the difference in mean peak loudness between potato chips and tortilla chips.

Short Answer

Expert verified
The 95% confidence interval for the difference in mean peak loudness between open-mouth and closed-mouth potato chips is given by: \(CI_a = (\bar{X}_1 - \bar{X}_2) \pm 1.96 * \sqrt{\frac{{s_1}^2}{10} + \frac{{s_2}^2}{10}}\) If this interval contains 0, there is no significant difference in the mean peak loudness between the two chewing methods. The 95% confidence interval for the difference in mean peak loudness between closed-mouth potato chips and tortilla chips is given by: \(CI_b = (\bar{X}_2 - \bar{X}_3) \pm 1.96 * \sqrt{\frac{{s_2}^2}{10} + \frac{{s_3}^2}{10}}\) If this interval contains 0, there is no significant difference in the mean peak loudness between the two types of chips during closed-mouth chewing.

Step by step solution

01

Identify the data

From the exercise, we are given the following summary values (sample size = 10): Open-mouth potato chips: - Mean peak loudness: \(\bar{X}_1\) - Sample variance: \(s_1^2\) Closed-mouth potato chips: - Mean peak loudness: \(\bar{X}_2\) - Sample variance: \(s_2^2\) Closed-mouth tortilla chips: - Mean peak loudness: \(\bar{X}_3\) - Sample variance: \(s_3^2\) For a 95% confidence level, the z-score would be 1.96.
02

Construct the confidence interval for open-mouth and closed-mouth potato chips

Using the given data, we will calculate the 95% confidence interval for the difference in mean peak loudness between open-mouth and closed-mouth potato chips using the formula: \(CI_a = (\bar{X}_1 - \bar{X}_2) \pm 1.96 * \sqrt{\frac{{s_1}^2}{10} + \frac{{s_2}^2}{10}}\)
03

Interpret the confidence interval

The 95% confidence interval calculated in step 2 gives us a range within which we are 95% confident the true difference in mean peak loudness between open-mouth and closed-mouth potato chips lies. If the interval contains 0, it implies that there is no significant difference in the mean peak loudness between the two chewing methods.
04

Construct the confidence interval for closed-mouth potato chips and tortilla chips

Using the given data, we will calculate the 95% confidence interval for the difference in mean peak loudness between closed-mouth potato chips and tortilla chips using the formula: \(CI_b = (\bar{X}_2 - \bar{X}_3) \pm 1.96 * \sqrt{\frac{{s_2}^2}{10} + \frac{{s_3}^2}{10}}\)
05

Interpret the confidence interval

The 95% confidence interval calculated in step 4 gives us a range within which we are 95% confident the true difference in mean peak loudness between closed-mouth potato chips and tortilla chips lies. If the interval contains 0, it implies that there is no significant difference in the mean peak loudness between the two types of chips during closed-mouth chewing.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mean Peak Loudness
Mean peak loudness refers to the highest sound level recorded during a specific activity. In this exercise, we are studying the sounds made while chewing different types of chips. When more than one trial is performed, a mean of the peak loudness values is calculated. This mean gives us a sense of the central tendency, or the typical loudness, during those chewing scenarios.

Understanding mean peak loudness is crucial because it helps to summarize the data into a single value for each condition. This allows for easy comparison between the four different combinations of chewing styles and chip types in the exercise. With mean values available, we can start constructing confidence intervals that guide our understanding of the variability of these sounds in different scenarios.

In statistical analyses, particularly when assessing differences between groups, the mean peak loudness acts as the starting point. It enables us to infer conclusions about the population while only using a sample.
Normal Distribution
A normal distribution is a bell-shaped curve that is symmetrical around the mean. In the context of sound studies like this, it means assuming the peak loudness follows this specific pattern. This assumption is critical because many statistical methods, including calculating confidence intervals, rely on data being normally distributed.

Given its properties, a normal distribution helps to make predictions about the data. For example, it suggests that most data points will cluster around the mean, with fewer occurrences as one moves farther from the mean. The tails of the distribution represent rarer events, like exceptionally quiet or loud sounds during chewing.

When data is approximately normal, like in this exercise, it validates the use of certain calculations. For instance, computing confidence intervals becomes more straightforward because the distribution provides a built-in framework to determine variability. This helps to ensure that our intervals are accurate and meaningful when comparing different sound patterns, like those observed in open-mouth versus closed-mouth chewing.
Sample Variance
Sample variance is a measure that tells us how much the data points in a sample spread out from the mean. In this exercise, calculating sample variance lets us understand how consistent the sound levels are during the different chewing conditions. A higher variance indicates more variation in peak loudness from one chew to the next.

Variance is computed as the average of the squared differences from the mean. This means that each individual measurement is compared to the mean, and these differences are squared and averaged. The squaring nullifies the effects of negative differences, ensuring all deviations are treated equally.

In the context of constructing confidence intervals, sample variance plays a key role. It allows us to determine how precise our estimate of the mean is likely to be by directly influencing the margin of error. When variance is lower, our estimates of the mean peak loudness are likely more accurate, leading to tighter confidence intervals. Conversely, higher variance results in wider intervals, indicating more uncertainty about the mean.

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Most popular questions from this chapter

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