/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 5 In the study An X-Ray Fluorescen... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

In the study An X-Ray Fluorescence Method for Analyzing Polybutadiene-Acrylic Acid (PBAA) Propellants, Quarterly Reports, RK-TR-62-1, Army Ordnance Missile Command, an experiment was conducted to determine whether or not there is a significant difference in the amount of aluminum achieved in the analysis between certain levels of certain processing variables. The data given in the table were recorded. $$ \begin{array}{cccccc} &\ {\text { Phys. Mixing Blade Nitrogen }} \\ \text { Obs.} &{ State } & \text { Time } &\text { Speed } & {Condition}& { Aluminum}{ } \\ \hline \mathbf{1} & 1 & 1 & 2 & 2 & 16.3 \\ 2 & 1 & 2 & 2 & 2 & 16.0 \\ 3 & 1 & 1 & 1 & 1 & 16.2 \\ 4 & 1 & 2 & 1 & 2 & 16.1 \\ 5 & 1 & 1 & 1 & 2 & 16.0 \\ 6 & 1 & 2 & 1 & 1 & 16.0 \\ 7 & 1 & 2 & 2 & 1 & 15.5 \\ 8 & 1 & 1 & 2 & 1 & 15.9 \\ 9 & 2 & 1 & 2 & 2 & 16.7 \\ 10 & 2 & 2 & 2 & 2 & 16.1 \\ 11 & 2 & 1 & 1 & 1 & 16.3 \\ 12 & 2 & 2 & 1 & 2 & 15.8 \\ 13 & 2 & 1 & 1 & 2 & 15.9 \\ 14 & 2 & 2 & 1 & 1 & 15.9 \\ 15 & 2 & 2 & 2 & 1 & 15.6 \\ 16 & 2 & 1 & 2 & 1 & 15.8 \end{array} $$ The variables are given below. .4: mixing time level \(1-2\) hours level \(2-4\) hoursi B: \(\quad\) blade speed \(\begin{array}{lll}\text { level } & 1-36 & \text { rpin }\end{array}\) level \(2-78\) rpm \(C: \quad\) condition of nitrogen passed over propellant level \(1-\mathrm{dry}\) level \(2-72 \%\) relative humidity \(D: \quad\) physical state of propellant level 1 -uncured level 2 -cured Assuming all three- and four-factor interactions to be negligible, analyze the data. Use a 0.05 level of significance. Write a brief report summarizing the findings.

Short Answer

Expert verified
In this multi-factor ANOVA, it's necessary to calculate the sum of squares, degrees of freedom, mean squares, and F-value for each factor and their interactions, and compare them with the critical values to check for significance. The significant factors are the ones which have a p-value less than the given significance level (0.05). The analysis is complex and requires a thorough understanding of ANOVA concept and a good grasp of calculation.

Step by step solution

01

Understanding The Data

First, understand what the data is representing. Each row in the table represents a different trial of the experiment. There are four factors: physical state of the propellant (A), mixing time (B), blade speed (C), and the condition of nitrogen passed over propellant (D). Each factor has two levels, so there are a total of 16 combinations or trials.
02

Setting Up ANOVA

Set up the Analysis of Variance (ANOVA) table. The ANOVA table should include the source of variation (the 4 factors and their interactions), the sum of squares (SS), the degrees of freedom (df), the mean squares (MS), the F-value, and the p-value.
03

Calculating SS Among and Within

Calculate the sum of squares among groups (SSA, SSB, SSC, SSD, SSAB, SSBC, SBD, SSCD) and the sum of squares within groups (SSE). This is done by finding the total sum of squares (SST), and subtracting the sum of squares among groups.
04

Calculating df, MS and F-value

Next, calculate the degrees of freedom (df), mean squares (MS), and the F-value. The df is the number of categories of each factor minus 1. The MS is the SS divided by the df. The F-value is the ratio of the mean squares between groups to the mean square within groups.
05

Testing The Hypothesis

Using the F-distribution table and the given significance level (0.05), find the critical F-value and reject the null hypothesis if the calculated F-value is greater than the critical F-value.
06

Summarizing Findings

Interpret the results and summarize the findings. If any of the factors' p-values is less than the significance level, this means that the factor has a statistically significant effect on the aluminum content.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Statistical Significance
Understanding statistical significance is fundamental when interpreting ANOVA results. The term refers to the likelihood that the difference observed in an experiment or a study is due to something other than random chance. To assess this, researchers set a threshold called the significance level, typically denoted as \( \alpha \). The common significance level is \( \alpha = 0.05 \), meaning there's a 5% risk of concluding that a difference exists when there isn't one.

In the context of the propellant study, we use the significance level to determine if processing variables like physical state, mixing time, blade speed, and nitrogen condition, actually impact the aluminum content quantitatively measured. If the calculated p-value for a factor is less than \( \alpha \), we would declare a statistically significant difference attributable to that factor. This would suggest that the level of aluminum detected in the propellant analysis changes with different conditions of that particular factor beyond what we'd expect from random variation.
Sum of Squares
The sum of squares (SS) is a measure used in statistics to quantify variations within data. When performing ANOVA, SS is a critical component that breaks down the total variability observed in the data into components attributable to each source of variation. There are several types of SS:

Between-Group Sum of Squares (SSB)

This reflects the variance due to the differences between the group means. In your ANOVA for the propellant study, each factor like mixing time and blade speed contributes to SSB.

Within-Group Sum of Squares (SSW)

Reflects the variance within each group, which could be due to randomness or experimental error.

Total Sum of Squares (SST)

The overall variability in the data. Calculated as the sum of SSB and SSW.

