/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q24E Six individuals, including \({\r... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Six individuals, including \({\rm{A}}\) and \({\rm{B}}\), take seats around a circular table in a completely random fashion. Suppose the seats are numbered\({\rm{1, \ldots ,6}}\). Let \({\rm{X = }}\) A's seat number and \({\rm{Y = B}}\) 's seat number. If A sends a written message around the table to \({\rm{B}}\) in the direction in which they are closest, how many individuals (including A and B) would you expect to handle the message?

Short Answer

Expert verified

The solution is \({\rm{E(g(X,Y)) = 2}}{\rm{.8}}\).

Step by step solution

01

Definition

Probability simply refers to the likelihood of something occurring. We may talk about the probabilities of particular outcomes—how likely they are—when we're unclear about the result of an event. Statistics is the study of occurrences guided by probability.

02

Determining the sample size

The

Expected Value

(mean value) of a random variable\({\rm{g(X,Y)}}\), where \({\rm{g( \times )}}\) is a function, denoted as \({\rm{E(g(X,Y))}}\)is given by

\({\rm{E(g(X,Y)) = }}\left\{ {\begin{aligned}{*{20}{l}}{\sum\limits_{\rm{x}} {\sum\limits_{\rm{y}} {\rm{g}} } {\rm{(x,y) \times p(x,y)}}}&{{\rm{,X and Y discrete }}}\\{\int_{{\rm{ - ¥}}}^{\rm{¥}} {\int_{{\rm{ - ¥}}}^{\rm{¥}} {\rm{g}} } {\rm{(x,y) \times f(x,y)dxdy}}}&{{\rm{,X and Y continuous}}{\rm{. }}}\end{aligned}} \right.\)

where \({\rm{p(x,y)}}\) is pmf and \({\rm{f(x,y)}}\) pdf.

We want to use this. In order to do that, we need to determine \({\rm{g(X,Y)}}\)which would be the number of individuals (including A and B) who handle the message.

We first need to notice that individuals \({\rm{A}}\) and \({\rm{B}}\)cannot sit on the same spot. The minimum number of individuals who can handle the message is two (only A and B), and that is if they sit one to another. The maximum number of people who can handle the message is \({\rm{4}}\) (if there are two people sitting from the left and right of \({\rm{A}}\) and \({\rm{B}}\) - they sit across).

The sits are numbered, \({\rm{X}}\)represent A's seat number, and \({\rm{Y}}\) represents B's seat number, therefore, \({\rm{(2,1)}}\)would mean that person A sits on seat\({\rm{2}}\), and person B sits on seat\({\rm{1}}\), and \({\rm{g(2,1)}}\) would be \({\rm{2}}\) , because the only two individuals who handles the message are \({\rm{A}}\) and\({\rm{B}}\). We will do the same thing and represent it in a table.

To compute the expectation, we need\({\rm{p(x,y)}}\). There are

\({\rm{6 \times 5 = 30}}\)

total number of ways that \({\rm{A}}\) and \({\rm{B}}\) can sit, therefore

\({\rm{p(x,y) = }}\frac{{\rm{1}}}{{{\rm{30}}}}{\rm{.}}\)

The following is true

\(\begin{aligned}{\rm{E(g(X,Y)) = }}\sum\limits_{\rm{x}} {\sum\limits_{\rm{y}} {\rm{g}} } {\rm{(x,y) \times p(x,y)}}\\{\rm{ = }}\frac{{\rm{1}}}{{{\rm{30}}}}{\rm{ \times }}\sum\limits_{\rm{x}} {\sum\limits_{\rm{y}} {\rm{g}} } {\rm{(x,y)}}\\{\rm{ = }}\frac{{\rm{1}}}{{{\rm{30}}}}{\rm{ \times 84}}\\{\rm{ = 2}}{\rm{.8}}\end{aligned}\)

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The joint pdf of pressures for right and left front tires.

a. Determine the conditional pdf of \({\rm{Y}}\) given that \({\rm{X = x}}\) and the conditional pdf of \({\rm{X}}\) given that \({\rm{Y = y}}\).

b. If the pressure in the right tire is found to be \({\rm{22}}\) psi, what is the probability that the left tire has a pressure of at least \({\rm{25}}\) psi? Compare this to.

c. If the pressure in the right tire is found to be \({\rm{22}}\) psi, what is the expected pressure in the left tire, and what is the standard deviation of pressure in this tire?

