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Annie and Alvie have agreed to meet between 5:00 P.M. and 6:00 P.M. for dinner at a local health-food restaurant. Let \(X=\) Annie's arrival time and \(Y=\) Alvie's arrival time. Suppose \(X\) and \(Y\) are independent with each uniformly distributed on the interval \([5,6]\). a. What is the joint pdf of \(X\) and \(Y\) ? b. What is the probability that they both arrive between \(5: 15\) and \(5: 45 ?\) c. If the first one to arrive will wait only \(10 \mathrm{~min}\) before leaving to eat elsewhere, what is the probability that they have dinner at the health- food restaurant? [Hint: The event of interest is \(A=\left\\{(x, y):|x-y| \leq \frac{1}{6}\right\\}\).

Short Answer

Expert verified
a. 1; b. 0.25; c. \(\frac{2}{3}\)

Step by step solution

01

Understanding Joint PDF

Since Annie and Alvie's arrival times are independent and uniformly distributed, each over the interval \([5, 6]\), the joint probability density function (pdf) of \(X\) and \(Y\) is given by the product of their individual pdfs. Thus, the joint pdf is constant over the region and is given by:\[f(x, y) = f_X(x) \cdot f_Y(y) = 1 \cdot 1 = 1, \quad \text{for } 5 \leq x \leq 6 \text{ and } 5 \leq y \leq 6.\]
02

Probability between Time Intervals

To find the probability that both arrive between \(5:15\) and \(5:45\), we calculate the area of the square where both \(X\) and \(Y\) are in the interval \([5.25, 5.75]\). The length of each side of the square is \(5.75 - 5.25 = 0.5\). Thus, the probability is:\[P(5.25 \leq X \leq 5.75, 5.25 \leq Y \leq 5.75) = 0.5 \cdot 0.5 = 0.25.\]
03

Probability of Meeting Within 10 Minutes

The event \(A\) where they meet after waiting at most 10 minutes is defined by the condition \(|X - Y| \leq \frac{1}{6}\), which equates to a wait time of \(10\) minutes out of \(60\) minutes. Geometrically, this is the area between two diagonal lines: \(y = x + \frac{1}{6}\) and \(y = x - \frac{1}{6}\). The region of interest forms a band centered on the line \(y = x\) with width \(\frac{1}{3}\). The length of the square's diagonal, fitting the interval \([5,6]\), is \(\sqrt{2}\). The band forms a rhombus inside the square, split diagonally along the line \(y = x\). The area of this rhombus is:\[\text{Diagonal 1} = \frac{1}{3} \cdot \sqrt{2} \cdot 2 = \frac{2\sqrt{2}}{3}, \quad \text{Diagonal 2} = \sqrt{2}\]Therefore, the area of the rhombus is:\[\text{Area} = \frac{1}{2} \cdot \frac{2\sqrt{2}}{3} \cdot \sqrt{2} = \frac{2}{3}.\]Thus, the probability is \(\frac{2}{3}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Uniform Distribution
In probability theory, a uniform distribution is one of the simplest forms of distributions that we encounter. Imagine a situation where an event is equally possible at every given point within a certain range. This is what a uniform distribution represents. For example, Annie and Alvie's arrival times are uniformly distributed in the interval \([5,6]\), meaning that every moment within this hour is equally likely for their arrival.
Such distributions are often continuous, meaning that they can represent an infinite number of possible outcomes over a specified range. The uniform distribution is defined by its constant density, indicating that no single point is more probable than another in the given interval. This characteristic simplifies calculations because it suggests uniformity or equality across the board, whether we are calculating individual or joint probabilities.
Probability Density Function
The probability density function (pdf) is a fundamental concept in the field of statistics and probability. It serves as the backbone for understanding continuous random variables like the ones in our problem. For a continuous random variable, a pdf provides a way to describe the likelihood of the variable taking on a particular value.
The pdf described in the exercise is constant because of the uniform distribution. For instance, since Annie and Alvie are both equally likely to arrive at any given time from 5 P.M. to 6 P.M., the joint pdf for their arrival times is constant over the interval. It is calculated by multiplying their individual pdfs. In our scenario, the pdf for each variable \(f_X(x)\) and \(f_Y(y)\) is 1, resulting in a joint pdf \(f(x, y) = 1\). This effectively means that within the specified interval, every possible combination of arrival times is equally probable.
Independent Random Variables
Independence is a crucial property when dealing with random variables. Two random variables are independent if the occurrence of one does not affect the occurrence of the other. In our given problem, Annie's and Alvie's arrival times \(X\) and \(Y\) are considered independent.
This independence implies that the joint probability distribution is simply the product of the individual distributions. Consequently, knowing the arrival time of one friend does not provide any information about the arrival time of the other. This characteristic allows us to calculate probabilities easily by using the multiplication rule for independent events, as we see when deriving the joint probability density function.
Probability Calculation
Probability calculations involve determining the likelihood of certain events within defined conditions. In our example, multiple scenarios are explored using probability formulas and understandings. For instance, assessing the probability that both friends show up within a certain 30-minute window involves calculating the area they are both likely to overlap, considering their uniform distribution.
To calculate the probability that they meet within a certain time frame, given as 10 minutes, we need to consider more complex geometry. In this case, it involves finding the area of overlap (rhombus) on the graph of their arrival times. This requires understanding the geometrical representation of probabilities and how the interval of overlap translates into probabilistic terms. The calculations eventually show us how to determine the likelihood of these specific events occurring, offering real-world implications for straightforward scenarios.

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Most popular questions from this chapter

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