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91Ó°ÊÓ

Determine the point estimate of the population mean and margin of error for each confidence interval. Lower bound: \(20,\) upper bound: 30

Short Answer

Expert verified
Point Estimate: 25, Margin of Error: 5

Step by step solution

01

Understand the Problem

The given problem requires determining the point estimate of the population mean and the margin of error from the provided confidence interval bounds. The lower bound is 20 and the upper bound is 30.
02

Calculate the Point Estimate

The point estimate of the population mean can be found by calculating the average of the lower and upper bounds of the confidence interval. Use the formula:\[ \text{Point Estimate} = \frac{\text{Lower Bound} + \text{Upper Bound}}{2} \]Substitute the given values:\[ \text{Point Estimate} = \frac{20 + 30}{2} = 25 \]
03

Calculate the Margin of Error

The margin of error can be determined by finding the difference between the upper bound and the lower bound of the confidence interval, and then divide by 2. Use the formula:\[ \text{Margin of Error} = \frac{\text{Upper Bound} - \text{Lower Bound}}{2} \]Substitute the given values:\[ \text{Margin of Error} = \frac{30 - 20}{2} = 5 \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

population mean
The population mean is a crucial concept in statistics. It represents the average value of a particular characteristic in the whole population. For example, if you calculate the average height of all students in a school, this average height is the population mean. Calculating the population mean is often impractical due to the size of the population, so we estimate it using a sample mean from selected data.

This sample mean helps us to make assumptions about the entire population. When we estimate the population mean, we use techniques like confidence intervals to understand how accurate our estimate might be. The true population mean lies within this interval, giving us a range where the actual mean is likely to be. By understanding the population mean, you can make more informed decisions and predictions based on data.
point estimate
A point estimate is a single value that approximates a population parameter. It's like picking a single point in a dart game to hit the target. In the context of population mean, the point estimate would be the average of the sample data, aimed to represent the population mean.

For instance, in our given exercise, to determine the point estimate of the population mean, we used the formula: \( \text{Point Estimate} = \frac{\text{Lower Bound} + \text{Upper Bound}}{2} \). By substituting the given values (lower bound: 20 and upper bound: 30), we get: \( \text{Point Estimate} = \frac{20 + 30}{2} = 25 \).

This value of 25 is our point estimate, offering an approximation of the actual population mean from our sample data. Remember, a point estimate doesn't provide any information about the accuracy or uncertainty of the estimate. That's why we use confidence intervals along with it.
margin of error
The margin of error measures the range of uncertainty around a point estimate. It tells us how much our point estimate might vary due to sampling variability or inherent statistical errors. It is an essential part of the confidence interval, helping clarify the reliability of the estimate.

In the given exercise, we calculated the margin of error using the formula: \( \text{Margin of Error} = \frac{\text{Upper Bound} - \text{Lower Bound}}{2} \). By substituting the values (upper bound: 30 and lower bound: 20), we have: \( \text{Margin of Error} = \frac{30 - 20}{2} = 5 \).

This means our point estimate (25) could be off by 5 units in either direction. So, the true population mean is likely to be between 20 (25-5) and 30 (25+5).

That’s it! By understanding the margin of error, you can better gauge how close your sample's point estimate might be to the actual population parameter. This helps you make more informed decisions and reduces the risk of incorrect conclusions based on the data.

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Most popular questions from this chapter

A researcher wishes to estimate the proportion of households that have broadband Internet access. What size sample should be obtained if she wishes the estimate to be within 0.03 with \(99 \%\) confidence if (a) she uses a 2009 estimate of 0.635 obtained from the National Telecommunications and Information Administration? (b) she does not use any prior estimates?

The following data represent the \(\mathrm{pH}\) of rain for a random sample of 12 rain dates in Tucker County, West Virginia. A normal probability plot suggests the data could come from a population that is normally distributed. A boxplot indicates there are no outliers. $$ \begin{array}{llllll} \hline 4.58 & 5.19 & 5.05 & 4.80 & 4.77 & 4.77 \\ \hline 5.72 & 4.75 & 5.02 & 4.74 & 4.76 & 4.56 \\ \hline \end{array} $$ (a) Determine a point estimate for the population mean \(\mathrm{pH}\) of rainwater in Tucker County. (b) Construct and interpret a \(95 \%\) confidence interval for the mean \(\mathrm{pH}\) of rainwater in Tucker County, West Virginia. (c) Construct and interpret a \(99 \%\) confidence interval for the mean \(\mathrm{pH}\) of rainwater in Tucker County, West Virginia. (d) What happens to the interval as the level of confidence is increased? Explain why this is a logical result.

Sleep apnea is a disorder in which you have one or more pauses in breathing or shallow breaths while you sleep. In a cross-sectional study of 320 individuals who suffer from sleep apnea, it was found that 192 had gum disease. Note: In the general population, about \(17.5 \%\) of individuals have gum disease. (a) What does it mean for this study to be cross-sectional? (b) What is the variable of interest in this study? Is it qualitative or quantitative? Explain. (c) Estimate the proportion of individuals who suffer from sleep apnea who have gum disease with \(95 \%\) confidence. Interpret your result.

The following data represent the repair cost for a low-impact collision in a simple random sample of mini- and micro-vehicles (such as the Chevrolet Aveo or Mini Cooper). $$ \begin{array}{lrlrr} \hline \$ 3148 & \$ 1758 & \$ 1071 & \$ 3345 & \$ 743 \\ \hline \$ 2057 & \$ 663 & \$ 2637 & \$ 773 & \$ 1370 \\ \hline \end{array} $$ (a) Draw a normal probability plot to determine if it is reasonable to conclude the data come from a population that is normally distributed. (b) Draw boxplot to check for outliers. (c) Construct and interpret a \(95 \%\) confidence interval for the population mean cost of repair. (d) Suppose you obtain a simple random sample of size \(n=10\) of a Mini Cooper that was in a low-impact collision and determine the cost of repair. Do you think a \(95 \%\) confidence interval would be wider or narrower? Explain.

A sociologist wishes to conduct a poll to estimate the percentage of Americans who favor affirmative action programs for women and minorities for admission to colleges and universities. What sample size should be obtained if she wishes the estimate to be within 4 percentage points with \(90 \%\) confidence if (a) she uses a 2003 estimate of \(55 \%\) obtained from a Gallup Youth Survey? (b) she does not use any prior estimates? (c) Why are the results from parts (a) and (b) so close?

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