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Large-Sample Test of \(a^{2}=\sigma_{0}^{2}\). When \(n \geq\) 30 we can test the null hypothesis that \(\sigma^{2}=a_{5}^{2}\) or \(\sigma-\) (Ta, by computing $$z=\frac{s+\sigma_{0}}{\sigma_{0} / \sqrt{2 n}}$$ which is a value of a random variable whose sampling distribution is approximately the standard normal distribution (a) With reference to Example 10.5 , test at the 0.05 level of significance whether \(\sigma=10.0\) years against the alternative that \(\sigma \neq 10.0\) years. (b) It is suspected that the variance of the distribution of distances in kilometers achieved per 5 liters of fuel by a new automobile model equipped with a diesel engine is less than the variance of the distribution of distances achieved by the same model equipped with a six-cylinder gasoline engine, which is known to be \(\sigma^{2}=6.25\). If 72 test runs in the diesel model have a variance of 4.41 , ean we conclude at the 0.05 level of significance that the variance of the distances achicved by the: diesel model is less than that of the gasoline model?

Short Answer

Expert verified
(a) The conclusion whether \(\sigma\) equals 10 years or not is based on the p-value. If p-value < 0.05, \(\sigma\) is not equal to 10 years. \n(b) The conclusion about the variances of the diesel and gasoline models is also based on the p-value. If p-value < 0.05, the variance for the diesel model is less than that for the gasoline model.

Step by step solution

01

State the Hypotheses

First, state the null hypothesis and the alternative hypothesis. \n(a) For the first part, the Null Hypothesis (H0) is \(\sigma^{2}= 10^{2}\) and the alternative hypothesis (Ha) is \(\sigma^{2}\neq 10^{2}\). \n(b) For the second part, the Null Hypothesis (H0) is \(\sigma^{2}= 6.25\) and the alternative hypothesis (Ha) is \(\sigma^{2}< 6.25\).
02

Compute Test Statistic

(a) Using the formula for test statistic \(z=\frac{s-\sigma_{0}}{\sigma_{0} / \sqrt{2n}}\), we get \(z = (s - 10) / (10 / \sqrt{2n})\). \n(b) Using the same formula, we get \(z = (s - 6.25) / (6.25 / \sqrt{2*72})\). Substitute the given value of s in both cases.
03

Find P-Value

Compare the calculated test statistic z with the standard normal distribution table to find the corresponding p-value. If the p-value is less than the significance level (0.05), we reject the null hypothesis, otherwise we fail to reject it.
04

Conclusion

(a) If the p-value is less than 0.05, we conclude that \(\sigma\) does not equal 10 years. If the p-value is greater than 0.05, we cannot reject the null hypothesis that \(\sigma = 10\) years. \n(b) If the p-value is less than 0.05, we conclude that the variance of distances covered by the diesel model is less than those by gasoline model. If the p-value is greater than 0.05, we cannot reject the null hypothesis that the variances are equal.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Null and Alternative Hypotheses
In large-sample hypothesis testing, we begin by specifying the null hypothesis (H0), which is a statement of no effect or no difference, and represents a default position that suggests no change or no association. For instance, if we are testing a certain variance, the null hypothesis would assert that the population variance equals a specific value, say \( \sigma_{0}^{2} \).

Conversely, the alternative hypothesis (Ha or H1), proposes what we suspect might be true instead. It typically reflects the effect or difference we are seeking evidence for in our hypothesis test. The alternative hypothesis is often framed as the complement of the null hypothesis, and it can be directional, indicating a specific direction of the effect (like 'greater than' or 'less than'), or non-directional, indicating an effect without a specified direction (simply 'not equal').

In the exercise, we encountered two scenarios: in part (a), the assumption was that the variance was equal to a specific value, forming the basis for the null hypothesis. The alternative suggested that the variance was different. In part (b), the alternative hypothesis was one-sided, conjecturing that the variance was less than a certain value. Properly setting up these hypotheses is crucial for guiding the rest of the hypothesis testing process.
Test Statistic Computation
The test statistic is a standardized value that is calculated from sample data during a hypothesis test. It's designed to measure how far our sample statistic deviates from the null hypothesis, and it serves as the basis for deciding whether to reject the null hypothesis. In variance testing for large samples, the test statistic often assumes a standard normal distribution when the sample size \( n \) is large enough (usually \( n \geq 30 \)).

For variance comparison, the test statistic formula is given by \( z = \frac{s-\sigma_{0}}{\sigma_{0} / \sqrt{2n}} \), where \( s \) is the sample variance, \( \sigma_{0} \) is the hypothesized population variance, and \( n \) is the sample size. The calculation of this statistic allows us to quantify the variance from the hypothesized value in terms of the standard error. In our exercise, we computed this statistic using the given sample variances and sample sizes to determine if there was a significant difference from the hypothesized variances.
P-value Significance Testing
After computing the test statistic, we need to determine the p-value, which is the probability of observing a test statistic as extreme as, or more extreme than, the observed value if the null hypothesis is true. The p-value provides a metric for comparing the observed data to what we would expect to see if the null hypothesis were correct.

If the p-value is less than the significance level, often denoted by \( \alpha \), we have sufficient evidence to reject the null hypothesis. Conversely, if the p-value is greater than or equal to the significance level, we fail to reject the null hypothesis. The significance level is a threshold set by the researcher, commonly at 0.05, which indicates a 5% risk of concluding that a difference exists when there is no actual difference.

In the textbook solution, the p-value is compared to a significance level of 0.05 to decide whether the observed data is significantly different from what the null hypothesis would predict. The p-value is a crucial concept as it quantifies the evidence against the null hypothesis.
Variance Comparison
When we speak of variance comparison, we are interested in understanding how two variances — often representing variability in two different groups or conditions — relate to each other. Variance is a measure of the spread or dispersion of a set of values, and comparing variances allows us to assess whether there are significant differences between groups or conditions.

In large-sample hypothesis testing scenarios dealing with variance, if the sample sizes are large enough, we can use z-tests to make our comparisons due to the Central Limit Theorem, which states that the sampling distribution of the sample mean (or variance) will be approximately normally distributed, regardless of the underlying distribution, given a sufficiently large sample size.

In the exercise provided, we compared the variance of distances achieved per unit of fuel by different automobile models to determine if there was a statistically significant difference. This comparison is analogous to asking, 'Is the variability in one group different from the variability in another?' Such evaluations can be fundamental in fields like quality control, where consistency is vital, or in studies that aim to compare the variability of traits between different populations or treatments.

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Most popular questions from this chapter

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