/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 36 A rock specimen from a particula... [FREE SOLUTION] | 91Ó°ÊÓ

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A rock specimen from a particular area is randomly selected and weighed two different times. Let \(W\) denote the actual weight and \(X_{1}\) and \(X_{2}\) the two measured weights. Then \(X_{1}=W+E_{1}\) and \(X_{2}=W+E_{2}\), where \(E_{1}\) and \(E_{2}\) are the two measurement errors. Suppose that the \(E_{i}\) 's are independent of one another and of \(W\) and that \(V\left(E_{1}\right)=V\left(E_{2}\right)=\sigma_{E}^{2}\). a. Express \(\rho\), the correlation coefficient between the two measured weights \(X_{1}\) and \(X_{2}\), in terms of \(\sigma_{W}^{2}\), the variance of actual weight, and \(\sigma_{X}^{2}\), the variance of measured weight. b. Compute \(\rho\) when \(\sigma_{W}=1 \mathrm{~kg}\) and \(\sigma_{E}=.01 \mathrm{~kg}\).

Short Answer

Expert verified
a. \(\rho = \frac{\sigma_W^2}{\sigma_W^2 + \sigma_E^2}\). b. \(\rho \approx 0.9999\).

Step by step solution

01

Express the Variance of Measured Weight

We start by understanding the relationship between the measured weights and the actual weight. Given: \[ X_1 = W + E_1 \]\[ X_2 = W + E_2 \]where \(E_1\) and \(E_2\) are errors with variance \(V(E_1) = V(E_2) = \sigma_E^2\). To find \(V(X_1)\) and \(V(X_2)\), apply the properties of variance:\[ V(X_1) = V(W + E_1) = V(W) + V(E_1) = \sigma_W^2 + \sigma_E^2 \]\[ V(X_2) = V(W + E_2) = V(W) + V(E_2) = \sigma_W^2 + \sigma_E^2 \]Hence, the variance of each measured weight, denoted as \(\sigma_X^2\), is \(\sigma_X^2 = \sigma_W^2 + \sigma_E^2\).
02

Calculate the Covariance Between X1 and X2

The covariance between \(X_1\) and \(X_2\) can be expressed as:\[ \text{Cov}(X_1, X_2) = \text{Cov}(W + E_1, W + E_2)\]Using linearity of covariance and the independence assumptions, we have:\[ \text{Cov}(X_1, X_2) = \text{Cov}(W, W) + \text{Cov}(W, E_2) + \text{Cov}(E_1, W) + \text{Cov}(E_1, E_2) \]Since \(W\) and \(E_i\) are independent:\[ \text{Cov}(W, E_1) = 0, \quad \text{Cov}(W, E_2) = 0, \quad \text{Cov}(E_1, E_2) = 0 \]Therefore:\[ \text{Cov}(X_1, X_2) = \text{Cov}(W, W) = V(W) = \sigma_W^2 \]
03

Derive the Formula for the Correlation Coefficient

The correlation coefficient \( \rho \) is defined as:\[ \rho = \frac{\text{Cov}(X_1, X_2)}{\sqrt{V(X_1)V(X_2)}} \]Substitute our previous expressions:\[ \rho = \frac{\sigma_W^2}{\sqrt{(\sigma_W^2 + \sigma_E^2)(\sigma_W^2 + \sigma_E^2)}} \]\[ \rho = \frac{\sigma_W^2}{\sigma_W^2 + \sigma_E^2} \]
04

Compute Rho with Given Variances

Now, compute \(\rho\) using the given values \(\sigma_W = 1\, \text{kg}\) and \(\sigma_E = 0.01\, \text{kg}\):\[ \rho = \frac{1^2}{1^2 + 0.01^2} = \frac{1}{1 + 0.0001} \]\[ \rho = \frac{1}{1.0001} \approx 0.9999 \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Correlation Coefficient
Determining the relationship between two variables often involves calculating the correlation coefficient. The correlation coefficient, denoted as \( \rho \), measures the strength and direction of a linear relationship between two random variables. In the context of the original exercise, it is used to assess the degree to which the two measured weights \( X_1 \) and \( X_2 \) of a rock specimen are related.
The formula for the correlation coefficient is expressed as:
  • \( \rho = \frac{\text{Cov}(X_1, X_2)}{\sqrt{V(X_1) V(X_2)}} \)
The value of \( \rho \) ranges between -1 and 1. A \( \rho \) value of 1 indicates a perfect positive linear relationship, -1 represents a perfect negative linear relationship, and 0 signifies no linear relationship.
In our exercise, by substituting the appropriate variances and covariance values, we found that \( \rho \) is approximately 0.9999, indicating an almost perfect positive correlation between the two measured weights.
Variance
Variance is a statistical measure that describes the spread of a set of data points around their mean value. It indicates how much the values in a dataset differ from the mean. In this exercise, the concept of variance helps understand the variability in the actual weight \( W \) and the measured weights \( X_1 \) and \( X_2 \).
Variance is calculated as:
  • For a random variable \( X \), \( V(X) = \text{E}[(X - \mu)^2] \)
Where \( \mu \) is the mean of \( X \).
In the given problem, the variance of the actual weight \( W \) is \( \sigma_W^2 \), and the variance of the measurement errors \( E_1 \) and \( E_2 \) is \( \sigma_E^2 \). The variance of each measured weight \( X \) is then given by \( V(X) = \sigma_W^2 + \sigma_E^2 \).
This shows how both the natural variation of the rock's weight and measurement errors contribute to the overall variance of the data.
Measurement Errors
Measurement errors are discrepancies between the true value and the observed value due to imperfections in the measurement process. In scientific experiments or daily measurements, these errors can affect the accuracy and reliability of results.
In our exercise, each measured weight \( X_1 \) and \( X_2 \) incorporates a measurement error \( E_1 \) and \( E_2 \) respectively. The errors are assumed independent, meaning they don't affect each other and have constant variance \( \sigma_E^2 \).
Understanding that measurement errors are independent and identically distributed helps simplify statistical analyses, like calculating the overall variance or assessing correlation. This independence assumption also contributes to the conclusion that the covariance of errors is zero, impacting our calculation for the covariance between the measured weights.
Covariance
Covariance is a measure of how changes in one variable relate to changes in another. It helps identify whether an increase in one variable suggests an increase or decrease in another variable, implying a positive or negative relationship.
The formula for covariance between two variables \( X \) and \( Y \) is:
  • \( \text{Cov}(X, Y) = \text{E}[(X - \mu_X)(Y - \mu_Y)] \)
Where \( \mu_X \) and \( \mu_Y \) are the means of \( X \) and \( Y \), respectively.
In the problem, we calculate \( \text{Cov}(X_1, X_2) \) and utilize this to find the correlation coefficient. We apply the properties that the covariance of an independent variable with itself is its variance – specifically, \( \text{Cov}(W, W) = V(W) = \sigma_W^2 \).
Recognizing zero covariance between independent errors \( E_1 \) and \( E_2 \) is crucial, as including these would inaccurately reflect dependencies that don't exist, simplifying the calculation of \( \text{Cov}(X_1, X_2) \) to just \( \sigma_W^2 \).

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