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91Ó°ÊÓ

Determine the critical value for a left-tailed test regarding a population proportion at the \(\alpha=0.1\) level of significance.

Short Answer

Expert verified
The critical value is \( -1.28 \).

Step by step solution

01

Identify the Significance Level

Understand that the level of significance \( \alpha \) is given as 0.1. This value represents the probability of rejecting the null hypothesis when it is actually true.
02

Understand the Tail Type

Recognize that this is a left-tailed test. This means the critical region is in the left tail of the standard normal distribution curve.
03

Find the Critical Value Using Z-Table

To find the critical value for a left-tailed test at \( \alpha=0.1 \), use the Z-table to look up the z-value that corresponds to a cumulative probability of 0.1. This value indicates the point where 10% of the area under the normal curve is to the left.
04

Determine the Z-Value

Using the Z-table, find the z-value that corresponds to a cumulative probability of 0.1. The critical z-value for \( \alpha = 0.1 \) in a left-tailed test is \( -1.28 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

left-tailed test
A left-tailed test is a type of hypothesis test in statistics where the critical region falls in the left tail of the standard normal distribution curve. In these tests, you are specifically interested in whether the sample data significantly less than the population parameter outlined in the null hypothesis.

If you imagine a bell curve, the left tail is the area on the far left side. This is where we would find values that are significantly smaller than the mean. The purpose of a left-tailed test is to test for a decrease or a minimum in the sample data.
  • Example: Testing if a new medication lowers blood pressure more than the standard medication.
By finding the critical value in this left tail, we can determine if the observed sample statistic lies in this critical area, which suggests that the null hypothesis should be rejected in favor of the alternative hypothesis.
significance level
The significance level, denoted by the Greek letter \( \alpha \), represents the probability of rejecting the null hypothesis when it is actually true. This is also known as the probability of making a Type I error.

In hypothesis testing, the significance level is chosen before collecting data. It sets a threshold for how extreme the observed result must be to reject the null hypothesis.
  • A commonly used value is \( \alpha = 0.05 \), meaning there's a 5% risk of concluding that an effect exists when it doesn't.
  • In our example, the significance level is set at \( \alpha = 0.1 \), which means we are willing to accept a 10% risk.
The lower the significance level, the less likely we are to reject the null hypothesis, requiring stronger evidence against it.
Z-table lookup
The Z-table, also known as the standard normal table, is used to find the critical values corresponding to a given significance level in standard normal distribution. This table provides the area (or probability) to the left of a specified Z-score.

To use the Z-table for a left-tailed test:
  • Locate the desired cumulative probability (here, 0.1 for a 10% significance level).
  • Find the corresponding Z-value, which indicates the point on the standard normal distribution.
In our example, we look for the cumulative probability of 0.1 in the Z-table, which results in a Z-value of -1.28.

This value means that approximately 10% of the data lies to the left of -1.28 in a standard normal distribution.
population proportion
Population proportion refers to the fraction of the population that possesses a particular characteristic. It is denoted by \( p \).

For example, if 45 out of 100 students in a school are left-handed, the population proportion of left-handed students is 0.45 or 45%.
  • When testing hypotheses about population proportions, we often use Z-tests, especially for large sample sizes.
  • Essential context involves the hypothesized population proportion, the sample proportion, and the Z-table lookup to determine critical values and p-values.
Understanding population proportions is crucial for analyzing categorical data and making inferences about larger groups based on sample statistics.

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Most popular questions from this chapter

According to menstuff.org, \(22 \%\) of married men have "strayed" at least once during their married lives. A survey of 500 married men indicated that 122 have strayed at least once during their married life. Does this survey result contradict the results of menstuff.org? (a) What does it mean to make a Type II error for this test? (b) If the researcher decides to test this hypothesis at the \(\alpha=0.05\) level of significance, determine the probability of making a Type II error if the true population proportion is \(0.25 .\) What is the power of the test? (c) Redo part (b) if the true proportion is 0.20 .

The manufacturer of processed deli meats reports that the standard deviation of the number of carbohydrates in its smoked turkey breast is 0.5 gram per 2-ounce serving. A dietitian does not believe the manufacturer and randomly selects eighteen 2 -ounce servings of the smoked turkey breast and determines the number of carbohydrates per serving. The standard deviation of the number of carbs is computed to be 0.62 gram per serving. Is there sufficient evidence to indicate that the standard deviation is not 0.5 gram per serving at the \(\alpha=0.05\) level of significance? A normal probability plot indicates that the number of carbohydrates per serving is normally distributed.

According to the Centers for Disease Control and Prevention, \(2.8 \%\) of high school students currently use electronic cigarettes. A high school counselor is concerned the use of e-cigs at her school is higher. (a) Determine the null and alternative hypotheses. (b) If the sample data indicate that the null hypothesis should not be rejected, state the conclusion of the school counselor. (c) Suppose, in fact, that the proportion of students at the counselor's high school who use electronic cigarettes is \(0.034 .\) Was a Type I or Type II error committed?

Throwing darts at the stock pages to decide which companies to invest in could be a successful stock-picking strategy. Suppose a researcher decides to test this theory and randomly chooses 100 companies to invest in. After 1 year, 53 of the companies were considered winners; that is, they outperformed other companies in the same investment class. To assess whether the dart-picking strategy resulted in a majority of winners, the researcher tested \(H_{0}: p=0.5\) versus \(H_{1}: p>0.5\) and obtained a \(P\) -value of \(0.2743 .\) Explain what this \(P\) -value means and write a conclusion for the researcher.

To test \(H_{0}: p=0.30\) versus \(H_{1}: p<0.30,\) a simple random sample of \(n=300\) individuals is obtained and \(x=86\) successes are observed. (a) What does it mean to make a Type II error for this test? (b) If the researcher decides to test this hypothesis at the \(\alpha=0.05\) level of significance, compute the probability of making a Type II error if the true population proportion is \(0.28 .\) What is the power of the test? (c) Redo part (b) if the true population proportion is 0.25 .

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