/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 23 Students in a representative sam... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Students in a representative sample of 65 first-year students selected from a large university in England participated in a study of academic procrastination ("Study Goals and Procrastination Tendencies at Different Stages of the Undergraduate Degree," Studies in Higher Education [2016]: 2028-2043). Each student in the sample completed the Tuckman Procrastination Scale, which measures procrastination tendencies. Scores on this scale can range from 16 to \(64,\) with scores over 40 indicating higher levels of procrastination. For the 65 first-year students in this study, the mean score on the procrastination scale was 37.02 and the standard deviation was 6.44 . a. Construct a \(95 \%\) confidence interval estimate of \(\mu,\) the mean procrastination scale for first-year students at this college. (Hint: See Example 12.7.) b. Based on your interval, is 40 a plausible value for the population mean score? What does this imply about the population of first-year students?

Short Answer

Expert verified
The 95% confidence interval for the mean procrastination score of first-year students at this university is approximately (35.45, 38.59). Since the value 40 is not within this interval, it is not a plausible value for the population mean score. This implies that, on average, first-year students at this college have a lower level of procrastination than the threshold for higher levels of procrastination (40), indicating that the majority of first-year students may not be categorized as having higher levels of procrastination based on the Tuckman Procrastination Scale.

Step by step solution

01

Identify the given information

We are given the following information: - Sample size (n) = 65 - Sample mean (\(\bar{x}\)) = 37.02 - Sample standard deviation (s) = 6.44 - Confidence level = 95%
02

Find the critical value (t) for a 95% confidence interval

In order to construct the confidence interval, we need to find the critical value corresponding to the given confidence level. We will use the t-distribution, since the population standard deviation is unknown. The t-distribution has n-1 degrees of freedom. In this case, we have 65 - 1 = 64 degrees of freedom. To find the critical t-value, we will use a t-table or a calculator that can compute the inverse t-distribution. For a 95% confidence interval with 64 degrees of freedom, the critical t-value (t) is approximately 1.999.
03

Calculate the margin of error

To calculate the margin of error, we will use the following formula: Margin of error = t × (s / √n) Substitute the values to get: Margin of error = 1.999 × (6.44 / √65) Margin of error ≈ 1.569
04

Construct the 95% confidence interval

To construct the confidence interval, we will add and subtract the margin of error from the sample mean: Lower limit = \(\bar{x}\) - Margin of error = 37.02 - 1.569 ≈ 35.45 Upper limit = \(\bar{x}\) + Margin of error = 37.02 + 1.569 ≈ 38.59 So, the 95% confidence interval for the population mean is (35.45, 38.59).
05

Determine if 40 is a plausible value for the population mean

To determine if 40 is a plausible value for the population mean, we need to check if it lies within the calculated confidence interval. Since 40 is outside the interval (35.45, 38.59), it is not considered a plausible value for the population mean.
06

Discuss the implications for the population of first-year students

Since 40 is not a plausible value for the population mean, we can conclude that, on average, first-year students at this college have a lower level of procrastination than the threshold for higher levels of procrastination (40). It indicates that the majority of first-year students may not be categorized as having higher levels of procrastination based on the Tuckman Procrastination Scale.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Tuckman Procrastination Scale
The Tuckman Procrastination Scale is a psychological assessment tool designed to measure an individual's tendency to procrastinate. Developed by Bruce Tuckman, this self-report questionnaire consists of a series of statements to which respondents indicate their level of agreement. The scale typically ranges from 16 to 64, with higher scores indicating a greater propensity for procrastination.

In academic settings, the scale can reveal important insights into student behavior, particularly in how they approach their studies and manage time. Scores exceeding 40 suggest the student may be prone to putting off tasks, leading to potential academic difficulties or stress. This data is valuable for educators and counselors who aim to develop strategies to help students improve their time management and study skills.
Academic Procrastination
Academic procrastination refers to the act of delaying or postponing academic tasks such as studying, completing assignments, or preparing for examinations. It is a widespread phenomenon that affects a significant number of students at various educational levels. The causes of academic procrastination can vary, including fear of failure, a lack of motivation, or poor time management skills.

