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91Ó°ÊÓ

In a research report by Richard H. Weindruch of the UCLA Medical School, it is claimed that mice with an average life span of 32 months will live to be about 40 months old when \(40 \%\) of the calories in their food are replaced by vitamins and protein. Is there any reason to believe that \(\mu<40\) if 64 mice that are placed on this diet have an average life of 38 months with a standard deviation of 5.8 months? Use a P-value in your conclusion.

Short Answer

Expert verified
The specific conclusion depends on the calculated P-value. If the P-value derived from the sample is smaller or equal to 0.05, then there is sufficient evidence to conclude that the diet decreases the lifespan of the mice. If the P-value is greater than 0.05, the evidence is insufficient, and it cannot be concluded that the diet affects the lifespan in any way.

Step by step solution

01

State the Hypotheses

The null hypothesis (\(H_0\)) is that the population mean (\(\mu\)) is equal to 40 months, which means that the diet has no effect. The alternative hypothesis (\(H_1\)) is that the mean is less than 40 months, which would indicate that the diet actually decreases lifespan. Therefore, we set up the hypotheses as follows: \(H_0: \mu = 40\) and \(H_1: \mu < 40\).
02

Calculate the Test Statistic

The test statistic for a hypothesis test about a population mean when the population standard deviation is unknown and the sample size is large can be obtained using the formula \(Z = \frac{x - \mu_0}{\sigma/\sqrt{n}}\). Here, \(x\) is the sample mean (38 months), \(\mu_0\) is the hypothesized value of the population mean (40 months), \(\sigma\) is the sample standard deviation (5.8 months), and \(n\) is the sample size (64 mice). Substituting these values into the formula, we get: \(Z = \frac{38 - 40}{5.8/\sqrt{64}}\).
03

Find the P-Value

The P-value is the probability that we would obtain a test statistic as extreme as the one we calculated, assuming the null hypothesis is true. It can be obtained by looking up the calculated Z-score in a standard normal distribution table or by using a statistical calculator. A smaller P-value implies stronger evidence against the null hypothesis.
04

Make the Decision

If the P-value is less than or equal to the significance level (typically 0.05), we reject the null hypothesis. If the P-value is greater than the significance level, we do not have sufficient evidence to reject the null hypothesis. In other words, a small P-value (typically ≤ 0.05) indicates strong evidence against the null hypothesis, so we reject the null hypothesis. A large P-value (> 0.05) indicates weak evidence against the null hypothesis, so we fail to reject the null hypothesis.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Null and Alternative Hypothesis
The null and alternative hypotheses are the starting points of any hypothesis test in statistics. They are two mutually exclusive statements about a population parameter such as the mean (\(\mu\)). The null hypothesis (\(H_0\)) represents a theory that has not yet been proven wrong, therefore it's normally assumed to be true until evidence suggests otherwise. It sets the benchmark for measuring the probability of an observed outcome under the assumption that there's no effect or no difference. In contrast, the alternative hypothesis (\(H_1\) or \(H_a\)) reflects what a researcher is trying to prove or substantiate – it's the statement that there is a statistically significant effect or difference.

For example, concerning the life span of mice, our null hypothesis (\(H_0\)) is \(\mu = 40\) months, meaning the new diet does not affect longevity. Conversely, the alternative hypothesis (\(H_1\)) is \(\mu < 40\) months, indicating that the diet may decrease the lifespan. The test will determine which hypothesis the data supports more strongly.
Test Statistic Calculation
The test statistic is a numerical value used in statistical hypothesis testing to decide whether to reject the null hypothesis. It is calculated based on sample data and measures the degree to which the sample deviates from what would be expected under the null hypothesis. If the test statistic falls into a critical region determined by the significance level of the test, the null hypothesis is rejected.

In our mice lifespan example, the Z-score is the test statistic used. It's computed using the formula \(Z = \frac{x - \mu_0}{\sigma/\sqrt{n}}\), where \(x\) is the sample mean, \(\mu_0\) is the null hypothesis mean, \(\sigma\) is the standard deviation, and \(n\) is the sample size. For the given data, substituting these into the formula yields a test statistic that can be used to ascertain how significantly the sample mean deviates from the hypothesized population mean.
P-value Interpretation
The P-value is a crucial concept in deciding the outcome of a hypothesis test. It's the probability of obtaining test results at least as extreme as the ones observed during the test, under the assumption that the null hypothesis is correct. Essentially, it quantifies the strength of the evidence against the null hypothesis.

A low P-value (\(\leq 0.05\) typically) indicates that the observed data is unlikely under the null hypothesis – pushing researchers to reject the null hypothesis. In the context of our mice diet study, by calculating the P-value, we can gauge the credibility of the null hypothesis (\(H_0: \mu = 40\)) given the observed average life span of the mice. A small P-value would suggest that the alternative hypothesis (\(H_1: \mu < 40\)) may be the more plausible scenario.
Decision Making in Hypothesis Testing
The ultimate goal in hypothesis testing is making a decision about the null hypothesis' validity based on the P-value. The decision rule is generally cut and dry: if the P-value is less than or equal to the predetermined significance threshold, often 0.05, the null hypothesis is rejected. This would mean accepting the alternative hypothesis as more likely given the data.

For our mice diet example, if the P-value calculated from the test statistic is low enough, it would lead us to conclude that there is significant evidence that the diet is associated with a decrease in lifespan, contradicting the initial claim. This process of using the P-value to make a decision is vital because it helps uphold the integrity of statistical analysis, ensuring that conclusions are not made arbitrarily but are instead based on reliable evidence and sound reasoning.

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Most popular questions from this chapter

In a study on the fertility of married women conducted by Martin O'Connell and Carolyn C. Rogers for the Census Bureau in 1979 , two groups of childless wives aged 25 to 29 were selected at random and each wife was asked if she eventually planned to have a child. One group was selected from among those wives married less than two years and the other from among those wives married five years. Suppose that 240 of 300 wives married less than two years planned to have children some day compared to 288 of the 400 wives married five years, Can we conclude that the proportion of wives married less than two years who planned to have children is significantly higher than the proportion of wives married five years? Make use of a P-value

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