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Refer to the instructions prior to Exercise \(10.90 .\) The paper "I Smoke but I Am Not a Smoker" ( Journal of American College Health [2010]: \(117-125\) ) describes a survey of 899 college students who were asked about their smoking behavior. Of the students surveyed, 268 classified themselves as nonsmokers, but said "yes" when asked later in the survey if they smoked. These students were classified as "phantom smokers" meaning that they did not view themselves as smokers even though they do smoke at times. The authors were interested in using these data to determine if there is convincing evidence that more than \(25 \%\) of college students fall into the phantom smoker category.

Short Answer

Expert verified
In our hypothesis test, we found a z-score of 3.366 and a P-value of 0.00038, which is less than the significance level 伪 = 0.05. Therefore, we reject the null hypothesis, providing evidence that more than 25% of college students fall into the phantom smoker category.

Step by step solution

01

Define the Hypotheses

First, we need to define our null and alternative hypotheses: H鈧: p = 0.25 (the proportion of phantom smokers in the college student population is 25%) H鈧: p > 0.25 (the proportion of phantom smokers in the college student population is more than 25%)
02

Calculate the Sample Proportion

Next, we need to calculate the sample proportion (p虃) of phantom smokers: p虃 = 268 / 899 = 0.2981
03

Calculate the Standard Error

Now, we need to calculate the standard error of the sample proportion. The standard error (SE) is expressed as: SE = sqrt((p*(1-p))/n), where p = 0.25 (the proportion of phantom smokers under the null hypothesis) and n = 899 (the number of students in the survey). SE = sqrt((0.25 * (1 - 0.25)) / 899) = 0.0143
04

Calculate the Test Statistic

We have to compute the test statistic, which is a z-score, using the following formula: z = (p虃 - p) / SE z = (0.2981 - 0.25) / 0.0143 = 3.366
05

Determine the P-value

We need to find the P-value corresponding to the test statistic. Since H鈧 has '>' sign, we should calculate the area under the standard normal curve to the right of z = 3.366. Using a z-table or calculator, we find P(Z > 3.366) 鈮 0.00038.
06

Make a Decision

Lastly, we compare our P-value (0.00038) with a given significance level, usually 伪 = 0.05. If the P-value is less than 伪, we reject the null hypothesis. In this case, 0.00038 < 0.05, which means we reject H鈧 and provide evidence that the proportion of college students who are phantom smokers is more than 25%.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Hypothesis Testing
Hypothesis testing is a fundamental procedure in statistics that allows researchers to make inferences about a population based on sample data. The process starts by formulating two opposing hypotheses: the null hypothesis (H鈧) and the alternative hypothesis (H鈧). The null hypothesis typically represents a theory that there is no effect or no difference, while the alternative hypothesis represents the theory that there's an observed effect.

For the phantom smokers study, the null hypothesis is that the proportion of phantom smokers among college students is 25% (H鈧: p = 0.25), and the alternative hypothesis is that the proportion is greater than 25% (H鈧: p > 0.25). Researchers then use sample data to calculate a test statistic, which is compared to a distribution under the assumption that the null hypothesis is true to determine whether there is enough evidence to reject H鈧 in favor of H鈧.
Sample Proportion
A sample proportion is a statistic that estimates the proportion of a certain attribute in a population. It is expressed as p虃 (pronounced 'p-hat') and calculated by dividing the number of observed cases by the total number of observations in the sample.

In the phantom smokers study, the sample proportion would be the number of students who smoke but do not consider themselves smokers divided by the total number of students surveyed. Calculated as p虃 = 268 / 899, the sample proportion found in this study is approximately 0.2981. This estimated proportion from the sample is used to draw conclusions about the population proportion.
Standard Error Calculation
The standard error (SE) measures the variability of a sampling statistic, which in this case is the sample proportion. It informs us how much the sample proportion may vary from the true population proportion and is a crucial component in calculating the test statistic. Formulaically, it's represented as SE = sqrt((p*(1-p))/n), where 'p' is the population proportion under the null hypothesis and 'n' is the sample size.

For the phantom smoker study, the standard error is calculated using the proportion stated in H鈧, which is 25%, and the actual number of students surveyed: SE = sqrt((0.25 * (1 - 0.25)) / 899) = 0.0143. The standard error is pivotal for understanding the accuracy of the sample proportion as an estimate of the true proportion.
Test Statistic
The test statistic is a value used in hypothesis testing to determine whether to reject the null hypothesis. It is calculated by comparing the observed sample statistic to what was postulated in the null hypothesis and then adjusting for sample size via the standard error. Generally, a test statistic can follow various distributions, but in this context, it follows a z-distribution, making it a z-score.

