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In a survey of mobile phone owners, \(53 \%\) of iPhone users and \(42 \%\) of Android phone users indicated that they upgraded their phones at least every two years ("Americans Split on How Often They Upgrade Their Smartphones," July 8, \(2015,\) www.gallup.com, retrieved December 15,2016 ). The reported percentages were based on large samples that were thought to be representative of the population of iPhone users and the population of Android phone users. The sample sizes were 8234 for the iPhone sample and 6072 for the Android phone sample. Suppose you want to decide if there is evidence that the proportion of iPhone owners who upgrade their phones at least every two years is greater than this proportion for Android phone users. (Hint: See Example 11.5.) a. What hypotheses should be tested to answer the question of interest? b. Are the two samples large enough for the large-sample test for a difference in population proportions to be appropriate? Explain. c. Based on the following Minitab output, what is the value of the test statistic and what is the value of the associated \(P\) -value? If a significance level of 0.01 is selected for the test, will you reject or fail to reject the null hypothesis? d. Interpret the result of the hypothesis test in the context of this problem.

Short Answer

Expert verified
Based on the large-sample test for a difference in population proportions, we reject the null hypothesis at the 0.01 significance level, indicating that there is significant evidence that the proportion of iPhone users who upgrade their phones at least every two years is greater than the proportion of Android users who upgrade their phones at least every two years.

Step by step solution

01

a. Hypotheses Formulation

Let \(p_1\) be the proportion of iPhone users that upgrade their phones at least every two years, and \(p_2\) be the proportion of Android users that upgrade their phones at least every two years. We want to test if there is evidence that the proportion of iPhone owners who upgrade their phones at least every two years is greater than this proportion for Android phone users. In other words, we want to test if \(p_1 > p_2\). The null hypothesis (\(H_0\)) states that there is no difference between the proportions, and the alternative hypothesis (\(H_a\)) states that there is a difference. \(H_0 : p_1 - p_2 = 0\) \(H_a : p_1 - p_2 > 0\)
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b. Assessing Sample Size Appropriateness for the Large-Sample Test

The large-sample test for a difference in population proportions is appropriate when the sample sizes for both populations are large enough. This is typically satisfied when the following four conditions are met: 1. \(n_1p_1 \geq 5\) 2. \(n_1(1-p_1) \geq 5\) 3. \(n_2p_2 \geq 5\) 4. \(n_2(1-p_2) \geq 5\) Using the given sample sizes and proportions: 1. \(8234 \times 0.53 \geq 5\), which is true. 2. \(8234 \times (1-0.53) \geq 5\), which is true. 3. \(6072 \times 0.42 \geq 5\), which is true. 4. \(6072 \times (1-0.42) \geq 5\), which is true. Since all four conditions are met, the sample sizes are large enough for the large-sample test for a difference in population proportions to be appropriate.
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c. Calculating Test Statistic, P-value, and Making a Decision

Since we are not given the Minitab output, we will compute it manually: The test statistic is given by: \(z = \frac{\bar{p}_1 - \bar{p}_2}{\sqrt{\frac{\bar{p}_1(1-\bar{p}_1)}{n_1}+\frac{\bar{p}_2(1-\bar{p}_2)}{n_2}}}\) where \(\bar{p}_1 = 0.53\), \(\bar{p}_2 = 0.42\), \(n_1 = 8234\) and \(n_2 = 6072\). Plugging in the values, we get: \(z = \frac{0.53 - 0.42}{\sqrt{\frac{0.53\times (1-0.53)}{8234}+\frac{0.42\times (1-0.42)}{6072}}}\) \(z \approx 10.18\) Now, we need to find the P-value to make a decision. Since we have a one-tailed test, we use the standard normal distribution table to find the P(z > 10.18). In our case, this value is virtually 0 (because 10.18 is extremely large for standard normal distribution). Since the P-value (approximately 0) is less than the significance level (0.01), we reject the null hypothesis.
04

d. Interpreting the Result

By rejecting the null hypothesis, we can conclude that there is significant evidence at the 0.01 significance level that the proportion of iPhone users who upgrade their phones at least every two years is greater than the proportion of Android users who upgrade their phones at least every two years.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Population Proportion
When we refer to the population proportion, we are talking about the fraction or percentage of the population that showcase a certain attribute or behavior. In our context, population proportion pertains to the percentage of iPhone or Android users who choose to upgrade their phones at least every two years.

To give you a clearer idea, the population proportion is usually denoted by the symbol 'p.' When we conduct studies or surveys, we can't ask every single individual in the population, so we take a sample and calculate the sample proportion, depicted as \( \bar{p} \). If the sample is representative, this sample proportion gives us a good estimate of the actual population proportion. It’s critical to ensure that our sample is large and unbiased, so conclusions drawn from the sample are likely to be an accurate reflection of the entire population.
Large-Sample Test
A large-sample test is a type of hypothesis test applied when the sample size is sufficiently large to use normal approximation. This test is particularly relevant when dealing with population proportions, as it allows us to make inferences about the population based on our sample data.

