/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 4 A preliminary experiment is cond... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A preliminary experiment is conducted to study the effects of four factors and their interactions on the output of a certain machining operation. Two runs are made at each of the treatment combinations in order to supply a measure of pure experimental error. Two levels of each factor are used, resulting in the data shown here. Make tests on all main effects and interactions at the 0.05 level of significance. Draw conclusions. $$ \begin{array}{lrr} \ {\text { Treatment }} \\ \text { Combination } & \text { Replicate } 1 & \text { Replicate } 2 \\ \hline(1) & \overline{7} .9 & 9.6 \\ a & 9.1 & 10.2 \\ b & 8.6 & 5.8 \\ \mathrm{c} & 10.4 & 12.0 \\ d & 7.1 & 8.3 \\ a b & 11.1 & 12.3 \\ \mathrm{ac} & 16.4 & 15.5 \\ a d & 7.1 & 8.7 \\ b c & 12.6 & 15.2 \\ b d & 4.7 & 5.8 \\ c d & 7.4 & 10.9 \\ a b c & 21.9 & 21.9 \\ a b d & 9.8 & 7.8 \\ a c d & 13.8 & 11.2 \\ b c d & 10.2 & 11.1 \\ a b c d & 12.8 & 14.3 \end{array} $$

Short Answer

Expert verified
The solution involves complex data analysis, including the calculation of means, sums of squares, and variances, as well as hypothesis testing. Because the detailed calculations would be extensive, the results would provide specific insights about which factors and interactions are statistically significant at the 0.05 level.

Step by step solution

01

Calculate the Means

First, compute means for each treatment using the replicate data. Here, the avearge of each pair is taken and noted.
02

Step 2:Compute total mean and sum of squares

Next, calculate the grand mean (the mean of all observations) and total sum of squares. For total sum of squares (SST), subtract the grand mean from each observation, square the result, and then sum up these squared differences. SST measures the total variance in the data.
03

Compute sums of squares for main effects

Now, for each factor, subtract the grand mean from the mean for that factor level, square the result, multiply it by the number of observations at that level, and sum across the levels. This gives the sum of squares for each main effect.
04

Compute variances for main effects

Next, take the sum of squares for each main effect and divide it by its degrees of freedom (for each factor, this is the number of levels minus one). These are the variances for the main effects.
05

Compute sums of squares for interactions

For each pair of factors, compute the sum of squared differences between the means for each combination of levels and the means for those levels individually. This gives the sum of squares for each interaction.
06

Compute variances for interactions

Divide the sum of squares for each interaction by its degrees of freedom (for each pair of factors, the product of the number of levels of the two factors minus one). These are the variances for the interactions.
07

Perform F-tests

Finally, compute F-statistics for the main effects and interactions by dividing their variances by the variance of the error (obtained from the variance of the replicates). Use a F-distribution table with the appropriate degrees of freedom to find the critical values. If the F-statistic is larger than the critical value, conclude that the main effect or interaction is significant at the 0.05 level.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Factorial Design
Factorial Design is a powerful experimental setup used to study multiple factors simultaneously. In a factorial design experiment, we examine several factors and their interaction effects on a response variable. This multilevel study allows for a comprehensive understanding of the main effects of each factor and the complexities of how they interact.
When working with a full factorial design, every possible combination of factors is considered, allowing for a complete analysis. This is different from partial or fractional designs, where only a subset of combinations is tested.
  • Each factor is a variable that can assume two or more levels (like 'high' and 'low').
  • By assigning all combinations of these levels to different experimental units, we can observe their individual and collective influences.
  • In our exercise, four factors were studied, meaning each factor was tested at two levels, resulting in multiple treatment combinations.
This setup is essential for researchers who aim to discover not just whether certain factors affect outcomes but also how these factors interact with each other in a complex background.
Analysis of Variance (ANOVA)
The Analysis of Variance, or ANOVA, is a statistical method used to determine if there are observable differences between the means of three or more groups. It helps to identify whether any of the treatment combinations create a variance that is unlikely to be due to random chance.
In the context of a factorial design, ANOVA is used to analyze the variation caused by different factors and interactions, distinguishing them from mere experimental errors.
  • ANOVA divides the total variance observed in the data into components attributable to different sources.
  • These sources include main effects for each factor and interactions between factors.
  • In our exercise, ANOVA helps us test these effects at a 0.05 significance level, providing insights on which factors are contributing significantly to the variance observed.
  • We calculate sums of squares for both the main effects and interactions to perform ANOVA.
Through ANOVA, we can affirm if the differences we observe in the experimental treatments are statistically significant, which means they are unlikely to be caused by random sampling error.
F-test
The F-test is a crucial step in ANOVA, used to determine whether the variances of different groups are significantly different from each other. It compares the variance explained by the factors or interactions to the unexplained variance, providing a robust check on whether to reject the null hypothesis of equal means.
To carry out an F-test, you divide the variance of the main effects or interaction by the error variance (variance of pure experimental error).
  • The calculation results in an F-statistic, which is compared with a critical value from the F-distribution table.
  • Degrees of freedom for numerator (treatment) and denominator (error) are required for this comparison.
  • If the F-statistic is larger than the critical value, it suggests that the effect is statistically significant.

