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Each of the following is a confidence interval for \({\rm{\mu = }}\) true average (i.e., population mean) resonance frequency (Hz) for all tennis rackets of a certain type: \({\rm{(114}}{\rm{.4,115}}{\rm{.6)(114}}{\rm{.1,115}}{\rm{.9)}}\) a. What is the value of the sample mean resonance frequency? b. Both intervals were calculated from the same sample data. The confidence level for one of these intervals is \({\rm{90\% }}\) and for the other is \({\rm{99\% }}\). Which of the intervals has the \({\rm{90\% }}\) confidence level, and why?

Short Answer

Expert verified

(a) The value of sample mean resonance is \({\rm{115}}\).

(b) Interval \({\rm{(114}}{\rm{.4,115}}{\rm{.6)}}\) as narrower.

Step by step solution

01

Define frequency

The number of times a repeated event occurs per unit of time is known as frequency. It's also referred to as temporal frequency to distinguish it from spatial frequency, and ordinary frequency to distinguish it from angular frequency.

02

Explanation


(a) When a normal population is given,

\({\rm{100(1 - \alpha )\% confidence interval}}\)

the mean is calculated using,

\(\left( {{\rm{\bar x - }}{{\rm{z}}_{{\rm{\alpha /2}}}}{\rm{ \times }}\frac{{\rm{\sigma }}}{{\sqrt {\rm{n}} }}{\rm{,\bar x + }}{{\rm{z}}_{{\rm{\alpha /2}}}}{\rm{ \times }}\frac{{\rm{\sigma }}}{{\sqrt {\rm{n}} }}} \right)\)

when it is known what the value\({{\rm{\sigma }}^{\rm{2}}}\)is.

So, because sample mean is the middle of the provided interval,

\(\begin{array}{c}\left( {{\rm{\bar x + }}{{\rm{z}}_{{\rm{\alpha /2}}}}{\rm{ \times }}\frac{{\rm{\sigma }}}{{\sqrt {\rm{n}} }}{\rm{ + \bar x - }}{{\rm{z}}_{{\rm{\alpha /2}}}}{\rm{ \times }}\frac{{\rm{\sigma }}}{{\sqrt {\rm{n}} }}} \right){\rm{/2 = }}\frac{{{\rm{2\bar x}}}}{{\rm{2}}}\\{\rm{ = \bar x}}{\rm{.}}\end{array}\)

As a result, the sample mean,

\(\begin{array}{c}{\rm{\bar x = }}\frac{{{\rm{114}}{\rm{.4 + 115}}{\rm{.6}}}}{{\rm{2}}}\\{\rm{ = 115}}\\{\rm{ = }}\frac{{{\rm{114}}{\rm{.1 + 115}}{\rm{.9}}}}{{\rm{2}}}\end{array}\)

Therefore, the value is \({\rm{115}}\).

03

Explanation

(b) The \({\rm{90}}\) percent confidence level refers to the narrower confidence interval \({\rm{(114}}{\rm{.4,115}}{\rm{.6)}}\), because the broader the interval, the greater the probability (the higher confidence level).

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