/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 33 Suppose a randomly chosen indivi... [FREE SOLUTION] | 91Ó°ÊÓ

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Suppose a randomly chosen individual's verbal score \(X\) and quantitative score \(Y\) on a nationally administered aptitude examination have a joint pdf $$ f(x, y)=\left\\{\begin{array}{cl} \frac{2}{5}(2 x+3 y) & 0 \leq x \leq 1,0 \leq y \leq 1 \\ 0 & \text { otherwise } \end{array}\right. $$ You are asked to provide a prediction \(t\) of the individual's total score \(X+Y\). The error of prediction is the mean squared error \(E\left[(X+Y-t)^{2}\right]\). What value of \(t\) minimizes the error of prediction?

Short Answer

Expert verified
The value of t that minimizes the error is the expected value of X+Y, E[X+Y].

Step by step solution

01

Understanding the Problem

We need to find a value of \( t \) that minimizes the error of prediction. The error of prediction is given by the mean squared error \( E\left[(X+Y-t)^2\right] \). To find this, we need to analyze the joint pdf \( f(x,y) = \frac{2}{5}(2x+3y) \) for \( 0 \leq x \leq 1 \) and \( 0 \leq y \leq 1 \).
02

Calculate Expected Value of Total Score

The expected value \( E[X+Y] \) can be calculated by integrating \( x+y \) over the range of \( x \) and \( y \) with respect to the joint pdf. That is, \[ E[X+Y] = \int_0^1 \int_0^1 (x + y) \frac{2}{5}(2x + 3y) \; dy \; dx. \]
03

Integrate with Respect to y

Perform the integration with respect to \( y \):\[ \int_0^1 (x+y) \frac{2}{5}(2x+3y) \; dy = \frac{2}{5}\int_0^1 (x+y)(2x+3y) \; dy. \] Expand \((x+y)(2x+3y)\) and integrate term by term.
04

Integrate with Respect to x

Now integrate the expression obtained in the previous step with respect to \( x \) over the range \( 0 \leq x \leq 1 \). Combine the results from the integration.
05

Short Answer Based on Result

The minimized value for prediction \( t \) is equal to \( E[X+Y] \). Since the expected value of the total score minimizes the mean squared error when predicting, the optimal \( t \) is \( E[X+Y] \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mean Squared Error
The Mean Squared Error (MSE) is an essential measure in statistics used to estimate the accuracy of a prediction. It calculates the average of the squares of the errors, where errors are the differences between predicted and actual values. In simpler terms, it tells us how far off a prediction is from the true values on average. This can be crucial when assessing the quality of a prediction model.

In the context of the exercise, MSE is used to evaluate how good a prediction of the total test score, represented by the variable \( t \), is. The objective is to find the value of \( t \) that minimizes the MSE, expressed mathematically as \( E\left[(X+Y-t)^2\right] \). By obtaining the value of \( t \) that makes this quantity as small as possible, we find the most accurate prediction for the sum of the verbal and quantitative scores. This approach helps minimize the overall prediction error.
  • MSE is a measure of prediction accuracy.
  • Lower MSE indicates better predictive performance.
  • The goal is to find \( t \) that minimizes MSE for accurate predictions.
Expected Value
The expected value is a key concept in probability and statistics that represents the average outcome you would expect if you could repeat an experiment indefinitely. It provides a single summary measure that can help you make informed predictions based on a probabilistic model.

In the exercise, we're tasked with calculating the expected value of the sum of scores, \( E[X+Y] \). This involves determining the average value of the total test score using the joint probability density function (pdf) provided: \( f(x, y)=\frac{2}{5}(2x+3y) \). This function gives us the combined probability landscape of verbal and quantitative scores.

By integrating over the ranges of both \( x \) and \( y \), we are able to compute the expected value. This calculation is important because it helps minimize the mean squared error when making predictions about the total score. By setting the prediction value \( t \) to \( E[X+Y] \), we achieve the most accurate prediction possible.
  • Expected Value provides a measure of central tendency in probability.
  • It is computed using integrals over the range of possible values, weighted by their probabilities.
  • In this case, it is used to minimize the prediction error for test scores.
Integration in Probability
Integration in probability is a technique used to find probabilities and expected values by summing their possible outcomes, weighted by likelihoods, over a continuous range. This is particularly necessary when dealing with continuous random variables represented by probability density functions (pdfs).

For the exercise, integration is required to calculate the expected value of \( X+Y \). We start by integrating with respect to one variable and then integrate the resulting expression with respect to the other. This process helps find out the average of sums of the random variables, weighted by their joint probabilities.

The integration of the joint pdf \( f(x, y)=\frac{2}{5}(2x+3y) \) over \( 0 \leq x \leq 1 \) and \( 0 \leq y \leq 1 \) helps in determining \( E[X+Y] \). The order of integration (first \( y \) then \( x \) or vice versa) can affect the complexity but not the outcome of the solution. With the completion of this integration, we find the expected value which directly determines the optimal prediction value \( t \).
  • Integration allows calculation of expectations in continuous distributions.
  • It values outcomes by their probability, over a range of occurrences.
  • Helps find expected values, crucial for minimizing prediction errors in the problem.

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