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In Problems \(13 - 20\) use \((20)\) to find the general solution of the given differential equation on \((0,\infty )\).

\(9{x^2}y'' + 9xy' + \left( {{x^6} - 36} \right)y = 0\)

Short Answer

Expert verified

The general solutions of the given differential equation are \(y = {C_1}{J_{2/3}}\left( {\frac{1}{9}{x^3}} \right) + {C_2}{J_{ - 2/3}}\left( {\frac{1}{9}{x^3}} \right)\) and \(y = {C_1}{J_{2/3}}\left( {\frac{1}{9}{x^3}} \right) + {C_2}{Y_{2/3}}\left( {\frac{1}{9}{x^3}} \right)\).

Step by step solution

01

Define Bessel’s equation.

Let the Bessel equation be \({x^2}y'' + xy' + \left( {{x^2} - {n^2}} \right)y = 0\). This equation has two linearly independent solutions for a fixed value of \(n\). A Bessel equation of the first kind, indicated by \({J_n}(x)\), is one of these solutions that may be derived using Frobinous approach.

\(\begin{array}{l}{y_1} = {x^a}{J_p}\left( {b{x^c}} \right)\\{y_2} = {x^a}{J_{ - p}}\left( {b{x^c}} \right)\end{array}\)

At \(x = 0\), this solution is regular. The second solution, which is singular at \(x = 0\), is represented by \({Y_n}(x)\) and is called a Bessel function of the second kind.

\({y_3} = {x^a}\left( {\frac{{cosp\pi {J_p}\left( {b{x^c}} \right) - {J_{ - p}}\left( {b{x^c}} \right)}}{{sinp\pi }}} \right)\)

02

Determine the general form of the Bessel’s equation.

Let the given differential equation be \(9{x^2}y'' + 9xy' + \left( {{x^6} - 36} \right)y = 0\), that has a singular point at \(x = 0\).

The equation becomes in the following form:

\(y'' + \frac{{1 - 2a}}{x}y' + \left( {{b^2}{c^2}{x^{2c - 2}} + \frac{{{a^2} - {p^2}{c^2}}}{{{x^2}}}} \right)y = 0\)… (1)

That yields,

\(\frac{{9{x^2}}}{{9{x^2}}}y'' + \frac{{9x}}{{9{x^2}}}y' + \frac{{{x^6} - 36}}{{9{x^2}}}y = 0\)

\(y'' + \frac{1}{x}y' + \left( {\frac{1}{9}{x^4} - \frac{4}{{{x^2}}}} \right)y = 0\) … (2)

03

Find the value of constants.

Compare the equations (1) and (2).

Solve for \(a\):

\(\begin{array}{c}1 - 2a = 1\\a = 0\end{array}\)

Solve for \(c\):

\(\begin{array}{c}2c - 2 = 4\\c = 3\end{array}\)

Solve for \(b\):

\(\begin{array}{c}{b^2}{c^2} = \frac{1}{9}\\b = \quad \frac{1}{9}\end{array}\)

Solve for \(p\):

\(\begin{array}{c}{a^2} - {p^2}{c^2} = - 4\\{p_1} = \frac{2}{3},{p_2} = \frac{{ - 2}}{3}\end{array}\)

04

Obtain the general solution.

There are two series which are linearly independent.

\(\begin{array}{c}{y_1} = {x^0}{J_{2/3}}\left( {\frac{1}{9}{x^3}} \right)\\ = {J_{2/3}}\left( {\frac{1}{9}{x^3}} \right)\\{y_2} = {J_{ - 2/3}}\left( {\frac{1}{9}{x^3}} \right)\end{array}\)

The general solution by using superposition principle is,

\(y = {C_1}{J_{2/3}}\left( {\frac{1}{9}{x^3}} \right) + {C_2}{J_{ - 2/3}}\left( {\frac{1}{9}{x^3}} \right)\)

There is another general solution obtained from the Bessel’s equation of second order. (i.e.) \(y = {C_1}{J_{2/3}}\left( {\frac{1}{9}{x^3}} \right) + {C_2}{Y_{2/3}}\left( {\frac{1}{9}{x^3}} \right)\).

Hence, the general solutions are \(y = {C_1}{J_{2/3}}\left( {\frac{1}{9}{x^3}} \right) + {C_2}{J_{ - 2/3}}\left( {\frac{1}{9}{x^3}} \right)\) and \(y = {C_1}{J_{2/3}}\left( {\frac{1}{9}{x^3}} \right) + {C_2}{Y_{2/3}}\left( {\frac{1}{9}{x^3}} \right)\).

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Most popular questions from this chapter

Show that \(y = {x^{1/2}}w\left( {\frac{2}{3}\alpha {x^{3/2}}} \right)\) is a solution of the given form of Airy’s differential equation whenever w is a solution of the indicated Bessel’s equation. (Hint: After differentiating, substituting, and simplifying, then let \(t = \frac{2}{3}\alpha {x^{3/2}}\))

(a) \(y'' + {\alpha ^2}xy = 0,x > 0;{t^2}w'' + tw' + \left( {{t^2} - \frac{1}{9}w} \right) = 0,t > 0\)

(b) \(y'' - {\alpha ^2}xy = 0,x > 0;{t^2}w'' + tw' - \left( {{t^2} - \frac{1}{9}w} \right) = 0,t > 0\)

(a) Use the second formula in (30) and Problem 32 to find the spherical Bessel functions \({y_1}(x)\) and \({y_2}(x)\).

(b) Use a graphing utility to plot the graphs of \({y_1}(x)\) and \({y_2}(x)\) in the same coordinate plane.

(a) Use (20) to show that the general solution of the differential equation \(xy'' + \lambda y = 0\) on the interval \((0,\infty )\) is \(y = {c_1}\sqrt x {J_1}\left( {2\sqrt {\lambda x} } \right) + {c_2}\sqrt x {Y_1}\left( {2\sqrt {\lambda x} } \right)\).

(b) Verify by direct substitution that \(y = \sqrt x {J_1}\left( {2\sqrt {\lambda x} } \right)\) is a particular solution of the DE in the case \(\lambda = 1\).

In Problems \(23 - 26\) first use \((20)\) to express the general solution of the given differential equation in terms of Bessel functions. Then use \((26)\) and \((27)\) to express the general solution in terms of elementary functions.

\({x^2}y'' + 4xy' + \left( {{x^2} + 2} \right)y = 0\)

Use the result in parts (a) and (b) of Problem 36 to express the general solution on \((0,\infty )\) of each of the two forms of Airy’s equation in terms of Bessel functions.

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