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A surveyor wishes to lay out a square region with each side having length\({\rm{L}}\). However, because of a measurement error, he instead lays out a rectangle in which the north-south sides both have length \({\rm{X}}\) and the east-west sides both have length\({\rm{Y}}\). Suppose that \({\rm{X}}\) and \({\rm{Y}}\) are independent and that each is uniformly distributed on the interval \({\rm{(L - A,L + A)}}\) (where \({\rm{0 < A < L}}\) ). What is the expected area of the resulting rectangle?

Short Answer

Expert verified

The expected area of the resulting rectangle is \({\rm{E(XY) = }}{{\rm{L}}^{\rm{2}}}{\rm{.}}\)

Step by step solution

01

Definition

Probability simply refers to the likelihood of something occurring. We may talk about the probabilities of particular outcomes—how likely they are—when we're unclear about the result of an event. Statistics is the study of occurrences guided by probability.

02

Determining the sample size

We are given a square region with a length of a side\({\rm{L}}\). However, a surveyor lands a rectangle. We have two sides with length \({\rm{X}}\) and two with length\({\rm{Y}}\).

Length of north-south sides is somewhere in interval\({\rm{(L - A,L + A)}}\), the same for east-west sides. This means that the length can be any number between \({\rm{L - A}}\) and\({\rm{L + A}}\). Because the given random variables are uniformly distributed on interval\({\rm{(L - A,L + A)}}\), the expected values are the midpoint - which is

\(\frac{{{\rm{L - A + L + A}}}}{{\rm{2}}}{\rm{ = L}}{\rm{.}}\)

An area of a rectangle is measured as \({\rm{a \times b}}\). In our case it is\({\rm{X \times Y}}\). Therefore, we need expectation of random variable \({\rm{X \times Y}}\), which is

\({\rm{E(XY)}}\mathop {\rm{ = }}\limits^{{\rm{(1)}}} {\rm{E(X)E(Y) = L \times L = }}{{\rm{L}}^{\rm{2}}}\)

(1): for two independent random variables \({\rm{E(XY) = E(X)E(Y)}}\).

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