/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q72E In any Ai independent of any oth... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

In any Ai independent of any other \({\rm{Aj}}\)? Answer using the multiplication property for independent events.

Short Answer

Expert verified

Events \({{\rm{A}}_1}\) and \({{\rm{A}}_{\rm{2}}}\) are independent

Events \({{\rm{A}}_1}\) and \({{\rm{A}}_{\rm{3}}}\) are independent

Events \({{\rm{A}}_{\rm{2}}}\) and \({{\rm{A}}_{\rm{3}}}\) are independent

Step by step solution

01

Introduction

Independence is a state in which a person, a nation, a country, or a state's people and population, or a portion of them, have self-government and, in most cases, sovereignty over their area. The status of a dependent territory is the polar opposite of independence.

02

Proofing independent events

Multiplication Property: Two events A and B are independent if and only if

\(P(A \cap B) = P(A) \cdot P(B)\)

As we are asked, we need to use the proposition given above. From exercise\({\rm{13}}\), we have

\(\begin{array}{l}P\left( {{A_1} \cap {A_2}} \right) = 0.11\\P\left( {{A_1} \cap {A_3}} \right) = 0.05\\P\left( {{A_2} \cap {A_3}} \right) = 0.07\end{array}\)

as well as the probabilities of event\({{\rm{A}}_{\rm{1}}}{\rm{,}}{{\rm{A}}_{\rm{2}}}\), and \({{\rm{A}}_{\rm{3}}}\)

\(\begin{array}{c}P\left( {{A_1}} \right) \cdot P\left( {{A_2}} \right) &=& 0.22 \cdot 0.25\\ &=& 0.055\\P\left( {{A_1}} \right) \cdot P\left( {{A_3}} \right) &=& 0.22 \cdot 0.28\\ &=& 0.0616\\P\left( {{A_2}} \right) \cdot P\left( {{A_3}} \right) &=& 0.25 \cdot 0.28\\ &=& 0.07\end{array}\)

03

Proofing independent events using rule

From the multiplication rule, the following is true

\(P\left( {{A_1} \cap {A_2}} \right) = 0.11 \ne 0.055 = P\left( {{A_1}} \right) \cdot P\left( {{A_2}} \right)\)

The following is holds

\(P\left( {{A_1} \cap {A_3}} \right) = 0.05 \ne 0.0616 = P\left( {{A_1}} \right) \cdot P\left( {{A_3}} \right)\)

Therefore, \({{\rm{A}}_{\rm{1}}}\)and \({{\rm{A}}_{\rm{3}}}\)are dependent.

The following is true

\(\begin{array}{c}P\left( {{A_2} \cap {A_3}} \right) &=& 0.07\\ &=& 0.07\\ &=& P\left( {{A_2}} \right) \cdot P\left( {{A_3}} \right)\end{array}\)

The following is true

Therefore, \({{\rm{A}}_1}\)and \({{\rm{A}}_{\rm{3}}}\)are independent.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Consider the system of components connected as in the accompanying picture. Components \({\rm{1}}\) and \({\rm{2}}\) are connected in parallel, so that subsystem works iff either 1 or 2 works; since \({\rm{3}}\)and\({\rm{4}}\) are connected in series, that subsystem works iff both\({\rm{3}}\)and\({\rm{4}}\)work. If components work independently of one another and P(component i works) \({\rm{ = }}{\rm{.9}}\)for \({\rm{i = }}{\rm{.1,2}}\)and \({\rm{ = }}{\rm{.8}}\)for \({\rm{i = 3,4}}\),calculate P(system works).

A certain system can experience three different types of defects. Let \({{\rm{A}}_{\rm{1}}}\)\({\rm{(i = 1,2,3)}}\)denote the event that the system has a defect of type Suppose that

\(\begin{aligned}P\left( {{A_1}} \right) &= .12\;\;\;P\left( {{A_2}} \right) = .07\;\;\;P\left( {{A_3}}\right) = .05 \hfill \\P\left( {{A_1}E {A_2}} \right) = .13\;\;\;P\left( {{A_1}E {A_3}}\right) &= .14 \hfill \\P\left( {{A_2}E {A_2}} \right) = .10\;\;\;P\left( {{A_1}{C}{A_3}{C}{A_7}} \right) &= .01 \hfill \\\end{aligned} \)

a. What is the probability that the system does not have a type 1 defect?

b. What is the probability that the system has both type 1 and type 2 defects?

c. What is the probability that the system has both type 1 and type 2 defects but not a type 3 defect?

d. What is the probability that the system has at most two of these defects?

One of the assumptions underlying the theory of control charting is that successive plotted points are independent of one another. Each plotted point can signal either that a manufacturing process is operating correctly or that there is some sort of malfunction.

According to July \(31, 2013\), posting on cnn.com subsequent to the death of a child who bit into a peanut, a \(2010\) study in the journal Pediatrics found that \(8\% \)of children younger than eighteen in the United States have at least one food allergy. Among those with food allergies, about \(39\% \)had a history of severe reaction.

a. If a child younger than eighteen is randomly selected, what is the probability that he or she has at least one food allergy and a history of severe reaction?

b. It was also reported that \(30\% \) of those with an allergy in fact are allergic to multiple foods. If a child younger than eighteen is randomly selected, what is the probability that he or she is allergic to multiple foods?

Consider purchasing a system of audio components consisting of a receiver, a pair of speakers, and a \({\rm{CD}}\) player. Let \({{\rm{A}}_{\rm{1}}}\) be the event that the receiver functions properly throughout the warranty period, \({{\rm{A}}_{\rm{2}}}\) be the event that the speakers function properly throughout the warranty period, and \({{\rm{A}}_{\rm{3}}}\) be the event that the \({\rm{CD}}\) player functions properly throughout the warranty period. Suppose that these events are (mutually) independent with \({\rm{P}}\left( {{{\rm{A}}_{\rm{1}}}} \right){\rm{ = }}{\rm{.95}}\), \({\rm{P}}\left( {{{\rm{A}}_{\rm{2}}}} \right){\rm{ = }}{\rm{.98}}\), and \({\rm{P}}\left( {{{\rm{A}}_{\rm{3}}}} \right){\rm{ = }}{\rm{.80}}\).

a. What is the probability that all three components function properly throughout the warranty period?

b. What is the probability that at least one component needs service during the warranty period?

c. What is the probability that all three components need service during the warranty period?

d. What is the probability that only the receiver needs service during the warranty period?

e. What is the probability that exactly one of the three components needs service during the warranty period?

f. What is the probability that all three components function properly throughout the warranty period but that at least one fails within a month after the warranty expires?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.