By partitioning SST into SSB and SSW, we can find out how much of the variation in aluminum content is due to the systematic differences in processing variables and how much is due to other factors, including inherent experimental variability.
F-distribution
The F-distribution is the foundation for conducting ANOVA and is used to calculate the F-value, a ratio that compares the variance between group means to the variance within groups. Here's how it works:

Forming the F-ratio

An F-value is calculated by dividing the mean square value of the variance among the groups (MSB) by the mean square value of the variance within the groups (MSW). In equation form, it looks like \( F = \frac{MSB}{MSW} \).

F-distribution Characteristics

The F-distribution is a right-skewed distribution that is defined by two different degrees of freedom: df1 for the numerator and df2 for the denominator. These degrees of freedom directly influence the shape of the F-distribution curve.

Considering the experiment to analyze PBAA propellants, after calculating the F-value for each factor, it's compared to a critical F-value from the F-distribution table. If the calculated F-value is greater than the critical F-value at a specified significance level, the null hypothesis (that there’s no effect) is rejected, indicating that there is a statistically significant difference caused by that factor.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The following experiment was rnn to study main effects and all interactions. Four factors are used at two levels each. The experiment is replicated and two blocks are necessary in each replication. The data are presented here. (a) What effect is confounded with blocks in the first replication of the experiment? In the second replication? (h) Conduct an appropriate analysis of variance showing tests on all main effects and interaction effects. Use a 0.05 level of significance. $$ \begin{array}{rr|rr} \ {\text { Replicate } 1} & &\ {\text { Replicate } 2} \\ \hline \text { Block 1 } & \text { Block 2 } & \text { Block 3 } & \text { Block 4 } \\ \hline \mathbf{( 1 )}=17.1 & a=15.5 & \mathbf{( 1 )}=18.7 & a=17.0 \\ d=16.8 & b=14.8 & a b=18.6 & b=17.1 \\ a b=16.4 & \mathrm{c}=16.2 & a c=18.5 & c=17.2 \\ a c=17.2 & a d=17.2 & a d=18.7 & d=17.6 \\ 6 \mathrm{c}=16.8 & b d=18.3 & b c=18.9 & a b c=17.5 \\ a b d=18.1 & c d=17.3 & b d=17.0 & a b d=18.3 \\ a c d=\mathbf{1 9 . 1} & a b c=17.7 & c d=\mathbf{1 8 . 7} & a c d=18.4 \\ b c d=18.4 & a b c d=19.2 & a b c d=19.8 & b c d=18.3 \end{array} $$

In an experiment conducted at the Department of Mechanical Engineering and analyzed by the Statistics Consulting Center at the Virginia Polytechnic Institute and State University, a sensor detects an electrical charge each time a turbine blade makes one; rotation. The sensor then measures the amplitude of the electrical current. Six factors arc rprn \(A\), temperature \(B\), gap between blades \(C\), gap between blade and casing \(D\), location of input \(E\), and location of detection \(F .\) A \(\frac{1}{4}\) fraction of a \(2^{\circ}\) factorial experiment is used, with defining contrasts being \(A B C E\) and \(B C D F .\) The data are as follows: $$ \begin{array}{rrrrrrr} A & B & C & D & E & F & \text { Response } \\ \hline-1 & -1 & -1 & -1 & -1 & -1 & 3.89 \\ 1 & -1 & -1 & -\mathrm{i} & 1 & -1 & 10.46 \\ -1 & 1 & -1 & -1 & 1 & 1 & 25.98 \\ 1 & 1 & -1 & -1 & -1 & 1 & 39.88 \\ -1 & -1 & 1 & -1 & 1 & 1 & 61.88 \\ 1 & -1 & 1 & -1 & -1 & 1 & 3.22 \\ -1 & 1 & 1 & -1 & -1 & -1 & 8.94 \\ 1 & 1 & 1 & -1 & 1 & -1 & 20.29 \\ -1 & -1 & -1 & 1 & -1 & 1 & 32.07 \\ 1 & -1 & -1 & 1 & 1 & 1 & 50.76 \\ -1 & 1 & -1 & 1 & 1 & -1 & 2.80 \\ 1 & 1 & -1 & 1 & -1 & -1 & 8.15 \\ -1 & -1 & 1 & 1 & 1 & -1 & 16.80 \\ 1 & -1 & 1 & 1 & -1 & -1 & 25.47 \\ -1 & 1 & 1 & 1 & -1 & 1 & 44.44 \\ 1 & 1 & 1 & 1 & 1 & 1 & 2.45 \end{array} $$ Perform an analysis of variance on main effects, and two-factor interactions. assuming that all three-factor and higher interactions are negligible. Use \(\alpha=0.05\).

A \(2^{2}\) factorial experiment is analyzed by the Statistics Consulting Center at Virginia Polytechnic Institute and State University. The client is a member of the Department of Housing, Interior Design, and Resource Management. The client is interested in comparing cold start versus preheating ovens in terms of total energy being delivered to the product. In addition, the conditions of convection are being compared to regular mode. Four experimental runs were made at each of the four factor combinations. Following are the data from the experiment: $$ \begin{array}{lcl|cc} & \ {\text { Preheat }} & & {\text { Cold }} \\ \hline \text { Convection } & 618 & 619.3 & 575 & 573.7 \\ \text { Mode } & 629 & 611 & 574 & 572 \\ \hline \text { Regular } & 581 & 585.7 & 558 & 562 \\ \text { Mode } & 581 & 595 & 562 & 566 \end{array} $$ Do an analysis of variance to study main effects and interaction. Draw conclusions.

List the aliases for the various effects in a \(2^{5}\) factorial experiment when the defining contrast is \(A C D E\).

Construct a Plackett-Burman design for 10 variables containing 24 experimental runs.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.