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In any Ai independent of any other \({\rm{Aj}}\)? Answer using the multiplication property for independent events.

Short Answer

Expert verified

Events \({{\rm{A}}_1}\) and \({{\rm{A}}_{\rm{2}}}\) are independent

Events \({{\rm{A}}_1}\) and \({{\rm{A}}_{\rm{3}}}\) are independent

Events \({{\rm{A}}_{\rm{2}}}\) and \({{\rm{A}}_{\rm{3}}}\) are independent

Step by step solution

01

Introduction

Independence is a state in which a person, a nation, a country, or a state's people and population, or a portion of them, have self-government and, in most cases, sovereignty over their area. The status of a dependent territory is the polar opposite of independence.

02

Proofing independent events

Multiplication Property: Two events A and B are independent if and only if

\(P(A \cap B) = P(A) \cdot P(B)\)

As we are asked, we need to use the proposition given above. From exercise\({\rm{13}}\), we have

\(\begin{array}{l}P\left( {{A_1} \cap {A_2}} \right) = 0.11\\P\left( {{A_1} \cap {A_3}} \right) = 0.05\\P\left( {{A_2} \cap {A_3}} \right) = 0.07\end{array}\)

as well as the probabilities of event\({{\rm{A}}_{\rm{1}}}{\rm{,}}{{\rm{A}}_{\rm{2}}}\), and \({{\rm{A}}_{\rm{3}}}\)

\(\begin{array}{c}P\left( {{A_1}} \right) \cdot P\left( {{A_2}} \right) &=& 0.22 \cdot 0.25\\ &=& 0.055\\P\left( {{A_1}} \right) \cdot P\left( {{A_3}} \right) &=& 0.22 \cdot 0.28\\ &=& 0.0616\\P\left( {{A_2}} \right) \cdot P\left( {{A_3}} \right) &=& 0.25 \cdot 0.28\\ &=& 0.07\end{array}\)

03

Proofing independent events using rule

From the multiplication rule, the following is true

\(P\left( {{A_1} \cap {A_2}} \right) = 0.11 \ne 0.055 = P\left( {{A_1}} \right) \cdot P\left( {{A_2}} \right)\)

The following is holds

\(P\left( {{A_1} \cap {A_3}} \right) = 0.05 \ne 0.0616 = P\left( {{A_1}} \right) \cdot P\left( {{A_3}} \right)\)

Therefore, \({{\rm{A}}_{\rm{1}}}\)and \({{\rm{A}}_{\rm{3}}}\)are dependent.

The following is true

\(\begin{array}{c}P\left( {{A_2} \cap {A_3}} \right) &=& 0.07\\ &=& 0.07\\ &=& P\left( {{A_2}} \right) \cdot P\left( {{A_3}} \right)\end{array}\)

The following is true

Therefore, \({{\rm{A}}_1}\)and \({{\rm{A}}_{\rm{3}}}\)are independent.

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Most popular questions from this chapter

In five-card poker, a straight consists of five cards with adjacent denominations (e.g., \({\rm{9}}\)of clubs, \({\rm{10}}\)of hearts, jack of hearts, queen of spades, and king of clubs). Assuming that aces can be high or low, if you are dealt a five-card hand, what is the probability that it will be a straight with high card \({\rm{10}}\)? What is the probability that it will be a straight? What is the probability that it will be a straight flush (all cards in the same suit)?

The composer Beethoven wrote \({\rm{9}}\) symphonies, \({\rm{9}}\) piano concertos (music for piano and orchestra), and \({\rm{32}}\) piano sonatas (music for solo piano).

a. How many ways are there to play first a Beethoven symphony and then a Beethoven piano concerto?

b. The manager of a radio station decides that on each successive evening (\({\rm{7}}\) days per week), a Beethoven symphony will be played followed by a Beethoven piano concerto followed by a Beethoven piano sonata. For how many years could this policy be continued before exactly the same program would have to be repeated?

Return to the credit card scenario of Exercise, and let C be the event that the selected student has an American Express card. In addition to\(P\left( A \right) = 0.6\), \(P\left( B \right) = 0.4\), and\(P\left( {A \cap B} \right) = 0.3\), suppose that\(P\left( C \right) = 0.2\), \(P\left( {A \cap C} \right)\; = 0.15\), \(P\left( {B \cap C} \right) = 0.1\), and \(P\left( {A \cap B \cap C} \right) = 0.08\)

a. What is the probability that the selected student has at least one of the three types of cards?

b. What is the probability that the selected student has both a Visa card and a MasterCard but not an American Express card?

c. Calculate and interpret \(P\left( {B|A} \right)\)and also \(P\left( {A|B} \right)\)

d. If we learn that the selected student has an American Express card, what is the probability that she or he also has both a Visa card and a MasterCard?

e. Given that the selected student has an American Express card, what is the probability that she or he has at least one of the other two types of cards?

Let Adenote the event that the next request for assistance from a statistical software consultant relates to the SPSS package, and let Bbe the event that the next request is for help with SAS. Suppose that P(A)=.30and P(B)=.50.

a. Why is it not the case that P(A)+P(B)=1?

b. Calculate P(A鈥).

c. Calculate P(A\( \cup \)B).

d. Calculate P(A鈥橽( \cap \)B鈥).

Suppose identical tags are placed on both the left ear and the right ear of a fox. The fox is then let loose for a period of time. Consider the two events \({{\rm{C}}_{\rm{1}}}{\rm{ = }}\){left ear tag is lost} and \({{\rm{C}}_{\rm{2}}}{\rm{ = }}\){right ear tag is lost}. Let 颅 \({\rm{\pi = P(}}{{\rm{C}}_{\rm{1}}}{\rm{) = P(}}{{\rm{C}}_{\rm{2}}}{\rm{)}}\),and assume \({{\rm{C}}_{\rm{1}}}\)and \({{\rm{C}}_{\rm{2}}}\) are independent events. Derive an expression (involving p) for the probability that exactly one tag is lost, given that at most one is lost (鈥淓ar Tag Loss in Red Foxes,鈥 J. Wildlife Mgmt., \({\rm{1976: 164--167)}}{\rm{.}}\) (Hint: Draw a tree diagram in which the two initial branches refer to whether the left ear tag was lost.)

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