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Determine the values of the following quantities

\(\begin{array}{l}{\rm{a}}{\rm{.}}{{\rm{x}}^{\rm{2}}}{\rm{,1,15}}\\{\rm{b}}{\rm{.}}{{\rm{X}}^{\rm{3}}}{\rm{,125}}\\{\rm{c}}{\rm{.}}{{\rm{X}}^{\rm{7}}}{\rm{01,25}}\\{\rm{d}}{\rm{.}}{{\rm{X}}^{\rm{2}}}{\rm{00525}}\\{\rm{e}}{\rm{.}}{{\rm{X}}^{\rm{7}}}{\rm{9925}}\\{\rm{f}}{\rm{.}}{{\rm{X}}^{\rm{7}}}{\rm{995,25}}\end{array}\)

Short Answer

Expert verified

The values are

\(\begin{aligned}{{\rm{a}}{\rm{.\;22}}{\rm{.307}}}\\{{\rm{b}}{\rm{.\;34}}{\rm{.381}}}\\{{\rm{c}}{\rm{.\;44}}{\rm{.313}}}\\{{\rm{d}}{\rm{. 46}}{\rm{.925}}}\\{{\rm{e}}{\rm{. 11}}{\rm{.524}}}\\{{\rm{f}}{\rm{. 10}}{\rm{.519}}}\\{\rm{\;}}\end{aligned}\)

Step by step solution

01

To Determine the values

The values of the quantities can be obtained from the appendix of the book. The \({\rm{\alpha or 1 - \alpha }}\)can be found in a column part and the degrees of freedom in a row part. Next to every value there is a picture with the area of a tail.

(a):

For \({{\rm{\chi }}_{{\rm{0}}{\rm{.1,15,}}}}{\rm{\alpha = 0}}{\rm{.1 and \nu = 15}}\)degrees of freedom, therefore, from the appendix of the book, Table A.7, the value is

\({{\rm{\chi }}_{{\rm{0}}{\rm{.1,15}}}}{\rm{ = 22}}{\rm{.307}}{\rm{.}}\)

(b):

For \({{\rm{\chi }}_{{\rm{0}}{\rm{.1,25}}}}{\rm{,\alpha = 0}}{\rm{.1 and \nu = 25}}\)degrees of freedom, therefore, from the appendix of the book, Table A.7, the value is \({{\rm{\chi }}_{{\rm{0}}{\rm{.1,25}}}}{\rm{ = 34}}{\rm{.381}}{\rm{.}}\)

(c):

For \({{\rm{\chi }}_{{\rm{0}}{\rm{.01,25}}}}{\rm{,\alpha = 0}}{\rm{.01 and \nu = 25}}\) degrees of freedom, therefore, from the appendix of, the value is \({{\rm{\chi }}_{{\rm{0}}{\rm{.01,25}}}}{\rm{ = 44}}{\rm{.313}}\)

02

To Determine the values

\({\rm{(d):}}\)

For \({{\rm{\chi }}_{{\rm{0}}{\rm{.005,25,}}}}{\rm{\alpha = 0}}{\rm{.01 and \nu = 25}}\)degrees of freedom, therefore, from the appendix of the book, Table A.7, the value is\({{\rm{\chi }}_{{\rm{0}}{\rm{.005,25}}}}{\rm{ = 46}}{\rm{.925}}{\rm{.}}\)

(e):

For \({{\rm{\chi }}_{{\rm{0}}{\rm{.99,25,}}}}{\rm{1 - \alpha = 0}}{\rm{.99 and \nu = 25}}\) degrees of freedom, therefore, from the appendix of the book,the value is \({{\rm{\chi }}_{{\rm{0}}{\rm{.99,25}}}}{\rm{ = 11}}{\rm{.523}}{\rm{.}}\)

(f):

For \({{\rm{\chi }}_{{\rm{0}}{\rm{.995,25r}}}}{\rm{,\alpha = 0}}{\rm{.995 and \nu = 25}}\) degrees of freedom, therefore, from the appendix of the book, the value is \({{\rm{\chi }}_{{\rm{0}}{\rm{.995,25}}}}{\rm{ = 10}}{\rm{.519}}{\rm{.}}\)

Hence

\(\begin{aligned}{{\rm{a}}{\rm{.\;22}}{\rm{.307}}}\\{{\rm{b}}{\rm{.\;34}}{\rm{.381}}}\\{{\rm{c}}{\rm{.\;44}}{\rm{.313}}}\\{{\rm{d}}{\rm{. 46}}{\rm{.925}}}\\{{\rm{e}}{\rm{. 11}}{\rm{.524}}}\\{{\rm{f}}{\rm{. 10}}{\rm{.519}}}\\{\rm{\;}}\end{aligned}\)

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Most popular questions from this chapter

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