A student has a class that is supposed to end at\({\rm{9:00 A}}{\rm{.M}}\). and another that is supposed to begin at \({\rm{9:10 A}}{\rm{.M}}\).

Suppose the actual ending time of the \({\rm{9:00 A}}{\rm{.M}}\). class is a normally distributed \({\rm{rv}}\) \({{\rm{X}}_{\rm{1}}}\)with mean \({\rm{9:02 A}}{\rm{.M}}\)and standard deviation \({\rm{1}}{\rm{.5\;min}}\)and that the starting time of the next class is also a normally distributed \({\rm{rv}}\) \({{\rm{X}}_{\rm{2}}}\)with mean \({\rm{9:10}}\)and standard deviation \({\rm{1\;min}}{\rm{.}}\)Suppose also that the time necessary to get from one classroom to the other is a normally distributed \({\rm{rv}}\) \({{\rm{X}}_{\rm{3}}}\)with mean \({\rm{6\;min}}\) and standard deviation\({\rm{1\;min}}\). What is the probability that the student makes it to the second class before the lecture starts? (Assume independence of\({{\rm{X}}_{\rm{1}}}{\rm{,}}{{\rm{X}}_{\rm{2}}}\), and\({{\rm{X}}_{\rm{3}}}\), which is reasonable if the student pays no attention to the finishing time of the first class.)

Suppose that when the pH of a certain chemical compound is\(5.00\), the pH measured by a randomly selected beginning chemistry student is a random variable with a mean of\(5.00\)and a standard deviation .2. A large batch of the compound is subdivided and a sample is given to each student in a morning lab and each student in an afternoon lab. Let\(X = \)the average pH as determined by the morning students and\(Y = \)the average pH as determined by the afternoon students.

a. If pH is a normal variable and there are\(25\)students in each lab, compute\(P\left( { - .1 \le X - Y \le - .1} \right)\)

b. If there are\(36\)students in each lab, but pH determinations are not assumed normal, calculate (approximately)\(P\left( { - .1 \le X - Y \le - .1} \right)\).

Three different roads feed into a particular freeway entrance. Suppose that during a fixed time period, the number of cars coming from each road onto the freeway is a random variable, with expected value and standard deviation as given in the table.

a. What is the expected total number of cars entering the freeway at this point during the period? (Hint: Let \({\rm{Xi = }}\)the number from road\({\rm{i}}\).)

b. What is the variance of the total number of entering cars? Have you made any assumptions about the relationship between the numbers of cars on the different roads?

c. With \({\rm{Xi}}\) denoting the number of cars entering from road\({\rm{i}}\)during the period, suppose that \({\rm{cov}}\left( {{{\rm{X}}_{\rm{1}}}{\rm{,}}{{\rm{X}}_{\rm{2}}}} \right){\rm{ = 80\; and\; cov}}\left( {{{\rm{X}}_{\rm{1}}}{\rm{,}}{{\rm{X}}_{\rm{3}}}} \right){\rm{ = 90\; and\; cov}}\left( {{{\rm{X}}_{\rm{2}}}{\rm{,}}{{\rm{X}}_{\rm{3}}}} \right){\rm{ = 100}}\) (so that the three streams of traffic are not independent). Compute the expected total number of entering cars and the standard deviation of the total.

Let \({\rm{X}}\)and \({\rm{Y}}\)be independent standard normal random variables, and define a new rv by \({\rm{U = }}{\rm{.6X + }}{\rm{.8Y}}\).

a. \({\rm{Determine\;Corr(X,U)}}\)

b. How would you alter \({\rm{U}}\)to obtain \({\rm{Corr(X,U) = \rho }}\)for a specified value of \({\rm{\rho ?}}\)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.