The 'large enough' criteria for sample sizes are guided by rules of thumb that expect the product of the sample size and the population proportion (both the success and failure—think 'p' and '1-p') to be greater than 5. When these conditions are met, we can confidently use the Z-test for comparing population proportions. In the context of our exercise, we verified that both iPhone and Android user samples were large enough to proceed with a large-sample test, thus providing reliable results for the proportion comparison.
Statistical Significance
Now, let’s talk about statistical significance. This concept helps us to determine whether the findings of our sample study can be generalized to the larger population. To assess statistical significance, we compare the P-value of our test statistic to a predetermined level of significance, often denoted by alpha (\(\alpha\)).

If our P-value is less than or equal to \(\alpha\), we reject the null hypothesis, suggesting that our findings are unlikely to be due to random chance and should be considered statistically significant. In our mobile phone upgrade study, the P-value was so minuscule that it virtually hit zero—far below the \(\alpha=0.01\), indicating a statistically significant difference between the proportions of iPhone and Android users upgrading their phones. Hence, we can confidently say that iPhone users indeed upgrade their phones at a higher rate than Android users.

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Most popular questions from this chapter

Many fundraisers ask for donations using e-mail and text messages. The paper "Now or Never! The Effect of Deadlines on Charitable Giving: Evidence from Two Natural Field Experiments" (Journal of Behavioral and Experimental Economics [2016]: 1-10) describes an experiment to investigate whether the proportion of people who make a donation when asked for a donation by e-mail is different from the proportion of people who make a donation when asked for a donation in a text message. In this experiment, \(1.32 \%\) of those who received and opened an e-mail request for a donation and \(7.77 \%\) of those who received a text message asking for a donation actually made a donation. Assume that the people who received these requests were randomly assigned to one of the two groups (e-mail or text message) and suppose that the given percentages are based on sample sizes of 2000 (the actual sample sizes in the experiment were much larger). a. The study described is an experiment with two treatments. What are the two treatments? b. Is there convincing evidence that the proportion who make a donation is not the same for the two different methods? Carry out a hypothesis test using a significance level of 0.05 . c. Use a \(90 \%\) confidence interval to estimate the difference in the proportions who donate for the two different treatments.

The Interactive Advertising Bureau surveyed a representative sample of 1000 adult Americans and a representative sample of 1000 adults in China (“Majority of Digital Users in U.S. and China Regularly Shop and Purchase via E-Commerce," November \(10,2016,\) www.iab.com, retrieved December 15,2016 ). They reported that American shoppers are much more likely to use a credit or a debit card to make an online purchase. This conclusion was based on finding that \(63 \%\) of the people in the United States sample said they pay with a credit or a debit card, while only \(34 \%\) of those in the China sample said that they used a credit card or a debit card to pay for online purchases. To determine if the stated conclusion is justified, you want to carry out a test of hypotheses to determine if there is convincing evidence that the proportion who pay with a credit card or a debit card is greater for adult Americans than it is for adult Chinese. a. What hypotheses should be tested to answer the question of interest? b. Are the two samples large enough for the large-sample test for a difference in population proportions to be appropriate? Explain. c. Based on the following Minitab output, what is the value of the test statistic and what is the value of the associated \(P\) -value? If a significance level of 0.01 is selected for the test, will you reject or fail to reject the null hypothesis? d. Interpret the result of the hypothesis test in the context of this problem.

The article referenced in the previous exercise also reported that \(53 \%\) of the Republicans surveyed indicated that they were opposed to making women register for the draft. Would you use the large-sample test for a difference in population proportions to test the hypothesis that a majority of Republicans are opposed to making women register for the draft? Explain why or why not.

Many people believe that they experience "information overload" in today's digital world. The report "Information Overload" (Pew Research Center, December 7, 2016) describes a survey in which people were asked if they feel overloaded by information. In a representative sample of 634 college graduates, 101 indicated that they suffered from information overload, while 119 people in an independent representative sample of 496 people who had never attended college said that they suffered from information overload. a. Construct and interpret a \(95 \%\) large-sample confidence interval for the proportion of college graduates who experience information overload. (Hint: This is a onesample confidence interval.) b. Construct and interpret a \(95 \%\) large-sample confidence interval for the proportion of people who have never attended college who experience information overload. c. Do the confidence intervals from Parts (a) and (b) overlap? What does this suggest about the two population proportions? d. Construct and interpret a \(95 \%\) large-sample confidence interval for the difference in the proportions who have experienced information overload for college graduates and for people who have never attended college. e. Is the interval in Part (d) consistent with your answer in Part (c)? Explain.

The article "Footwear, Traction, and the Risk of Athletic Injury" (January \(2016,\) www.lermagazine.com/article/footwear -traction-and-the-risk-of-athletic-injury, retrieved December \(15,\) 2016) describes a study in which high school football players were given either a conventional football cleat or a swivel disc shoe. Of 2373 players who wore the conventional cleat, 372 experienced an injury during the study period. Of the 466 players who wore the swivel disc shoe, 24 experienced an injury. The question of interest is whether there is evidence that the injury proportion is smaller for the swivel disc shoe than it is for conventional cleats. a. What are the two treatments in this experiment? b. The article didn't state how the players in the study were assigned to the two groups. Explain why it is important to know if they were assigned to the groups at random. c. For purposes of this example, assume that the players were randomly assigned to the two treatment groups. Carry out a hypothesis test to determine if there is evidence that the injury proportion is smaller for the swivel disc shoe than it is for conventional cleats. Use a significance level of 0.05 .

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