/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 101 A geneticist is interested in th... [FREE SOLUTION] | 91Ó°ÊÓ

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A geneticist is interested in the proportion of males and females in a population that have a certain minor blood disorder. In a random sample of 100 males, 31 are found to be aftlicted, whereas only 24 of 100 females tested appear to have the disorder. Can we conclude at the 0.01 level of significance that the proportion of men in the population afflicted with this blood disorder is significantly greater than the proportion of women afflicted?

Short Answer

Expert verified
If the p-value obtained is less than 0.01, we conclude that the proportion of men with the blood disorder is significantly higher than women at the 0.01 significance level. Otherwise, we do not have enough evidence to conclude so.

Step by step solution

01

Set up the Hypotheses

The objective is to check if the proportion of men with the disorder (\( p_m \)) is greater than that of women (\( p_f \)). Thus, the null hypothesis (\( H_0 \)) is \( p_m = p_f \) and the alternative hypothesis (\( H_A \)) is \( p_m > p_f \).
02

Calculate the Test Statistics

First, calculate the sample proportions for men and women separately. For men: \( \hat{p}_m = \frac{31}{100} \). For women: \( \hat{p}_f = \frac{24}{100} \). Then, calculate the combined sample proportion (\( \hat{p} \)) as \( \frac{31+24}{100+100} \). The z-score is given by \( \frac{\hat{p}_m - \hat{p}_f}{\sqrt{\frac{\hat{p}(1-\hat{p})}{100} + \frac{\hat{p}(1-\hat{p})}{100}} } \).
03

Find the P-value and Make a Conclusion

Our test is a right-tailed test because the alternative hypothesis says greater than. After finding the z-score, look it up in the z-table or use a statistical software to find the p-value. If the p-value is less than the level of significance (0.01), then reject the null hypothesis.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Proportion Hypothesis Test
A proportion hypothesis test is a statistical tool used to determine if there is a significant difference between the proportions of a certain characteristic within two or more groups. In the geneticist's study,
the objective is to compare the proportion of males (\( p_m \)) and females (\( p_f \)) afflicted with a blood disorder. To conduct this test, two hypotheses are set up: a null hypothesis (\( H_0 \)), which posits that there is no difference between the proportions (\( p_m = p_f \)), and an alternative hypothesis (\( H_A \)), which suggests that the proportion of afflicted males is greater than that of females (\( p_m > p_f \)).

The hypothesis test involves calculating the differences between the observed sample proportions and then assessing whether this observed difference is statistically significant. It is also important to define the level of significance, which in this case is 0.01. This value represents the threshold for deciding whether the observed data could occur by random chance, or whether it indicates a real difference between the proportions.
Statistical Significance
Statistical significance plays a central role in hypothesis testing as it helps to determine whether the results of the test are not due to random chance. Significance is usually denoted by a p-value, which is the probability of observing a test statistic at least as extreme as the one calculated from your sample data, under the assumption that the null hypothesis is true.

For the given problem, the level of significance is set at 0.01. This threshold means there is only a 1% chance that we would observe such a difference between the male and female proportions if, in reality, no difference exists (i.e., if the null hypothesis holds true). If the p-value obtained from the test statistic is less than 0.01, the result is considered statistically significant, and we reject the null hypothesis, indicating that the difference in proportions is unlikely to have occurred by chance alone.
Z-score Calculation
The z-score is a statistical measure that tells us how many standard deviations an element is from the mean. In the context of hypothesis testing for proportions, it quantifies the difference between the observed sample proportion and the hypothesized population proportion, in units of standard error. Calculating the z-score involves several steps. First, the sample proportions are computed. Then a combined sample proportion is found by pooling the samples, useful for estimating the standard error.

For the male and female proportions given in the exercise, the z-score calculation is based on the difference between the two sample proportions (\( \hat{p}_m - \hat{p}_f \)). To standardize this difference, it is divided by the standard error of the proportion difference, which is derived from the combined sample proportion. A higher z-score means a larger difference between the sample proportions, informing us about the likelihood of the result if the null hypothesis were true. If the absolute value of the z-score falls beyond the critical value corresponding to the significance level, we conclude that the difference in proportions is statistically significant.

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