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The breaking strength of a rivet has a mean value of 10,000 psi and a standard deviation of \(500 \mathrm{psi}\). a. What is the probability that the sample mean breaking strength for a random sample of 40 rivets is between 9900 and 10,200 ? b. If the sample size had been 15 rather than 40 , could the probability requested in part (a) be calculated from the given information?

Short Answer

Expert verified
a: 0.8923. b: No, because the sample size of 15 is too small for the Central Limit Theorem.

Step by step solution

01

Understand the Central Limit Theorem

The Central Limit Theorem states that the sampling distribution of the sample mean will be approximately normally distributed if the sample size is large enough, typically 30 or more. It allows us to use the normal distribution as an approximation even if the original distribution of the data is not normal.
02

Calculate the Standard Error

For a sample mean, the standard error (SE) is the standard deviation of the population divided by the square root of the sample size. Here, the standard deviation is 500 psi and the sample size is 40.\[ SE = \frac{\sigma}{\sqrt{n}} = \frac{500}{\sqrt{40}} \approx 79.06 \; \text{psi} \]
03

Calculate Z-scores for the Sample Mean Range

Convert the range 9900 to 10200 psi to Z-scores to find the probability. Use the formula:\[ Z = \frac{X - \mu}{SE} \]For 9900:\[ Z = \frac{9900 - 10000}{79.06} \approx -1.27 \]For 10200:\[ Z = \frac{10200 - 10000}{79.06} \approx 2.53 \]
04

Find the Probability Using Z-scores

Using the standard normal distribution table or a calculator, find the probability for each Z-score.The probability for Z = -1.27 is approximately 0.1020, and for Z = 2.53, it's approximately 0.9943. Therefore, the probability that the sample mean falls between 9900 and 10200 psi is:\[ P(-1.27 < Z < 2.53) = 0.9943 - 0.1020 = 0.8923 \]
05

Evaluate Sample Size of 15

Since the sample size of 15 is smaller than the typical threshold of 30, the Central Limit Theorem does not assure that the sampling distribution of the sample mean is approximately normal. Without additional information about the original distribution, the probability cannot be accurately calculated. A larger sample size or knowledge of the original distribution's shape is required.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Standard Error
The standard error (SE) gives us an understanding of how much the sample mean is expected to vary from the actual population mean. It's a crucial part of making predictions and estimations about a sample. To calculate the standard error, divide the population's standard deviation by the square root of the sample size. For instance, in the problem provided, the standard deviation is given as 500 psi, and the sample size is 40. Therefore, the standard error is calculated as follows:
\[ SE = \frac{\sigma}{\sqrt{n}} = \frac{500}{\sqrt{40}} \approx 79.06 \, \text{psi} \]
This formula tells us that with a larger sample size, the standard error decreases. This means our sample mean tends to be closer to the population mean as more data points are included, which is helpful for accurate predictions. The standard error is a part of the equation for the Z-score calculation, which we will discuss later.
Normal Distribution
A normal distribution is often described as a 'bell curve' for its distinctive bell shape. In a normal distribution, the data is symmetrically distributed, with most of the occurrences clustering around the central peak, which is the mean, and the probabilities taper off equally on both sides. This pattern arises commonly in nature. The Central Limit Theorem is crucial because it allows us to apply the normal distribution to the means of samples, even if the original data isn't normally distributed.
Knowing the properties of a normal distribution helps in determining probabilities and managing expectations about data tendencies. It provides a framework for making predictions about where data points are likely to fall, enabling us to compute probabilities such as the likelihood that a sample mean falls between two values. This is done under the assumption that the sampling distribution of the sample mean is normal, particularly when sample sizes are large.
Sampling Distribution
The sampling distribution is the probability distribution of a statistic, such as the sample mean, calculated from a set of samples. It helps understand how the statistic would behave if we were to repeatedly draw samples from the same population. Each sample would yield a different sample mean, and the set of these means would form the sampling distribution.
The Central Limit Theorem states that given a sufficiently large sample size, the sampling distribution of the sample mean will be approximately normally distributed, regardless of the shape of the population distribution. A common rule of thumb considers a sample size of 30 or more as large enough. This transformation towards a normal distribution allows us to use Z-scores and standard normal distribution tables to make inferences and calculate probabilities.
Z-score Calculation
Z-score calculation is an essential tool for understanding where a specific data point lies in relation to the rest of the dataset. By converting a data point (or sample mean) into a Z-score, we can determine how many standard deviations it is from the mean. This makes it possible to calculate probabilities using the standard normal distribution.
For the problem at hand, we convert the breaking strengths of 9900 psi and 10200 psi into Z-scores using the formula:
\[ Z = \frac{X - \mu}{SE} \]
Here, \(X\) is the sample mean, \(\mu\) is the population mean, and \(SE\) is the standard error:
For 9900 psi:
\[ Z = \frac{9900 - 10000}{79.06} \approx -1.27 \]
For 10200 psi:
\[ Z = \frac{10200 - 10000}{79.06} \approx 2.53 \]
These Z-scores help us find the probability that the sample mean will fall within this range by using a standard normal distribution table. This probabilistic approach allows for making informed decisions based on statistical evidence and helps answer questions about the dataset.

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