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What percentage of the time will a variable that has a distribution with the specified degrees of freedom fall in the indicated region? a. 5 df, between -2.02 and 2.02 b. 14 df, between -2.98 and 2.98 c. \(22 \mathrm{df}\), outside the interval from -1.72 to 1.72 d. \(26 \mathrm{df},\) to the left of -2.48

Short Answer

Expert verified
Here are the short versions of the answers for each case: a. The variable falls within the interval (-2.02, 2.02) 95% of the time. b. The variable falls within the interval (-2.98, 2.98) 99% of the time. c. The variable falls outside the interval (-1.72, 1.72) 10% of the time. d. The variable falls to the left of -2.48 1% of the time.

Step by step solution

01

Case a: 5 df, between -2.02 and 2.02

1. The degrees of freedom is 5 and the interval is between -2.02 and 2.02. 2. We can find the probabilities associated with these t-values in a t-distribution table. We find that the probability $$P(t \leq -2.02)$$ is 0.025 and $$P(t \leq 2.02)$$ is 0.975. 3. To find the probability within the interval, we subtract: $$0.975 - 0.025 = 0.95$$. This means that the variable falls within the interval 95% of the time.
02

Case b: 14 df, between -2.98 and 2.98

1. The degrees of freedom is 14 and the interval is between -2.98 and 2.98. 2. From the t-distribution table, we find that $$P(t \leq -2.98)$$ is 0.005 and $$P(t \leq 2.98)$$ is 0.995. 3. The probability within the interval is $$0.995 - 0.005 = 0.99$$. The variable falls within the interval 99% of the time.
03

Case c: 22 df, outside the interval from -1.72 to 1.72

1. The degrees of freedom is 22 and the interval we are interested in is outside -1.72 to 1.72. 2. From the t-distribution table, we find that $$P(t \leq -1.72)$$ is 0.05 and $$P(t \leq 1.72)$$ is 0.95. 3. Since we are looking for the probability outside the interval, we need to add the probabilities in the tails: $$0.05 + (1 - 0.95) = 0.10$$. Therefore, the variable falls outside the interval 10% of the time.
04

Case d: 26 df, to the left of -2.48

1. The degrees of freedom is 26 and we are looking for the probability to the left of -2.48. 2. From the t-distribution table, we find that $$P(t \leq -2.48)$$ is 0.01. 3. This means that the variable falls to the left of -2.48 in 1% of the time.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Degrees of Freedom
The concept of degrees of freedom (df) is crucial when dealing with various statistical distributions, including the t-distribution. In simple terms, the degrees of freedom in a statistical calculation represent the number of independent values that can vary in an analysis without breaking any constraints. For example, when estimating the sample variance, one degree of freedom is lost, because the sample mean is used in the calculation, thus, the degrees of freedom would be the sample size minus one.

In the context of the t-distribution probabilities, the degrees of freedom correspond to the sample size minus one, provided that we are estimating a mean from the sample. This parameter greatly affects the shape of the t-distribution: with fewer degrees of freedom, the distribution is wider and has heavier tails, meaning that there is more uncertainty. As the degrees of freedom increase, the t-distribution approaches the normal distribution in shape. Thus, understanding the impact of df helps students better interpret the probabilities extracted from the t-distribution.
Probability Calculation
Calculating probabilities is a fundamental concept in statistics. It involves determining the likelihood of an event occurring. When dealing with the t-distribution, probability calculation generally revolves around finding the area under the curve of the distribution for a given range of t-values, which corresponds to the probability of observing a value within that range. For instance, if you're looking to find the probability of a t-statistic falling between two values, you would subtract the probability associated with the lower t-value (or left of the range) from the probability associated with the higher t-value (or right of the range).

In cases where the probability to the left or to the right of a single value is required, we refer to cumulative probabilities from the t-distribution table. The ability to proficiently calculate these probabilities allows students to perform hypothesis testing and confidence interval estimations with a deeper understanding of the underlying statistics.
T-Distribution Table
The t-distribution table is an essential tool for students working with t-distribution probabilities. It lists the critical values of the t-distribution, and it’s used to find the probability associated with a particular t-value under a given degree of freedom. The t-table is typically organized such that rows correspond to degrees of freedom, and columns correspond to significance levels or probabilities. To use a t-table, you first determine the degrees of freedom for your scenario, then locate the corresponding row, and finally read off the t-values to find the cumulative probability.

Understanding how to navigate and utilize the t-distribution table effectively enables students to solve a wide range of problems without relying on statistical software for every calculation. Specifically, it is indispensable when working on exercises like determining the percentage of time a variable falls within or outside a certain range, as distinctive t-values correlate with the probabilities of events within the context of the t-distribution.

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Most popular questions from this chapter

The paper "The Effects of Adolescent Volunteer Activities on the Perception of Local Society and Community Spirit Mediated by Self-Conception" (Advanced Science and Technology Letters [2016]: 19-23) describes a survey of a large representative sample of middle school children in South Korea. One question in the survey asked how much time per year the children spent in volunteer activities. The sample mean was 14.76 hours and the sample standard deviation was 16.54 hours. a. Based on the reported sample mean and sample standard deviation, explain why it is not reasonable to think that the distribution of volunteer times for the population of South Korean middle school students is approximately normal. b. The sample size was not given in the paper, but the sample size was described as "large." Suppose that the sample size was 500 . Explain why it is reasonable to use a one-sample \(t\) confidence interval to estimate the population mean even though the population distribution is not approximately normal. c. Calculate and interpret a confidence interval for the mean number of hours spent in volunteer activities per year for South Korean middle school children. (Hint: See Example 12.7.)

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