Understanding procrastination can lead to better academic support systems and interventions design to prevent procrastination-related academic issues. Further, recognizing the factors contributing to procrastination can help students develop more effective personal strategies for managing their academic workload.
Sample Standard Deviation
The sample standard deviation is a measure of the amount of variation or dispersion of a set of values. A low standard deviation indicates that the data points tend to be close to the mean (or expected value) of the set, while a high standard deviation indicates that the data points are spread out over a larger range of values.

In the context of the Tuckman Procrastination Scale, the standard deviation can give insights into how varied the procrastination tendencies are among the sample of students. A higher standard deviation suggests that students' scores are more diverse, while a lower standard deviation implies that most students have similar levels of procrastination.
T-distribution
The t-distribution, also known as the Student's t-distribution, is a type of probability distribution that is symmetric and bell-shaped but has heavier tails than the normal distribution. It arises when estimates of the population mean are made from a small sample size and the population's standard deviation is unknown.

In constructing confidence intervals, as seen with the Tuckman Procrastination Scale example, the t-distribution is used to determine the critical value or t-score when the sample size is not large enough to assure a normal distribution of the sample mean. This t-score is then utilized to calculate the margin of error and construct a confidence interval that estimates the true population mean. With a given confidence level, you can infer that, with a certain degree of certainty, the population mean will fall within this interval, assuming the population from which the sample is drawn approximates a normal distribution.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A sign in the elevator of a college library indicates a limit of 16 persons. In addition, there is a weight limit of 2500 pounds. Assume that the average weight of students, faculty, and staff at this college is 150 pounds, that the standard deviation is 27 pounds, and that the distribution of weights of individuals on campus is approximately normal. A random sample of 16 persons from the campus will be selected. a. What is the mean of the sampling distribution of \(\bar{x} ?\) b. What is the standard deviation of the sampling distribution of \(\bar{x} ?\) c. What average weights for a sample of 16 people will result in the total weight exceeding the weight limit of 2500 pounds? d. What is the probability that a random sample of 16 people will exceed the weight limit?

The Economist collects data each year on the price of a Big Mac in various countries around the world. A sample of McDonald's restaurants in Europe in July 2016 resulted in the following Big Mac prices (after conversion to U.S. dollars): \(\begin{array}{llll}4.44 & 3.15 & 2.42 & 3.96\end{array}\) \(\begin{array}{llll}4.51 & 4.17 & 3.69 & 4.62\end{array}\) \(\begin{array}{lll}3.80 & 3.36 & 3.85\end{array}\) The mean price of a Big Mac in the U.S. in July 2016 was \$5.04. For purposes of this exercise, you can assume it is reasonable to regard the sample as representative of European McDonald's restaurants. Does the sample provide convincing evidence that the mean July 2016 price of a Big Mac in Europe is less than the reported U.S. price? Test the relevant hypotheses using \(\alpha=0.05 .\) (Hint: See Example 12.12.)

An automobile manufacturer decides to carry out a fuel efficiency test to determine if it can advertise that one of its models achieves \(30 \mathrm{mpg}\) (miles per gallon). Six people each drive a car from Phoenix to Los Angeles. The resulting fuel efficiencies (in miles per gallon) are: \(\begin{array}{ll}30.3 & 29.6\end{array}\) \(\begin{array}{llll}27.2 & 29.3 & 31.2 & 28.4\end{array}\) Assuming that fuel efficiency is normally distributed, do these data provide evidence against the claim that actual mean fuel efficiency for this model is (at least) \(30 \mathrm{mpg}\) ?

The formula used to calculate a confidence interval for the mean of a normal population is $$ \bar{x} \pm(t \text { critical value }) \frac{s}{\sqrt{n}} $$ What is the appropriate \(t\) critical value for each of the following confidence levels and sample sizes? a. \(90 \%\) confidence, \(n=12\) b. \(90 \%\) confidence, \(n=25\) c. \(95 \%\) confidence, \(n=10\)

Suppose that a random sample of size 64 is to be selected from a population with mean 40 and standard deviation 5. a. What are the mean and standard deviation of the sampling distribution of \(\bar{x}\) ? Describe the shape of the sampling distribution of \(\bar{x}\). b. What is the approximate probability that \(\bar{x}\) will be within 0.5 of the population mean \(\mu\) ? c. What is the approximate probability that \(\bar{x}\) will differ from \(\mu\) by more than \(0.7 ?\)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.