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a. Show that \(\operatorname{Cov}(X, Y+Z)=\operatorname{Cov}(X, Y)+\operatorname{Cov}(X, Z)\). b. Let \(X_{1}\) and \(X_{2}\) be quantitative and verbal scores on one aptitude exam, and let \(Y_{1}\) and \(Y_{2}\) be corresponding scores on another exam. If \(\operatorname{Cov}\left(X_{1}, Y_{1}\right)=5\), \(\operatorname{Cov}\left(X_{1}, Y_{2}\right)=1, \operatorname{Cov}\left(X_{2}, Y_{1}\right)=2\), and \(\operatorname{Cov}\left(X_{2}, Y_{2}\right)=\) 8 , what is the covariance between the two total scores \(X_{1}+X_{2}\) and \(Y_{1}+Y_{2} ?\)

Short Answer

Expert verified
The covariance between total scores is 16.

Step by step solution

01

Understand Covariance Property

Covariance has a linear additive property which helps to decompose the covariance between a random variable and the sum of two other random variables. The property states: \( \operatorname{Cov}(X, Y+Z) = \operatorname{Cov}(X, Y) + \operatorname{Cov}(X, Z) \). This property is vital in statistical predictive models where linear components are frequently decomposed.
02

Prove the Covariance Property

Start from the definition of covariance: \( \operatorname{Cov}(X, Y) = \mathbb{E}[(X - \mathbb{E}[X])(Y - \mathbb{E}[Y])] \). Using this definition, for \( \operatorname{Cov}(X, Y+Z) \), expand it to: \( \mathbb{E}[(X - \mathbb{E}[X])((Y+Z) - \mathbb{E}[Y+Z])] \). This can be rewritten as \( \mathbb{E}[(X - \mathbb{E}[X])(Y - \mathbb{E}[Y] + Z - \mathbb{E}[Z])] \), which expands further to: \( \mathbb{E}[(X - \mathbb{E}[X])(Y - \mathbb{E}[Y])] + \mathbb{E}[(X - \mathbb{E}[X])(Z - \mathbb{E}[Z])] \), proving the property: \( \operatorname{Cov}(X, Y+Z) = \operatorname{Cov}(X, Y) + \operatorname{Cov}(X, Z) \).
03

Express Covariance of Total Scores

For part b, you need to find \( \operatorname{Cov}(X_1 + X_2, Y_1 + Y_2) \). By the linearity of covariance, this transforms to: \( \operatorname{Cov}(X_1, Y_1 + Y_2) + \operatorname{Cov}(X_2, Y_1 + Y_2) \).
04

Apply Linear Covariance Decomposition

Using the property from Step 1, the expression becomes: \( \operatorname{Cov}(X_1, Y_1) + \operatorname{Cov}(X_1, Y_2) + \operatorname{Cov}(X_2, Y_1) + \operatorname{Cov}(X_2, Y_2) \).
05

Substitute Known Values

Substitute the known values from the problem: \( \operatorname{Cov}(X_1, Y_1) = 5 \), \( \operatorname{Cov}(X_1, Y_2) = 1 \), \( \operatorname{Cov}(X_2, Y_1) = 2 \), \( \operatorname{Cov}(X_2, Y_2) = 8 \). The expression becomes: \( 5 + 1 + 2 + 8 \).
06

