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In the publication Relief from Arthritis by Thorsons Publishers L.td. John E Croft claims that over \(40 \%\) of the sufferers from osteoarthritis received measurable relief from an ingredient produced by a particular species of mussel found off the eoust of New Zealand. To test this claim, the mussel extract is to be given to a group of 7 osteonrthritic patients. If or more of the patients roccive relief, we shall not re-ject the null hypothesis that \(p=0.4\); otherwise, we conclude that \(p<0.4\) (a) Evaluate a, assuming that \(p=0.4\). (b) Evaluate \(\beta\) for the alternative \(p=0.3\).

Short Answer

Expert verified
Assuming that \(p = 0.4\) would allow for the calculation of the Type I error 'a'. Similarly, assuming the alternative hypothesis \(p = 0.3\) helps to evaluate the Type II error '\(\beta\)'. These errors provide critical insights when deciding on a hypothesis in a statistical testing context.

Step by step solution

01

Setup the problem

Firstly, denote 'a' as the probability of a Type I error, which is the error of rejecting a true null hypothesis. Then, denote '\(\beta\)' as the probability of a Type II error, which is the error of failing to reject a false null hypothesis. Given that the mussel extract would be given to 7 patients, and it would be assumed the null hypothesis is true if 4 or more patients receive relief, therefore \(p = 0.4\). In this case, we are given to evaluate 'a' assuming \(p = 0.4\) and '\(\beta\)' for the alternative \(p = 0.3\).
02

Calculate 'a' (Probability of Type I error)

The given exercise indicates we would reject the null hypothesis when less than 4 patients out of 7 receive relief. This means we would mistakenly accept the null hypothesis (Type I error) when 4 or more patients receive relief. This situation can be represented by the formula for binomial probability:\[ P(X \geq 4) = P(X=4) + P(X=5) + P(X=6) + P(X=7) \]where \(X\) is the random variable representing the number of patients who receive relief, which follows a binomial distribution with parameters \(n = 7\) (number of trials) and \(p = 0.4\) (success probability). Now, apply the formula for binomial probability to each term of the above equation,
03

Calculate '\(\beta\)' (Probability of Type II error)

Now we will calculate '\(\beta\)', the probability of a Type II error, which occurs when we fail to reject a false null hypothesis. This means we should have rejected the null hypothesis, but we did not. If the true probability \(p\) is less than 0.4, say 0.3, then we wrongly fail to reject the null hypothesis when 4 or more patients receive relief. This situation can be represented by the same formula mentioned in step 2, where now \(p = 0.3\). Use the formula for binomial probability to compute the terms of the equation.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Binomial Distribution
The binomial distribution is a probability distribution that summarizes the likelihood that a variable will take one of two independent values under a given set of parameters. In our exercise, it models the number of patients experiencing relief from osteoarthritis after receiving a mussel extract.
Here, the number of trials is 7, corresponding to the 7 patients, and the probability of success is assumed to be 0.4, meaning there's a 40% chance a patient experiences relief.
The formula to calculate the probability of getting exactly k successes in n trials is \[ P(X = k) = \binom{n}{k} p^k (1-p)^{n-k} \] where \( \binom{n}{k} \) is the binomial coefficient. For the exercise, various probabilities such as \(P(X = 4)\) need to be computed.
Type I Error
A Type I error occurs when we incorrectly reject a true null hypothesis. In the context of hypothesis testing, it's akin to a false positive.
In our example, this would mean concluding the mussel extract does not meet the claimed 40% relief rate when it actually does, due to random variance in testing.
In statistical terms, this is represented by the probability \( \alpha \), which is calculated as the likelihood of getting 4 or more patients (out of 7) experiencing relief when the true success rate is 0.4.
This essentially involves summing up the probabilities of getting 4, 5, 6, or 7 successful outcomes using the binomial formula with \( p = 0.4 \).
Type II Error
Type II error happens when we fail to reject a false null hypothesis. This can be seen as a false negative.
For the mussel extract test, a Type II error would occur if we accepted that the mussel extract has at least a 40% relief rate when the true rate is actually lower, like 30%.
The probability of a Type II error, denoted by \( \beta \), is calculated as the chance of getting a misleading result (4 or more patients feeling relief) when the actual probability is lower (\( p = 0.3 \)).
This involves using the binomial distribution with the alternative hypothesis success rate, and summing the probabilities of 4 to 7 successes.
Null Hypothesis
The null hypothesis is a statement we assume to be true until evidence suggests otherwise. It's the starting point for any hypothesis test.
In the arthritis relief example, the null hypothesis posits that at least 40% of patients will experience relief from the mussel extract, symbolically written as \( p = 0.4 \).
The analysis involves testing this claim by observing the outcomes from 7 patients. If fewer than 4 out of the 7 patients report relief, we might suspect that the true relief rate is lower, prompting a potential rejection of this null hypothesis.
The process requires calculating the Type I and Type II errors to understand the likelihood of making incorrect decisions about this hypothesis.

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