/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 49 There are 40 students in an elem... [FREE SOLUTION] | 91Ó°ÊÓ

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There are 40 students in an elementary statistics class. On the basis of years of experience, the instructor knows that the time needed to grade a randomly chosen first examination paper is a random variable with an expected value of \(6 \mathrm{~min}\) and a standard deviation of \(6 \mathrm{~min}\). a. If grading times are independent and the instructor begins grading at 6:50 P.M. and grades continuously, what is the (approximate) probability that he is through grading before the 11:00 P.M. TV news begins? b. If the sports report begins at \(11: 10\), what is the probability that he misses part of the report if he waits until grading is done before turning on the TV?

Short Answer

Expert verified
a) ~90.66% probability to finish before 11:00 PM; b) ~3.22% chance to miss part of the sports report.

Step by step solution

01

Determine Total Grading Time

Since there are 40 students and the expected grading time for each paper is 6 minutes, calculate the expected total grading time: \( E(T) = 40 \times 6 = 240 \) minutes.
02

Convert Time to Hours and Minutes

Convert the 240 minutes of expected grading time into hours and minutes. \( 240 \text{ minutes} = 4 \text{ hours} \).
03

Calculate Theoretical Completion Time

If grading begins at 6:50 PM, then it is expected to finish at: \( 6:50 \text{ PM} + 4 \text{ hours} = 10:50 \text{ PM} \).
04

Apply the Central Limit Theorem

Use the Central Limit Theorem to approximate the distribution of the total grading time. The sum of independent normally distributed variables results in a normal distribution. Therefore, total grading time \( T \sim N(240, \sqrt{40} \times 6) \). Calculate standard deviation: \( \sigma(T) = \sqrt{40} \cdot 6 = 6\sqrt{40} \approx 37.95 \).
05

Convert News Start Time to Minutes

News starts at 11:00 PM, which is \( 4 \times 60 = 240 \text{ minutes} \) from 6:50 PM.
06

Calculate Z-Score for 11:00 PM Deadline

Calculate the Z-score by finding \( Z = \frac{(290 - 240)}{37.95} \approx 1.32 \).
07

Determine Probability Before TV News

Use a standard normal distribution table to find \( P(Z < 1.32) \approx 0.9066 \). Thus, the probability that grading is complete before 11:00 PM is approximately 90.66%.
08

Convert Sports Report Start Time to Minutes

The sports report begins at 11:10 PM, which is 20 minutes after 11:00 PM, totaling \( 290 + 20 = 310 \text{ minutes} \) from 6:50 PM.
09

Calculate Z-Score for 11:10 PM Deadline

Calculate the new Z-score for 11:10 PM: \( Z = \frac{(310 - 240)}{37.95} \approx 1.85 \).
10

Determine Probability Before Sports Report

Use a standard normal distribution table to find \( P(Z < 1.85) \approx 0.9678 \). Hence, the probability that grading is complete before 11:10 PM is approximately 96.78%. The probability of missing part of the sports report is \( 1 - 0.9678 = 0.0322 \), or 3.22%.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability
In the field of statistics, probability is a crucial concept that quantifies the likelihood of an event occurring. Probability ranges between 0 and 1, where 0 indicates impossibility, and 1 indicates certainty.
In this exercise, probability helps us understand how likely it is that the instructor finishes grading by certain times. For example, calculating when the instructor finishes grading depends on the combined probabilities of individual grading times. Since each grading time is independent, the total probability is calculated using a normal distribution and the central limit theorem, which approximates the total grading time as a normal distribution.
The approximation helps us find probabilities such as the instructor finishing before 11:00 PM, thus more easily planning activities based on critical time frames like TV news or sports reports.
Normal Distribution
In statistics, a normal distribution is a bell-shaped curve that describes how many things cluster around the average. This is important because many real-world outcomes, such as student test scores or adults' heights, follow this pattern. A normal distribution is defined by its mean, or average, and a measure called the standard deviation, which tells us how spread out the values are.
In the context of the problem, the total time it takes the instructor to grade all papers can be seen as a sum of random variables, each representing the grading time for one student. According to the Central Limit Theorem (CLT), the distribution of this sum will be approximately normal, even if the individual grading times aren't. This approximation allows us to calculate probabilities related to the grading completion times by converting them into z-scores and looking up these in the standard normal distribution table. This makes working with averages and unpredictability in grading far more manageable.
Standard Deviation
Standard deviation is a measure of how spread out numbers in a dataset are. A low standard deviation means that the numbers are close to the mean, while a high standard deviation means that the numbers are more spread out.
In our example, the standard deviation of the grading time is given as 6 minutes for one paper. When calculating for multiple papers, the overall standard deviation will change thanks to the central limit theorem. Specifically, for 40 students, the standard deviation of the total grading time is the original standard deviation adjusted by the square root of the number of students. This is expressed mathematically as:
  • Standard deviation of total grading time = 6 minutes × \( \sqrt{40} \)
  • Approximately 37.95 minutes
Understanding standard deviation helps determine how much actual grading time might differ from the expected time, thus influencing the probabilities of finishing before certain deadlines.
Expected Value
The expected value is the mean or average of a random variable; it's what we anticipate if an experiment were repeated numerous times. Think of it as the 'center' of a probability distribution.
In this grading exercise, the expected value for grading time per paper is 6 minutes. For the entire class, we calculate the total expected grading time by multiplying the expected grading time per paper by the number of students:
  • Expected total grading time = 6 minutes per paper × 40 papers = 240 minutes
This expected value serves as our baseline when calculating whether the instructor will finish grading before the news or sports report begins. By using the expected value, we develop a starting point for comparing actual grading performance and associated probabilities.

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