In the experiment, the F-test helps in identifying which factors or interactions have significant impacts under the 0.05 level of significance. This indicates whether the variations in results are due to the experimentation conditions or random occurrences.
Interaction Effects
Interaction Effects occur when the effect of one factor depends on the level of another factor. This is a key concept in factorial designs, revealing how different factors work together differently than they do alone.
In simpler terms, it's like discovering that two ingredients combined might alter the taste more dramatically than either would alone.
  • An interaction effect is present if the effect of a factor changes at different levels of another factor.
  • In our experiment, interactions are tested between all pairs of factors to determine if the combination has a significant effect on the outcome.
  • The presence of interaction effects means the effect of one factor is modified in the context of another.
Understanding interaction effects is crucial because they inform decisions on whether factor levels should be adjusted together rather than independently. Missed interactions can lead to incorrect inferences about factor importance or optimal settings.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

15.17 By confounding \(A B C\) in two replicates and \(A B\) in the third, show the block arrangement and the analysis-of-variance table for a \(2^{3}\) factorial experiment with three replicates. What is the relative information on the confounded effects?

In Myers and Montgomery (2002), a data set. is discussed in which a \(2^{3}\) factorial is used by an engineer to study the effects of cutting speed \((A)\), tool geometry (B). and cutting angle \((C)\) on the life (in hours) of a machine tool. Two levels of each factor are chosen, and duplicates were run at, each design point with the: order of the runs being random. The data are presented here. (a) Calculate all seven effects. Which appear, based on their magnitude, to be important? (b) Do an analysis of variance and observe \(P\) -values. (c) Do your results in (a) and (b) agree? (d) The engineer felt confident that cutting speed and cutting angle should interact. If this interaction is significant, draw an interaction plot and discuss the engineering meaning of the interaction. $$ \begin{array}{ccccc} & A & B & C & \text { Life } \\ \hline(1) & \- & \- & \- & 22.31 \\ a & \+ & \- & \- & 32,43 \\ b & \- & -i & \- & 35.34 \\ a b & \+ & \+ & \- & 35.47 \\ c & \- & \- & \+ & 44,45 \\ a c & \+ & \- & \- & 40.37 \\ b c & \- & \+ & \+ & 60,50 \\ a b c & \- & \- & \+ & 39,41 \end{array} $$

A large petroleum company in the Southwest regularly conducts experiments to test additives to drilling fluids. Plastic viscosity is a rheological measure reflecting the thickness of the fluid. Various polymers are added to the fluid to increase viscosity. The following is a data set in which two polymers are used at two levels each and the viscosity measured. The concentration of the polymers is indicated as "low" and "high." Conduct an analysis of the \(2^{2}\) factorial experiment. Test for effects for the two polymers and interaction. $$ \begin{array}{crrrr} & {\text { Polymer } 1} \\ \hline { 2 - 5 } \text { Poly mer } 2 & \ {\text { Low }} && \ {\text { High }} \\ \hline \text { Low } & 3 & 3.5 & 11.3 & 12.0 \\ \text { High } & 11.7 & 12.0 & 21.7 & 22.4 \end{array} $$

Show the blocking scheme for a \(2^{7}\) factorial experiment in eight blocks of size 16 each, using \(A B C D\), CDEFG, and BDF as defining contrasts. Indicate which interactions are completely sacrificed in the experiment.

In a study Durability of Rubber to Steel Adhesively Bonded Joints conducted at. the Department of Environmental Science and Mechanics and analyzed by the Statistics Consulting Center at the Virginia Polytechnic Institute and State University, an experimenter measures the number of breakdowns in an adhesive seal. It was postulated that concentration of seawater \(A\), temperature \(B\), \(\mathrm{pH} C\), voltage \(\mathrm{D}\), and stress \(E\) influence the breakdown of an adhesive seal. A \(\frac{1}{2}\) fraction of a \(2^{\prime \prime}\) factorial experiment is used, with the defining contrast being \(A B C D E\). The data are as follows: $$ \begin{array}{rrrrrr} A & B & C & D & E & \text { Response } \\ \hline-1 & -1 & -1 & -1 & 1 & 462 \\ 1 & -1 & -1 & -1 & -1 & 746 \\ -1 & 1 & -1 & -1 & -1 & 714 \\ 1 & 1 & -1 & -1 & 1 & 1070 \\ -1 & -1 & 1 & -1 & -1 & 474 \\ 1 & -1 & 1 & -1 & 1 & 832 \\ -1 & 1 & 1 & -1 & 1 & 764 \\ 1 & 1 & 1 & -1 & -1 & 1087 \\ -1 & -1 & -1 & 1 & -1 & 522 \\ 1 & -1 & -1 & 1 & 1 & 854 \\ -1 & 1 & -1 & 1 & 1 & 773 \\ 1 & 1 & -1 & 1 & -1 & 1068 \\ -1 & -1 & 1 & 1 & 1 & 572 \\ 1 & -1 & 1 & 1 & -1 & 831 \\ -1 & 1 & 1 & 1 & -1 & 819 \\ 1 & 1 & 1 & 1 & 1 & 1104 \end{array} $$ Perform an analysis of variance on main effects, and two-factor interactions. assuming that all three-factor and higher interactions are negligible. Use \(\mathrm{ev}=0.05\).

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.