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An instructor has given a short quiz consisting of two parts. For a randomly selected student, let \({\rm{X = }}\) the number of points earned on the first part and \({\rm{Y = }}\) the number of points earned on the second part. Suppose that the joint pmf of \({\rm{X}}\) and \({\rm{Y}}\) is given in the accompanying table.

a. If the score recorded in the grade book is the total number of points earned on the two parts, what is the expected recorded score\({\rm{E(X + Y)}}\)?

b. If the maximum of the two scores is recorded, what is the expected recorded score?

Short Answer

Expert verified

a. The expected recorded score is \[{\rm{E(X + Y) = 14}}{\rm{.1}}\].

b. The expected recorded score is \[{\rm{E[max(X,Y)] = 9}}{\rm{.6}}\].

Step by step solution

01

Definition

Probability simply refers to the likelihood of something occurring. We may talk about the probabilities of particular outcomes—how likely they are—when we're unclear about the result of an event. Statistics is the study of occurrences guided by probability.

02

Determining the expected recorded score \({\rm{E(X + Y)}}\)

We are given joint pmf of \({\rm{X}}\) and\({\rm{Y}}\).

(a):

Expected Value

(Mean value) of a random variable\({\rm{g(X,Y)}}\), where \({\rm{g( \times )}}\) is a function, denoted as \({\rm{E(g(X,Y))}}\) is given by \({\rm{E(g(X,Y)) = }}\left\{ {\begin{aligned}{*{20}{l}}{\sum\limits_{\rm{x}} {\sum\limits_{\rm{y}} {\rm{g}} } {\rm{(x,y) \times p(x,y)}}}&{{\rm{,X and Y discrete, }}}\\{\int_{{\rm{ - ¥}}}^{\rm{¥}} {\int_{{\rm{ - ¥}}}^{\rm{¥}} {\rm{g}} } {\rm{(x,y) \times f(x,y)dxdy}}}&{{\rm{,X and Y continuous}}{\rm{. }}}\end{aligned}} \right.\)

where \({\rm{p(x,y)}}\) is pmf and \({\rm{f}}\left( {{\rm{x, y}}} \right)\) pdf.

In our case, \({\rm{g(X,Y) = X + Y}}\), and the random variables are discrete, therefore the following is true

\(\begin{aligned}{\rm{E(X + Y) = }}\sum\limits_{\rm{x}} {\sum\limits_{\rm{y}} {\rm{g}} } {\rm{(x,y) \times p(x,y)}}\\{\rm{ = (0 + 0) \times 0}}{\rm{.02 + (0 + 5) \times 0}}{\rm{.06 + \ldots + (10 + 10) \times 0}}{\rm{.14 + (10 + 15) \times 0}}{\rm{.01}}\\{\rm{ = 14}}{\rm{.1}}\end{aligned}\)

03

Determining the expected recorded score

(b):

We are interested in expectation of random variable\({\rm{g(X,Y) = max(X,Y)}}\). Therefore,

\(\begin{aligned}{\rm{E(max(X,Y)) = }}\sum\limits_{\rm{x}} {\sum\limits_{\rm{y}} {\rm{g}} } {\rm{(x,y) \times p(x,y)}}\\{\rm{ = max(0,0) \times 0}}{\rm{.02 + max(0,5) \times 0}}{\rm{.06 + \ldots + max(10,10) \times 0}}{\rm{.14 + max(10,15) \times 0}}{\rm{.01}}\\{\rm{ = 0 \times 0}}{\rm{.02 + 5 \times 0}}{\rm{.06 + \ldots + \ldots 10 \times 0}}{\rm{.14 + 15 \times 0}}{\rm{.01}}\\{\rm{ = 9}}{\rm{.6}}\end{aligned}\)

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