/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 13 Throwing darts at the stock page... [FREE SOLUTION] | 91Ó°ÊÓ

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Throwing darts at the stock pages to decide which companies to invest in could be a successful stock-picking strategy. Suppose a researcher decides to test this theory and randomly chooses 100 companies to invest in. After 1 year, 53 of the companies were considered winners; that is, they outperformed other companies in the same investment class. To assess whether the dart-picking strategy resulted in a majority of winners, the researcher tested \(H_{0}: p=0.5\) versus \(H_{1}: p>0.5\) and obtained a \(P\) -value of \(0.2743 .\) Explain what this \(P\) -value means and write a conclusion for the researcher.

Short Answer

Expert verified
The P-value of 0.2743 indicates there is not enough evidence to reject the null hypothesis. The dart-picking strategy does not result in a majority of winners according to this test.

Step by step solution

01

- State the Null and Alternative Hypotheses

The null hypothesis ( H_0) is that the proportion of companies considered winners is 0.5 ( p = 0.5). The alternative hypothesis ( H_1) is that the proportion of companies considered winners is greater than 0.5 ( p > 0.5).
02

- Interpret the P-Value

The P -value represents the probability of observing the test results, or more extreme results, under the null hypothesis. In this case, a P -value of 0.2743 indicates that there is a 27.43% chance of obtaining a sample proportion of winners at least as extreme as 0.53, assuming the null hypothesis is true.
03

- Evaluate the P-Value Against the Significance Level

Typically, a significance level ( α) of 0.05 is used to decide whether to reject the null hypothesis. If the P -value is greater than α, we do not reject the null hypothesis. Here, the P -value (0.2743) is greater than 0.05.
04

- Draw a Conclusion

Since the P -value is greater than the significance level of 0.05, we do not reject the null hypothesis. This means there is not enough evidence to support the claim that the dart-picking strategy results in a majority of winners.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

P-Value Interpretation
The P-value is a key aspect of hypothesis testing. It tells us the probability of observing our data, or something more extreme, if the null hypothesis is true.

In our example, the P-value is 0.2743. This means that if the dart-picking strategy had no effect (i.e., the true proportion of winners is 0.5), there is a 27.43% chance of randomly selecting a sample with 53 or more winners out of 100.

When we evaluate a P-value, we compare it to our chosen significance level, denoted as \( \alpha \). If the P-value is lower than this threshold, we have enough evidence to reject the null hypothesis. Otherwise, we do not reject it.
Null and Alternative Hypotheses
Hypothesis testing begins with formulating two contrasting hypotheses: the null hypothesis (\( H_0 \)) and the alternative hypothesis (\( H_1 \)).

In this example,
the null hypothesis is \( H_0: p = 0.5 \), indicating that the proportion of winning companies is 0.5;
while the alternative hypothesis is \( H_1: p > 0.5 \), suggesting that the strategy results in more than 50% winners.

These hypotheses set the stage for the test. The null hypothesis represents a default position that there is no effect or no difference. The alternative hypothesis, on the other hand, reflects the claim we are testing for.

By conducting a hypothesis test and using the observed P-value, we can determine whether the data provides sufficient evidence to reject the null hypothesis in favor of the alternative hypothesis.
Significance Level (Alpha)
The significance level is a critical value that helps us decide if a result is statistically significant. It is denoted as \( \alpha \) and typically set at 0.05.

In our dart-picking example, the significance level \( \alpha \) is 0.05. This means we are willing to accept a 5% chance of concluding that the strategy results in a majority of winners when it actually does not.

We compare our P-value to \( \alpha \) to make a decision. If the P-value is less than \( \alpha \), we reject the null hypothesis, suggesting that the observed effect is statistically significant.
In this case, the P-value of 0.2743 is greater than 0.05, so we do not reject the null hypothesis.

This indicates that the observed proportion of 53 winners is not significantly higher than 50%, meaning there's not enough evidence to prove that the dart-picking strategy is effective.

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Most popular questions from this chapter

Simulation Simulate drawing 100 simple random samples of size \(n=15\) from a population that is normally distributed with mean 100 and standard deviation 15 . (a) Test the null hypothesis \(H_{0}: \mu=100\) versus \(H_{1}: \mu \neq 100\) for each of the 100 simple random samples. (b) If we test this hypothesis at the \(\alpha=0.05\) level of significance, how many of the 100 samples would you expect to result in a Type I error? (c) Count the number of samples that lead to a rejection of the null hypothesis. Is it close to the expected value determined in part (b)? (d) Describe how we know that a rejection of the null hypothesis results in making a Type I error in this situation.

NCAA rules require the circumference of a softball to be \(12 \pm 0.125\) inches. Suppose that the NCAA also requires that the standard deviation of the softball circumferences not exceed 0.05 inch. A representative from the NCAA believes the manufacturer does not meet this requirement. She collects a random sample of 20 softballs from the production line and finds that \(s=0.09\) inch. Is there enough evidence to support the representative's belief at the \(\alpha=0.05\) level of significance?

To test \(H_{0}: p=0.40\) versus \(H_{1}: p>0.40,\) a simple random sample of \(n=200\) individuals is obtained and \(x=84\) successes are observed. (a) What does it mean to make a Type II error for this test? (b) If the researcher decides to test this hypothesis at the \(\alpha=0.05\) level of significance, compute the probability of making a Type II error if the true population proportion is 0.44. What is the power of the test? (c) Redo part (b) if the true population proportion is 0.47

Suppose we are testing the hypothesis \(H_{0}: p=0.3\) versus \(H_{1}: p>0.3\) and we find the \(P\) -value to be \(0.23 .\) Explain what this means. Would you reject the null hypothesis? Why?

To test \(H_{0}: \sigma=4.3\) versus \(H_{1}: \sigma \neq 4.3,\) a random sample of size \(n=12\) is obtained from a population that is known to be normally distributed. (a) If the sample standard deviation is determined to be \(s=4.8\), compute the test statistic. (b) If the researcher decides to test this hypothesis at the \(\alpha=0.05\) level of significance, determine the critical values. (c) Draw a chi-square distribution and depict the critical regions. (d) Will the researcher reject the null hypothesis? Why?

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