Calculate Total Covariance

Sum the values to find the total covariance: \( 5 + 1 + 2 + 8 = 16 \). So the covariance between the total scores \( X_1 + X_2 \) and \( Y_1 + Y_2 \) is 16.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Proof of Covariance Properties
Covariance is a crucial concept in statistics that helps us understand the relationship between two random variables. To explore the properties of covariance, let's start with the general property: the covariance between a variable \(X\) and the sum of two other variables \(Y\) and \(Z\). Suppose you want to show that \(\operatorname{Cov}(X, Y+Z) = \operatorname{Cov}(X, Y) + \operatorname{Cov}(X, Z)\). Start by looking at the definition of covariance:\(\operatorname{Cov}(X, Y) = \mathbb{E}[(X - \mathbb{E}[X])(Y - \mathbb{E}[Y])]. \)With this definition, substituting \(Y+Z\) gives:\(\operatorname{Cov}(X, Y+Z) = \mathbb{E}[(X - \mathbb{E}[X])((Y+Z) - \mathbb{E}[Y+Z])].\)Breaking this into simpler parts, it becomes:\(\mathbb{E}[(X - \mathbb{E}[X])(Y - \mathbb{E}[Y] + Z - \mathbb{E}[Z])] = \mathbb{E}[(X - \mathbb{E}[X])(Y - \mathbb{E}[Y])] + \mathbb{E}[(X - \mathbb{E}[X])(Z - \mathbb{E}[Z])].\)Hence, we have:\(\operatorname{Cov}(X, Y) + \operatorname{Cov}(X, Z).\)This shows that covariance has a property of additivity which is rooted in its definition itself.
Linearity of Covariance
The linearity of covariance is an influential principle in statistics. It states that the covariance of a sum of variables can be decomposed into individual covariances. Why is this important? It's because breaking down complex expressions into simpler parts allows for easier computation and understanding. Covariance linearity can be illustrated through the formula:\(\operatorname{Cov}(X_1 + X_2, Y_1 + Y_2) = \operatorname{Cov}(X_1, Y_1) + \operatorname{Cov}(X_1, Y_2) + \operatorname{Cov}(X_2, Y_1) + \operatorname{Cov}(X_2, Y_2).\)What does this mean in practical terms?
  • Each covariance term breaks down relationships between specific pairs of variables.
  • This breakdown can help identify which factors contribute more significantly to the covariances.
  • It simplifies complex covariance calculations, making it much easier to manage randomly behaving elements simultaneously.
For instance, if you had known covariance values for each of those specific pairs and you wanted to find the covariance between sums \(X_1 + X_2\) and \(Y_1 + Y_2\), you could merely add these values as shown. This simplicity is crucial when dealing with multiple variables in statistics.
Covariance in Predictive Models
In predictive models, understanding the interplay between different variables is essential in making accurate predictions. Covariance plays a vital role here by capturing how two variables change together. Let's look into how covariance informs predictive modeling. When developing models, particularly linear regression, covariance offers insights into variable relationships. These relationships help determine:
  • Which variables are positively or negatively related.
  • The degree to which variables move together.
  • Potential dependencies that might affect predictions.
A high positive covariance indicates that as one variable increases, the other tends to increase too. Conversely, a high negative covariance suggests that as one variable rises, the other tends to fall. Such information is crucial when setting up a predictive model as it directly impacts the model’s assumptions and the interactions it needs to consider. In short, covariance not only aids in establishing the relationships within data but also in refining the predictive power of statistical models by ensuring that all significant factor interactions are accounted for efficiently.

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Most popular questions from this chapter

Six individuals, including \(\mathrm{A}\) and \(\mathrm{B}\), take seats around \(\mathrm{a}\) circular table in a completely random fashion. Suppose the seats are numbered \(1, \ldots, 6\). Let \(X=\) A's seat number and \(Y=\mathrm{B}\) 's seat number. If A sends a written message around the table to \(B\) in the direction in which they are closest, how many individuals (including \(A\) and \(B\) ) would you expect to handle the message?

A restaurant serves three fixed-price dinners costing \(\$ 12\), \(\$ 15\), and \(\$ 20\). For a randomly selected couple dining at this restaurant, let \(X=\) the cost of the man's dinner and \(Y=\) the cost of the woman's dinner. The joint pmf of \(X\) and \(Y\) is given in the following table: \begin{tabular}{cc|ccc} \(p(x, y)\) & & 12 & 15 & 20 \\ \hline & 12 & \(.05\) & \(.05\) & \(.10\) \\ \multirow{x}{*}{} & 15 & \(.05\) & \(.10\) & \(.35\) \\ & 20 & 0 & \(.20\) & \(.10\) \end{tabular} a. Compute the marginal pmf's of \(X\) and \(Y\). b. What is the probability that the man's and the woman's dinner cost at most \(\$ 15\) each? c. Are \(X\) and \(Y\) independent? Justify your answer. d. What is the expected total cost of the dinner for the two people? e. Suppose that when a couple opens fortune cookies at the conclusion of the meal, they find the message "You will receive as a refund the difference between the cost of the more expensive and the less expensive meal that you have chosen." How much would the restaurant expect to refund?

a. Use the rules of expected value to show that \(\operatorname{Cov}(a X+b, c Y+d)=a c \operatorname{Cov}(X, Y)\). b. Use part (a) along with the rules of variance and standard deviation to show that \(\operatorname{Corr}(a X+b\), \(c Y+d)=\operatorname{Corr}(X, Y)\) when \(a\) and \(c\) have the same sign. c. What happens if \(a\) and \(c\) have opposite signs?

Let \(X_{1}, X_{2}\), and \(X_{3}\) be the lifetimes of components 1,2 , and 3 in a three-component system. a. How would you define the conditional pdf of \(X_{3}\) given that \(X_{1}=x_{1}\) and \(X_{2}=x_{2}\) ? b. How would you define the conditional joint pdf of \(X_{2}\) and \(X_{3}\) given that \(X_{1}=x_{1}\) ?

Manufacture of a certain component requires three different machining operations. Machining time for each operation has a normal distribution, and the three times are independent of one another. The mean values are 15,30 , and \(20 \mathrm{~min}\), respectively, and the standard deviations are 1,2 , and \(1.5 \mathrm{~min}\), respectively. What is the probability that it takes at most 1 hour of machining time to produce a randomly selected component?

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