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Show that if \(Y=a X+b(a \neq 0)\), then \(\operatorname{Corr}(X, Y)=+1\) or \(-1\). Under what conditions will \(\rho=+1\) ?

Short Answer

Expert verified
\(\operatorname{Corr}(X, Y)=+1\) if \(a > 0\).

Step by step solution

01

Understand the Given Transformation

The transformation given is \(Y = aX + b\) where \(a eq 0\). This is a linear transformation of the variable \(X\), where \(a\) is a constant slope and \(b\) is a constant intercept. The correlation examines how \(X\) and \(Y\) relate to each other proportionally.
02

Calculate Covariance between X and Y

The covariance \( \text{Cov}(X, Y) \) is calculated as \( \text{Cov}(X, aX + b) = a \cdot \text{Cov}(X, X) + \text{Cov}(X, b) \). Since \(b\) is a constant, \(\text{Cov}(X, b) = 0\). Hence, \( \text{Cov}(X, Y) = a \cdot \text{Var}(X)\).
03

Calculate Standard Deviations of X and Y

The standard deviation of \(X\) is \( \sigma_X = \sqrt{\text{Var}(X)} \). The standard deviation of \(Y\) is \( \sigma_Y = \sqrt{\text{Var}(aX + b)} = \sqrt{a^2 \text{Var}(X)} = |a| \sigma_X \).
04

Write the Correlation Formula

The correlation \( \operatorname{Corr}(X, Y) \) is given by \( \rho = \frac{\text{Cov}(X, Y)}{\sigma_X \sigma_Y} \). Substitute the values from the previous steps to get \( \rho = \frac{a \cdot \text{Var}(X)}{\sigma_X \cdot |a| \sigma_X} = \frac{a}{|a|} = \pm 1\).
05

Determine the Condition for \(\rho = +1\)

For \(\rho\) to be +1, it is necessary that \(\frac{a}{|a|} = +1\). This happens when \(a\) is positive, thus \(a > 0\). Therefore, if \(a > 0\), \( \operatorname{Corr}(X, Y) = +1 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Linear Transformation
A linear transformation is a mathematical operation where a function maps one variable to another, maintaining its linear properties. In the context of our exercise, the transformation is expressed as \( Y = aX + b \), where \( a \) and \( b \) are constants, and \( a eq 0 \). This specific type of transformation implies that for each unit increase in \( X \), \( Y \) increases by \( a \) units if \( a > 0 \), or decreases if \( a < 0 \). Linear transformations are pivotal in various fields because they preserve the operations of vector addition and scalar multiplication. They help extend our understanding of functions by explaining how one set of data relates proportionately to another.
  • \( a \): Controls the slope or the steepness of the transformation.
  • \( b \): Adjusts the intercept, which is where the line crosses the y-axis.
If the relationship between \( X \) and \( Y \) is perfectly linear and either increasing or decreasing directly, this will result in complete correlation, as posited by the problem in the exercise.
Covariance
Covariance is a statistical measurement of the directional relationship between two random variables. The formula for covariance between \( X \) and \( Y \) gives us an indication of how the variables change together. The key equation in this context is \( \text{Cov}(X, Y) = a \cdot \text{Var}(X) \), deduced from the transformation \( Y = aX + b \). Covariance tells us the direction of the linear relationship - whether the variables tend to increase together (+covariance) or as one increases, the other tends to decrease (-covariance). However, it doesn't indicate the strength of the relationship. That’s where the correlation coefficient becomes essential.In our exercise:
  • \( \text{Cov}(X, b) = 0 \), since \( b \) is a constant.
  • \( \text{Cov}(X, Y) = a \cdot \text{Var}(X) \), where \( \text{Var}(X) \) is the variance of \( X \).
Covariance is foundational for computing the correlation coefficient as seen in later steps.
Standard Deviation
Standard deviation measures the amount of variation or dispersion in a set of values. It’s crucial for understanding the spread of data points around the mean. In the transformation presented in the exercise, calculate the standard deviations of \( X \) and \( Y \) as follows:- For \( X \), find \( \sigma_X = \sqrt{\text{Var}(X)} \).- For \( Y \), given our transformation \( Y = aX + b \), the standard deviation is expressed as \( \sigma_Y = |a| \sigma_X \). This arises because variance transforms with the square of any scaling factor in linear equations hence \( \sigma_Y = \sqrt{a^2 \text{Var}(X)} \).Standard deviation is an essential component as it normalizes the covariance, offering a more interpretable metric of data consistency. This normalization leads to the correlation coefficient, which is a standardized measure.
Correlation Coefficient
The correlation coefficient, denoted as \( \rho \), quantifies the degree to which two variables are related. It is bounded between -1 and +1. In our example, the exercise shows that \( \rho = \pm 1 \), meaning a perfect linear relationship between \( X \) and \( Y \).The formula used is:\[ \rho = \frac{\text{Cov}(X, Y)}{\sigma_X \sigma_Y} \]Inserting values from previous discussions, \( \rho = \frac{a}{|a|} \) simplifies to +1 or -1:
  • If \( a > 0 \), \( \rho = +1 \), indicating a perfect positive linear relationship.
  • If \( a < 0 \), \( \rho = -1 \), indicating a perfect negative linear relationship.
The correlation coefficient effectively encapsulates the strength and direction of the linear relationship. Thus, showcasing its power in statistical analysis, especially in predicting the extent to which two variables show a systematic pattern together.

