Chapter 13: Q41E (page 589)
Use a CAS to graph \({J_{3/2}}(x),{J_{ - 3/2}}(x),{J_{5/2}}(x),\) and \({J_{ - 5/2}}(x)\).
Short Answer
The graph has been plotted.
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Chapter 13: Q41E (page 589)
Use a CAS to graph \({J_{3/2}}(x),{J_{ - 3/2}}(x),{J_{5/2}}(x),\) and \({J_{ - 5/2}}(x)\).
The graph has been plotted.
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In Problems \(23 - 26\) first use \((20)\) to express the general solution of the given differential equation in terms of Bessel functions. Then use \((26)\) and \((27)\) to express the general solution in terms of elementary functions.
\(4{x^2}y'' - 4xy' + \left( {16{x^2} + 3} \right)y = 0\)
In Problems 29 and 30 use (22) or (23) to obtain the given result.
\({J_0}(x) = {J_{ - 1}}(x) = {J_1}(x)\)
(a) Proceed as in Example \(6\) to show that \(xJ_v^'(x) = - v{J_v}(x) + x{J_{v - 1}}(x)\). (Hint: Write \(2n + v = 2(n + v) - v\).) (b) Use the result in part (a) to derive \((23)\).
Use the change of variables \(s = \frac{2}{\alpha }\sqrt {\frac{k}{m}} {e^{ - \alpha t/2}}\) to show that the differential equation of the aging spring \(mx'' + k{e^{ - \alpha t}}x = 0\),\(\alpha > 0\) becomes \({s^2}\frac{{{d^2}x}}{{d{s^2}}} + s\frac{{dx}}{{ds}} + {s^2}x = 0\).
In Problems \(13 - 20\) use \((20)\) to find the general solution of the given differential equation on \((0,\infty )\).
\(9{x^2}y'' + 9xy' + \left( {{x^6} - 36} \right)y = 0\)
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