A z-score measures how many standard errors an element is from the mean. For our phantom smokers case, the test statistic z = (p虃 - p) / SE is calculated with the sample proportion p虃, the null hypothesis proportion p, and the standard error SE. A large absolute value of z indicates that the observed data is less likely under the null hypothesis.
P-value Interpretation
The P-value is a crucial concept in hypothesis testing reflecting the probability of obtaining a test statistic as extreme as the observed one, or more, assuming the null hypothesis is true. It's not the probability that the null hypothesis is true, but rather a measure of the data鈥檚 compatibility with the null hypothesis.

In the phantom smokers study, the P-value calculates the probability of finding a sample proportion as large as 0.2981 if the true population proportion were only 0.25. A P-value lower than the significance level, commonly 0.05, suggests that such an extreme observation is unlikely to occur by random chance alone, leading analysts to reject the null hypothesis. The P-value in the study (0.00038) suggests strong evidence against the null hypothesis as it's much lower than the conventional significance level.

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Most popular questions from this chapter

USA TODAY, (February 17, 2011) described a survey of 1008 American adults. One question on the survey asked people if they had ever sent a love letter using e-mail. Suppose that this survey used a random sample of adults and that you want to decide if there is evidence that more than \(20 \%\) of American adults have written a love letter using e-mail. a. Describe the shape, center, and variability of the sampling distribution of \(\hat{p}\) for random samples of size 1008 if the null hypothesis \(H_{0}: p=0.20\) is true. b. Based on your answer to Part (a), what sample proportion values would convince you that more than \(20 \%\) of adults have sent a love letter via e-mail?

Explain why a \(P\) -value of 0.002 would be interpreted as strong evidence against the null hypothesis.

The report "Robot, You Can Drive My Car: Majority Prefer Driverless Technology" (Transportation Research Institute University of Michigan, www.umtri.umich.edu/what -were-doing/news/robot-you-can-drive-my-car-majority -prefer-driverless-technology, July \(22,2015,\) retrieved May 8 , 2017 ) describes a survey of 505 licensed drivers. Each driver in the sample was asked if they would prefer to keep complete control of the car while driving, to use a partially self-driving car that allowed partial driver control, or to turn full control over to a driverless car. Suppose that it is reasonable to regard this sample as a random sample of licensed drivers in the United States, and that you want to use the data from this survey to decide if there is evidence that fewer than half of all licensed drivers in the United States prefer to keep complete control of the car while driving. a. Describe the shape, center, and variability of the sampling distribution of \(\hat{p}\) for random samples of size 505 if the null hypothesis \(H_{0}: p=0.50\) is true. b. Would you be surprised to observe a sample proportion as small as \(\hat{p}=0.48\) for a sample of size 505 if the null hypothesis \(H_{0}: p=0.50\) were true? Explain why or why not. c. Would you be surprised to observe a sample proportion as small as \(\hat{p}=0.46\) for a sample of size 505 if the null hypothesis \(H_{0}: p=0.50\) were true? Explain why or why not, d. The actual sample proportion observed in the study was \(\hat{p}=0.44\). Based on this sample proportion, is there convincing evidence that fewer than \(50 \%\) of licensed drivers prefer to keep complete control of the car when driving, or is the sample proportion consistent with what you would expect to see when the null hypothesis is true? Support your answer with a probability calculation.

Medical personnel are required to report suspected cases of child abuse. Because some diseases have symptoms that are similar to those of child abuse, doctors who see a child with these symptoms must decide between two competing hypotheses: \(H_{0}:\) symptoms are due to child abuse \(H:\) symptoms are not due to child abuse (Although these are not hypotheses about a population characteristic, this exercise illustrates the definitions of Type I and Type II errors.) The article "Blurred Line Between Illness, Abuse Creates Problem for Authorities" (Macon Telegraph, February \(28,\) 2000 ) included the following quote from a doctor in Atlanta regarding the consequences of making an incorrect decision: "If it's disease, the worst you have is an angry family. If it is abuse, the other kids (in the family) are in deadly danger." a. For the given hypotheses, describe Type I and Type II errors. b. Based on the quote regarding consequences of the two kinds of error, which type of error is considered more serious by the doctor quoted? Explain.

The article "Facebook Use and Academic Performance Among College Students," Computers in Human Behavior [2015]: \(265-272\) ) estimated that \(70 \%\) of students at a large public university in California who are Facebook users log into their Facebook profiles at least six times a day. Suppose that you plan to select a random sample of 400 students at your college. You will ask each student in the sample if they are a Facebook user and if they log into their Facebook profile at least six times a day. You plan to use the resulting data to decide if there is evidence that the proportion for your college is different from the proportion reported in the article for the college in Califomia. What hypotheses should you test? (Hint: See Example \(10.3 .)\)

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