/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q2E Refer to Exercise 1 and suppose ... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 16: Q2E (page 680)

Refer to Exercise 1 and suppose the ten most recent values of the quality statistic are .0493, .0485, .0490, .0503, .0492, .0486, .0495, .0494, .0493, and .0488. Construct the relevant portion of the corresponding control chart, and comment on its appearance.

Short Answer

Expert verified

There may be decreased in average value of the sample mean thickness.

Step by step solution

01

solving using graph:

All ten values are between UCL and LCL.

Notice that only value is above the central line. This might suggest that, there may be decreased in average value of the sample mean thickness.

02

final answer:

There may be decreased in average value of the sample mean thickness.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Subgroups of power supply units are selected once each hour from an assembly line, and the high-voltage output of each unit is determined.

a. Suppose the sum of the resulting sample ranges for\(30\)subgroups, each consisting of four units, is\(85.2\). Calculate control limits for an\(R\)chart.

b. Repeat part (a) if each subgroup consists of eight units and the sum is\(106.2\).

If a process variable is normally distributed, in the long run virtually all observed values should be between饾潄-3饾潏and饾潄+3饾潏, giving a process spread of 6饾潏.

a.With LSL and USL denoting the lower and upper specification limits, one commonly used process capability indexis Cp = (USL 鈥� LSL)/6饾潏. The value Cp= 1 indicates a process that is only marginally capable of meeting specifications. Ideally, Cp should exceed 1.33 (a 鈥渧ery good鈥� process). Calculate the value of Cp for each of the cork production processes described in the previous exercise, and comment.

b. The Cp index described in (a) does not take into account process location. A capability measure that does involve the process mean is Cpk = min {(饾潏USL -饾潄)/3饾潏, (饾潄鈥� LSL)/3饾潏} Calculate the value of Cpk for each of the cork production processes described in the previous exercise, and comment. (Note: In practice, m and s have to be estimated from process data; we show how to do this in Section 16.2)

c. How do Cp and Cpk compare, and when are they equal?

Some sources advocate a somewhat more restrictive type of doubling-sampling plan in which \({r_1} = {c_2} + 1\); that is, the lot is rejected if at either stage the (total) number of defectives is at least \({r_1}\) (see the book by Montgomery). Consider this type of sampling plan with \({n_1} = 50,{n_2} = 100,{c_1} = 1\), and \({r_1} = 4\). Calculate the probability of lot acceptance when \(p = .02,.05\), and .10.

An alternative to the \(p\) chart for the fraction defective is the np chart for number defective. This chart has \(UCL = n\bar p + 3\sqrt {n\bar p(1 - \bar p)} ,LCL = n\bar p - 3\sqrt {n\bar p(1 - \bar p)} \),

and the number of defectives from each sample is plotted on the chart. Construct such a chart for the data of Example 16.6. Will the use of an \(n p\) chart always give the same message as the use of a \(p\)chart (i.e., are the two charts equivalent)?

Containers of a certain treatment for septic tanks are supposed to contain \(16oz\) of liquid. A sample of five containers is selected from the production line once each hour, and the sample average content is determined. Consider the following results: \(15.992,16.051,16.066,15.912\), \(16.030,16.060,15.982,15.899,16.038,16.074,16.029\), \(15.935,16.032,15.960,16.055\). Using \(\Delta = .10\) and\(h = .20\), employ the computational form of the CUSUM procedure to investigate the behaviour of this process.
See all solutions

Recommended explanations on Math Textbooks

Applied Mathematics

Read Explanation

Mechanics Maths

Read Explanation

Logic and Functions

Read Explanation

Probability and Statistics

Read Explanation

Calculus

Read Explanation

Theoretical and Mathematical Physics

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.