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Most popular questions from this chapter

Manufacture of a certain component requires three different machining operations. Machining time for each operation has a normal distribution, and the three times are independent of one another. The mean values are 15,30 , and \(20 \mathrm{~min}\), respectively, and the standard deviations are 1,2 , and \(1.5 \mathrm{~min}\), respectively. What is the probability that it takes at most 1 hour of machining time to produce a randomly selected component?

Let \(X\) be the number of packages being mailed by a randomly selected customer at a certain shipping facility. Suppose the distribution of \(X\) is as follows: \begin{tabular}{l|rrrr} \(x\) & 1 & 2 & 3 & 4 \\ \hline\(p(x)\) & \(.4\) & \(.3\) & \(.2\) & \(.1\) \end{tabular} a. Consider a random sample of size \(n=2\) (two customers), and let \(\bar{X}\) be the sample mean number of packages shipped. Obtain the probability distribution of \(\bar{X}\). b. Refer to part (a) and calculate \(P(\bar{X} \leq 2.5)\). c. Again consider a random sample of size \(n=2\), but now focus on the statistic \(R=\) the sample range (difference between the largest and smallest values in the sample). Obtain the distribution of \(R\). [Hint: Calculate the value of \(R\) for each outcome and use the probabilities from part (a).] d. If a random sample of size \(n=4\) is selected, what is \(P(\bar{X} \leq 1.5)\) ? [Hint: You should not have to list all possible outcomes, only those for which \(\bar{x} \leq 1.5\).]

A stockroom currently has 30 components of a certain type, of which 8 were provided by supplier 1,10 by supplier 2 , and 12 by supplier 3 . Six of these are to be randomly selected for a particular assembly. Let \(X=\) the number of supplier l's components selected, \(Y=\) the number of supplier 2's components selected, and \(p(x, y)\) denote the joint pmf of \(X\) and \(Y\). a. What is \(p(3,2)\) ? [Hint: Each sample of size 6 is equally likely to be selected. Therefore, \(p(3,2)=\) (number of outcomes with \(X=3\) and \(Y=2) /\) (total number of outcomes). Now use the product rule for counting to obtain the numerator and denominator.] b. Using the logic of part (a), obtain \(p(x, y)\). (This can be thought of as a multivariate hypergeometric distribution-sampling without replacement from a finite population consisting of more than two categories.)

Each customer making a particular Internet purchase must pay with one of three types of credit cards (think Visa, MasterCard, AmEx). Let \(A_{i}(i=1,2,3)\) be the event that a type \(i\) credit card is used, with \(P\left(A_{1}\right)=.5\), \(P\left(A_{2}\right)=.3\), and \(P\left(A_{3}\right)=.2\). Suppose that the number of customers who make such a purchase on a given day is a Poisson rv with parameter \(\lambda\). Define rv's \(X_{1}, X_{2}, X_{3}\) by \(X_{i}=\) the number among the \(N\) customers who use a type \(i\) card \((i=1,2,3)\). Show that these three rv's are independent with Poisson distributions having parameters \(.5 \lambda, .3 \lambda\), and \(.2 \lambda\), respectively. [Hint: For non- negative integers \(x_{1}, x_{2}, x_{3}\), let \(n=x_{1}+x_{2}+x_{3}\). Then \(P\left(X_{1}=x_{1}\right.\), \(\left.X_{2}=x_{2}, X_{3}=x_{3}\right)=P\left(X_{1}=x_{1}, X_{2}=x_{2}, X_{3}=x_{3}, N=n\right)\) [why is this?]. Now condition on \(N=n\), in which case the three \(X i\) 's have a trinomial distribution (multinomial with three categories) with category probabilities \(.5, .3\), and .2.]

a. Use the rules of expected value to show that \(\operatorname{Cov}(a X+b, c Y+d)=a c \operatorname{Cov}(X, Y)\). b. Use part (a) along with the rules of variance and standard deviation to show that \(\operatorname{Corr}(a X+b\), \(c Y+d)=\operatorname{Corr}(X, Y)\) when \(a\) and \(c\) have the same sign. c. What happens if \(a\) and \(c\) have opposite signs?

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